让我们把你的优秀和最喜欢的扩展方法列一个列表。

要求是必须发布完整的代码,以及如何使用它的示例和解释。

基于对这个主题的高度兴趣,我在Codeplex上建立了一个名为extensionoverflow的开源项目。

请将您的回答标记为接受,以便将代码放入Codeplex项目。

请张贴完整的源代码,而不是一个链接。

Codeplex上新闻:

24.08.2010 Codeplex页面现在在这里:http://extensionoverflow.codeplex.com/

11.11.2008 XmlSerialize / XmlDeserialize现在是实现和单元测试。

11.11.2008仍有发展空间。;-)现在就加入!

11.11.2008第三位贡献者加入了ExtensionOverflow,欢迎加入BKristensen

11.11.2008 FormatWith现在是实现和单元测试。

09.11.2008第二个贡献者加入ExtensionOverflow。欢迎来到chakrit。

我们需要更多的开发人员。: -)

09.11.2008 ThrowIfArgumentIsNull现已在Codeplex上实现和单元测试。


当前回答

我最喜欢的是字符串上的IsLike()扩展。IsLike()匹配VB的Like操作符,当你不想写一个完整的正则表达式来解决你的问题时,它很方便。用法是这样的:

"abc".IsLike("a*"); // true
"Abc".IsLike("[A-Z][a-z][a-z]"); // true
"abc123".IsLike("*###"); // true
"hat".IsLike("?at"); // true
"joe".IsLike("[!aeiou]*"); // true

"joe".IsLike("?at"); // false
"joe".IsLike("[A-Z][a-z][a-z]"); // false

下面是代码

public static class StringEntentions {
    /// <summary>
    /// Indicates whether the current string matches the supplied wildcard pattern.  Behaves the same
    /// as VB's "Like" Operator.
    /// </summary>
    /// <param name="s">The string instance where the extension method is called</param>
    /// <param name="wildcardPattern">The wildcard pattern to match.  Syntax matches VB's Like operator.</param>
    /// <returns>true if the string matches the supplied pattern, false otherwise.</returns>
    /// <remarks>See http://msdn.microsoft.com/en-us/library/swf8kaxw(v=VS.100).aspx</remarks>
    public static bool IsLike(this string s, string wildcardPattern) {
        if (s == null || String.IsNullOrEmpty(wildcardPattern)) return false;
        // turn into regex pattern, and match the whole string with ^$
        var regexPattern = "^" + Regex.Escape(wildcardPattern) + "$";

        // add support for ?, #, *, [], and [!]
        regexPattern = regexPattern.Replace(@"\[!", "[^")
                                   .Replace(@"\[", "[")
                                   .Replace(@"\]", "]")
                                   .Replace(@"\?", ".")
                                   .Replace(@"\*", ".*")
                                   .Replace(@"\#", @"\d");

        var result = false;
        try {
            result = Regex.IsMatch(s, regexPattern);
        }
        catch (ArgumentException ex) {
            throw new ArgumentException(String.Format("Invalid pattern: {0}", wildcardPattern), ex);
        }
        return result;
    }
}

其他回答

字符串。格式的快捷方式:

public static class StringExtensions
{
    // Enable quick and more natural string.Format calls
    public static string F(this string s, params object[] args)
    {
        return string.Format(s, args);
    }
}

例子:

var s = "The co-ordinate is ({0}, {1})".F(point.X, point.Y);

要快速复制粘贴,请点击这里。

难道你不觉得输入“一些字符串”. f(“param”)而不是字符串更自然吗?格式(“一些字符串”,“参数”)?

想要一个更容易读懂的名字,试试下面的建议:

s = "Hello {0} world {1}!".Fmt("Stack", "Overflow");
s = "Hello {0} world {1}!".FormatBy("Stack", "Overflow");
s = "Hello {0} world {1}!".FormatWith("Stack", "Overflow");
s = "Hello {0} world {1}!".Display("Stack", "Overflow");
s = "Hello {0} world {1}!".With("Stack", "Overflow");

..

将double类型转换为使用指定区域性格式化的字符串:

public static class ExtensionMethods 
{
  public static string ToCurrency(this double value, string cultureName)
  {
    CultureInfo currentCulture = new CultureInfo(cultureName);
    return (string.Format(currentCulture, "{0:C}", value));
  }
}

例子:

double test = 154.20;
string testString = test.ToCurrency("en-US"); // $154.20

这是罗马数字的to-and-from。不常用,但可能很方便。用法:

if ("IV".IsValidRomanNumeral())
{
   // Do useful stuff with the number 4.
}

Console.WriteLine("MMMDCCCLXXXVIII".ParseRomanNumeral());
Console.WriteLine(3888.ToRomanNumeralString());

源:

    public static class RomanNumeralExtensions
    {
        private const int NumberOfRomanNumeralMaps = 13;

        private static readonly Dictionary<string, int> romanNumerals =
            new Dictionary<string, int>(NumberOfRomanNumeralMaps)
            {
                { "M", 1000 }, 
                { "CM", 900 }, 
                { "D", 500 }, 
                { "CD", 400 }, 
                { "C", 100 }, 
                { "XC", 90 }, 
                { "L", 50 }, 
                { "XL", 40 }, 
                { "X", 10 }, 
                { "IX", 9 }, 
                { "V", 5 }, 
                { "IV", 4 }, 
                { "I", 1 }
            };

        private static readonly Regex validRomanNumeral = new Regex(
            "^(?i:(?=[MDCLXVI])((M{0,3})((C[DM])|(D?C{0,3}))"
            + "?((X[LC])|(L?XX{0,2})|L)?((I[VX])|(V?(II{0,2}))|V)?))$", 
            RegexOptions.Compiled);

        public static bool IsValidRomanNumeral(this string value)
        {
            return validRomanNumeral.IsMatch(value);
        }

        public static int ParseRomanNumeral(this string value)
        {
            if (value == null)
            {
                throw new ArgumentNullException("value");
            }

            value = value.ToUpperInvariant().Trim();

            var length = value.Length;

            if ((length == 0) || !value.IsValidRomanNumeral())
            {
                throw new ArgumentException("Empty or invalid Roman numeral string.", "value");
            }

            var total = 0;
            var i = length;

            while (i > 0)
            {
                var digit = romanNumerals[value[--i].ToString()];

                if (i > 0)
                {
                    var previousDigit = romanNumerals[value[i - 1].ToString()];

                    if (previousDigit < digit)
                    {
                        digit -= previousDigit;
                        i--;
                    }
                }

                total += digit;
            }

            return total;
        }

        public static string ToRomanNumeralString(this int value)
        {
            const int MinValue = 1;
            const int MaxValue = 3999;

            if ((value < MinValue) || (value > MaxValue))
            {
                throw new ArgumentOutOfRangeException("value", value, "Argument out of Roman numeral range.");
            }

            const int MaxRomanNumeralLength = 15;
            var sb = new StringBuilder(MaxRomanNumeralLength);

            foreach (var pair in romanNumerals)
            {
                while (value / pair.Value > 0)
                {
                    sb.Append(pair.Key);
                    value -= pair.Value;
                }
            }

            return sb.ToString();
        }
    }

空格规范化非常有用,特别是在处理用户输入时:

namespace Extensions.String
{
    using System.Text.RegularExpressions;

    public static class Extensions
    {
        /// <summary>
        /// Normalizes whitespace in a string.
        /// Leading/Trailing whitespace is eliminated and
        /// all sequences of internal whitespace are reduced to
        /// a single SP (ASCII 0x20) character.
        /// </summary>
        /// <param name="s">The string whose whitespace is to be normalized</param>
        /// <returns>a normalized string</returns>
        public static string NormalizeWS( this string @this )
        {
            string src        = @this ?? "" ;
            string normalized = rxWS.Replace( src , m =>{
                  bool isLeadingTrailingWS = ( m.Index == 0 || m.Index+m.Length == src.Length ? true : false ) ;
                  string p                 = ( isLeadingTrailingWS ? "" : " " ) ;
                  return p ;
                }) ;

            return normalized ;

        }
        private static Regex rxWS = new Regex( @"\s+" ) ;
    }
}

每n个字符换行一个字符串。

public static string WrapAt(this string str, int WrapPos)
{
    if (string.IsNullOrEmpty(str))
        throw new ArgumentNullException("str", "Cannot wrap a null string");
    str = str.Replace("\r", "").Replace("\n", "");

    if (str.Length <= WrapPos)
        return str;

    for (int i = str.Length; i >= 0; i--)
        if (i % WrapPos == 0 && i > 0 && i != str.Length)
            str = str.Insert(i, "\r\n");
    return str;
}