我经常用这个…

原始代码:

if (guid != Guid.Empty) return guid;
else return Guid.NewGuid();

新代码:

return guid.NewGuidIfEmpty();

扩展方法:

public static Guid NewGuidIfEmpty(this Guid uuid)
{
    return (uuid != Guid.Empty ? uuid : Guid.NewGuid());
}

与时间跨度相关的扩展，如:

public static TimeSpan Seconds(this int seconds)
{
  return TimeSpan.FromSeconds(seconds);
}

public static TimeSpan Minutes(this int minutes)
{
  return TimeSpan.FromMinutes(minutes);
}

允许使用:

1.Seconds()
20.Minutes()

像这样的锁定扩展:

public static IDisposable GetReadLock(this ReaderWriterLockSlim slimLock)
{
  slimLock.EnterReadLock();
  return new DisposableAction(slimLock.ExitReadLock);
}

public static IDisposable GetWriteLock(this ReaderWriterLockSlim slimLock)
{
  slimLock.EnterWriteLock();
  return new DisposableAction(slimLock.ExitWriteLock);
}

public static IDisposable GetUpgradeableReadLock(this ReaderWriterLockSlim slimLock)
{
  slimLock.EnterUpgradeableReadLock();
  return new DisposableAction(slimLock.ExitUpgradeableReadLock);
}

允许使用像这样的锁:

using (lock.GetUpgradeableReadLock())
{
  // try read
  using (lock.GetWriteLock())
  {
    //do write
  }
}

还有许多来自Lokad共享图书馆的其他书籍

public static class EnumerableExtensions
{
    [Pure]
    public static U MapReduce<T, U>(this IEnumerable<T> enumerable, Func<T, U> map, Func<U, U, U> reduce)
    {
        CodeContract.RequiresAlways(enumerable != null);
        CodeContract.RequiresAlways(enumerable.Skip(1).Any());
        CodeContract.RequiresAlways(map != null);
        CodeContract.RequiresAlways(reduce != null);
        return enumerable.AsParallel().Select(map).Aggregate(reduce);
    }
    [Pure]
    public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
    {
        CodeContract.RequiresAlways(list != null);
        CodeContract.RequiresAlways(list.Count >= 2);
        CodeContract.RequiresAlways(map != null);
        CodeContract.RequiresAlways(reduce != null);
        U result = map(list[0]);
        for (int i = 1; i < list.Count; i++)
        {
            result = reduce(result,map(list[i]));
        }
        return result;
    }

    //Parallel version; creates garbage
    [Pure]
    public static U MapReduce<T, U>(this IList<T> list, Func<T, U> map, Func<U, U, U> reduce)
    {
        CodeContract.RequiresAlways(list != null);
        CodeContract.RequiresAlways(list.Skip(1).Any());
        CodeContract.RequiresAlways(map != null);
        CodeContract.RequiresAlways(reduce != null);

        U[] mapped = new U[list.Count];
        Parallel.For(0, mapped.Length, i =>
            {
                mapped[i] = map(list[i]);
            });
        U result = mapped[0];
        for (int i = 1; i < list.Count; i++)
        {
            result = reduce(result, mapped[i]);
        }
        return result;
    }

}

我喜欢这些NUnit Assert扩展:http://svn.caffeine-it.com/openrasta/trunk/src/Rasta.Testing/AssertExtensions.cs

通配符字符串比较:

public static bool MatchesWildcard(this string text, string pattern)
{
    int it = 0;
    while (text.CharAt(it) != 0 &&
           pattern.CharAt(it) != '*')
    {
        if (pattern.CharAt(it) != text.CharAt(it) && pattern.CharAt(it) != '?')
            return false;
        it++;
    }

    int cp = 0;
    int mp = 0;
    int ip = it;

    while (text.CharAt(it) != 0)
    {
        if (pattern.CharAt(ip) == '*')
        {
            if (pattern.CharAt(++ip) == 0)
                return true;
            mp = ip;
            cp = it + 1;
        }
        else if (pattern.CharAt(ip) == text.CharAt(it) || pattern.CharAt(ip) == '?')
        {
            ip++;
            it++;
        }
        else
        {
            ip = mp;
            it = cp++;
        }
    }

    while (pattern.CharAt(ip) == '*')
    {
        ip++;
    }
    return pattern.CharAt(ip) == 0;
}

public static char CharAt(this string s, int index)
{
    if (index < s.Length)
        return s[index];
    return '\0';
}

它直接翻译了本文中的C代码，因此CharAt方法将字符串的末尾返回0

if (fileName.MatchesWildcard("*.cs"))
{
    Console.WriteLine("{0} is a C# source file", fileName);
}

Sql server有~2000个参数的限制，如果你有10k个id并想要与它们连接的记录，这是一个痛苦。我写了这些方法，接受批量id列表，并像这样调用:

List<Order> orders = dataContext.Orders.FetchByIds(
  orderIdChunks,
  list => row => list.Contains(row.OrderId)
);

List<Customer> customers = dataContext.Orders.FetchByIds(
  orderIdChunks,
  list => row => list.Contains(row.OrderId),
  row => row.Customer
);

public static List<ResultType> FetchByIds<RecordType, ResultType>(
    this IQueryable<RecordType> querySource,
    List<List<int>> IdChunks,
    Func<List<int>, Expression<Func<RecordType, bool>>> filterExpressionGenerator,
    Expression<Func<RecordType, ResultType>> projectionExpression
    ) where RecordType : class
{
    List<ResultType> result = new List<ResultType>();
    foreach (List<int> chunk in IdChunks)
    {
        Expression<Func<RecordType, bool>> filterExpression =
            filterExpressionGenerator(chunk);

        IQueryable<ResultType> query = querySource
            .Where(filterExpression)
            .Select(projectionExpression);

        List<ResultType> rows = query.ToList();
        result.AddRange(rows);
    }

    return result;
}

public static List<RecordType> FetchByIds<RecordType>(
    this IQueryable<RecordType> querySource,
    List<List<int>> IdChunks,
    Func<List<int>, Expression<Func<RecordType, bool>>> filterExpressionGenerator
    ) where RecordType : class
{
    Expression<Func<RecordType, RecordType>> identity = r => r;

    return FetchByIds(
        querySource,
        IdChunks,
        filterExpressionGenerator,
        identity
        );
}