我还没有看到任何关于这个问题的答案…

public static string[] Split(this string value, string regexPattern)
{
    return value.Split(regexPattern, RegexOptions.None);
}

public static string[] Split(this string value, string regexPattern, 
    RegexOptions options)
{
    return Regex.Split(value, regexPattern, options);
}

用法:

var obj = "test1,test2,test3";
string[] arrays = obj.Split(",");

相当于Python的Join方法:

/// <summary>
/// same as python 'join'
/// </summary>
/// <typeparam name="T">list type</typeparam>
/// <param name="separator">string separator </param>
/// <param name="list">list of objects to be ToString'd</param>
/// <returns>a concatenated list interleaved with separators</returns>
static public string Join<T>(this string separator, IEnumerable<T> list)
{
    var sb = new StringBuilder();
    bool first = true;

    foreach (T v in list)
    {
        if (!first)
            sb.Append(separator);
        first = false;

        if (v != null)
            sb.Append(v.ToString());
    }

    return sb.ToString();
}

在这里找到更多的例子:www.extensionmethod.net

public static bool In<T>(this T source, params T[] list)
{
  if(null==source) throw new ArgumentNullException("source");
  return list.Contains(source);
}

允许我替换:

if(reallyLongIntegerVariableName == 1 || 
    reallyLongIntegerVariableName == 6 || 
    reallyLongIntegerVariableName == 9 || 
    reallyLongIntegerVariableName == 11)
{
  // do something....
}

and

if(reallyLongStringVariableName == "string1" || 
    reallyLongStringVariableName == "string2" || 
    reallyLongStringVariableName == "string3")
{
  // do something....
}

and

if(reallyLongMethodParameterName == SomeEnum.Value1 || 
    reallyLongMethodParameterName == SomeEnum.Value2 || 
    reallyLongMethodParameterName == SomeEnum.Value3 || 
    reallyLongMethodParameterName == SomeEnum.Value4)
{
  // do something....
}

:

if(reallyLongIntegerVariableName.In(1,6,9,11))
{
      // do something....
}

and

if(reallyLongStringVariableName.In("string1","string2","string3"))
{
      // do something....
}

and

if(reallyLongMethodParameterName.In(SomeEnum.Value1, SomeEnum.Value2, SomeEnum.Value3, SomeEnum.Value4)
{
  // do something....
}

有时使用自定义分隔符在列表中选中的元素上写出字符串是很方便的。

例如，如果你有一个List<Person>并且想要用逗号分隔姓氏，你可以这样做。

string result = string.Empty;
foreach (var person in personList) {
   result += person.LastName + ", ";
}
result = result.Substring(0, result.Length - 2);
return result;

或者你可以使用这个方便的扩展方法

public static string Join<T>(this IEnumerable<T> collection, Func<T, string> func, string separator)
{
  return String.Join(separator, collection.Select(func).ToArray());
}

像这样使用它

personList.Join(x => x.LastName, ", ");

这将产生相同的结果，在本例中是由逗号分隔的姓氏列表。

“请在你的答案上标记接受将代码放入Codeplex项目。”

为什么?这个网站上的所有东西都在CC-by-sa-2.5下，所以只要把你的扩展溢出项目放在相同的许可证下，你就可以自由使用它。

总之，这是一个字符串。逆函数，基于这个问题。

/// <summary>
/// Reverse a String
/// </summary>
/// <param name="input">The string to Reverse</param>
/// <returns>The reversed String</returns>
public static string Reverse(this string input)
{
    char[] array = input.ToCharArray();
    Array.Reverse(array);
    return new string(array);
}