iOS13, Swift 5+

Locale.preferredLanguages.first

iOS 9的解决方案:

NSString *language = [[NSLocale preferredLanguages] objectAtIndex:0];

language = "en-US"

NSDictionary *languageDic = [NSLocale componentsFromLocaleIdentifier:language];

languageDic将拥有所需的组件

NSString *countryCode = [languageDic objectForKey:@"kCFLocaleCountryCodeKey"];

countryCode = "US"

NSString *languageCode = [languageDic objectForKey:@"kCFLocaleLanguageCodeKey"];

密码:

对于Swift 3.0，下面的代码可以用来回答你的问题:

 let language = Bundle.main.preferredLocalizations.first! as NSString

如果你只想得到语言，这里是我建议的答案:

NSString *langplusreg = [[NSLocale preferredLanguages] objectAtIndex:0];
NSString * langonly = [[langplusreg componentsSeparatedByString:@"-"] 
objectAtIndex:0];

在我的情况下，我只是想Locale语言而不是Locale区域。

输出: 如果你的区域语言是日语，区域区域是日本，那么:

朗加雷格 = 是-JP

朗只 = 和

I actually misread the original question, thought it asked for the "app UI" language (that's what I had googled for), not the "device UI", in which case the best answers would be the ones using preferredLocalizations, but those answers still give you a code, there is one more step to get a nice string to display. So, while the "device UI" language is already answered, if you want to display a nice string for which of the UI languages you support is currently in use, obviously the simplest solution is:

NSLocalizedString(@"currentLanguage", @"")

在你的每一个UI本地化中你都指定了你想要的显示方式。例如，在你的。strings文件的en版本中，你会有:

"currentLanguage"="English";

在你的fr版本的.strings文件中，你会有:

"currentLanguage"="Francais";

等。不要混淆代码等，你可以让你自己的字符串很好地匹配你的UI。

对于获得用户设备当前语言使用以下它的代码，它为我工作。

NSString * myString = [[NSLocale preferredlanguage]objectAtIndex:0];

从iOS 9开始，如果你只想要语言代码而不需要国家代码，你将需要这种帮助函数——因为语言将包含国家代码。

// gets the language code without country code in uppercase format, i.e. EN or DE
NSString* GetLanguageCode()
{
    static dispatch_once_t onceToken;
    static NSString* lang;
    dispatch_once(&onceToken, ^
    {
        lang = [[[NSLocale preferredLanguages] objectAtIndex:0] uppercaseString];
        NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern:@"^[A-Za-z]+" options:0 error:nil];
        NSTextCheckingResult* match = [regex firstMatchInString:lang options:0 range:NSMakeRange(0, lang.length)];
        if (match.range.location != NSNotFound)
        {
            lang = [lang substringToIndex:match.range.length];
        }
    });
    return lang;
}