我的单例访问方法通常是一些变种:

static MyClass *gInstance = NULL;

+ (MyClass *)instance
{
    @synchronized(self)
    {
        if (gInstance == NULL)
            gInstance = [[self alloc] init];
    }

    return(gInstance);
}

我能做些什么来改善这一点呢?


当前回答

我的方法很简单:

static id instanceOfXXX = nil;

+ (id) sharedXXX
{
    static volatile BOOL initialized = NO;

    if (!initialized)
    {
        @synchronized([XXX class])
        {
            if (!initialized)
            {
                instanceOfXXX = [[XXX alloc] init];
                initialized = YES;
            }
        }
    }

    return instanceOfXXX;
}

如果单例已经初始化,LOCK块将不会被输入。第二次检查if(!initialized)是为了确保当前线程获得LOCK时它还没有初始化。

其他回答

我知道有很多关于这个“问题”的评论,但是我没有看到很多人建议使用宏来定义单例对象。这是一个非常常见的模式,一个宏极大地简化了单例。

下面是我根据我见过的几个Objc实现编写的宏。

Singeton。h

/**
 @abstract  Helps define the interface of a singleton.
 @param  TYPE  The type of this singleton.
 @param  NAME  The name of the singleton accessor.  Must match the name used in the implementation.
 @discussion
 Typcially the NAME is something like 'sharedThing' where 'Thing' is the prefix-removed type name of the class.
 */
#define SingletonInterface(TYPE, NAME) \
+ (TYPE *)NAME;


/**
 @abstract  Helps define the implementation of a singleton.
 @param  TYPE  The type of this singleton.
 @param  NAME  The name of the singleton accessor.  Must match the name used in the interface.
 @discussion
 Typcially the NAME is something like 'sharedThing' where 'Thing' is the prefix-removed type name of the class.
 */
#define SingletonImplementation(TYPE, NAME) \
static TYPE *__ ## NAME; \
\
\
+ (void)initialize \
{ \
    static BOOL initialized = NO; \
    if(!initialized) \
    { \
        initialized = YES; \
        __ ## NAME = [[TYPE alloc] init]; \
    } \
} \
\
\
+ (TYPE *)NAME \
{ \
    return __ ## NAME; \
}

使用示例:

我的经理

@interface MyManager

SingletonInterface(MyManager, sharedManager);

// ...

@end

我的经理

@implementation MyManager

- (id)init
{
    self = [super init];
    if (self) {
        // Initialization code here.
    }

    return self;
}

SingletonImplementation(MyManager, sharedManager);

// ...

@end

为什么界面宏几乎是空的?头文件和代码文件之间的代码一致性;可维护性,以防您想添加更多的自动方法或更改它。

我使用initialize方法创建单例,就像这里(在撰写本文时)最流行的答案中使用的那样。

@interface MySingleton : NSObject
{
}

+ (MySingleton *)sharedSingleton;
@end

@implementation MySingleton

+ (MySingleton *)sharedSingleton
{
  static MySingleton *sharedSingleton;

  @synchronized(self)
  {
    if (!sharedSingleton)
      sharedSingleton = [[MySingleton alloc] init];

    return sharedSingleton;
  }
}

@end

(来源)

如何

static MyClass *gInstance = NULL;

+ (MyClass *)instance
{
    if (gInstance == NULL) {
        @synchronized(self)
        {
            if (gInstance == NULL)
                gInstance = [[self alloc] init];
        }
    }

    return(gInstance);
}

这样就避免了初始化后的同步成本?

我没有读完所有的解,所以如果这段代码是多余的,请原谅。

在我看来,这是最线程安全的实现。

+(SingletonObject *) sharedManager
{
    static SingletonObject * sharedResourcesObj = nil;

    @synchronized(self)
    {
        if (!sharedResourcesObj)
        {
            sharedResourcesObj = [[SingletonObject alloc] init];
        }
    }

    return sharedResourcesObj;
}
static mySingleton *obj=nil;

@implementation mySingleton

-(id) init {
    if(obj != nil){     
        [self release];
        return obj;
    } else if(self = [super init]) {
        obj = self;
    }   
    return obj;
}

+(mySingleton*) getSharedInstance {
    @synchronized(self){
        if(obj == nil) {
            obj = [[mySingleton alloc] init];
        }
    }
    return obj;
}

- (id)retain {
    return self;
}

- (id)copy {
    return self;
}

- (unsigned)retainCount {
    return UINT_MAX;  // denotes an object that cannot be released
}

- (void)release {
    if(obj != self){
        [super release];
    }
    //do nothing
}

- (id)autorelease {
    return self;
}

-(void) dealloc {
    [super dealloc];
}
@end