如果目录不存在,下面的方法是否正确?
它应该对脚本具有完全的权限,并且其他人可以阅读。
var dir = __dirname + '/upload';
if (!path.existsSync(dir)) {
fs.mkdirSync(dir, 0744);
}
如果目录不存在,下面的方法是否正确?
它应该对脚本具有完全的权限,并且其他人可以阅读。
var dir = __dirname + '/upload';
if (!path.existsSync(dir)) {
fs.mkdirSync(dir, 0744);
}
当前回答
下面是一个递归创建目录的小函数:
const createDir = (dir) => {
// This will create a dir given a path such as './folder/subfolder'
const splitPath = dir.split('/');
splitPath.reduce((path, subPath) => {
let currentPath;
if(subPath != '.'){
currentPath = path + '/' + subPath;
if (!fs.existsSync(currentPath)){
fs.mkdirSync(currentPath);
}
}
else{
currentPath = subPath;
}
return currentPath
}, '')
}
其他回答
使用Node.js 10 + ES6:
import path from 'path';
import fs from 'fs';
(async () => {
const dir = path.join(__dirname, 'upload');
try {
await fs.promises.mkdir(dir);
} catch (error) {
if (error.code === 'EEXIST') {
// Something already exists, but is it a file or directory?
const lstat = await fs.promises.lstat(dir);
if (!lstat.isDirectory()) {
throw error;
}
} else {
throw error;
}
}
})();
我的解决方案
CommonJS
var fs = require("fs");
var dir = __dirname + '/upload';
// if (!fs.existsSync(dir)) {
// fs.mkdirSync(dir);
// }
if (!fs.existsSync(dir)) {
fs.mkdirSync(dir, {
mode: 0o744,
});
// mode's default value is 0o744
}
ESM
更新包。json配置
{
//...
"type": "module",
//...
}
import fs from "fs";
import path from "path";
// create one custom `__dirname`, because it not exist in es-module env ⚠️
const __dirname = path.resolve();
const dir = __dirname + '/upload';
if (!fs.existsSync(dir)) {
fs.mkdirSync(dir);
}
// OR
if (!fs.existsSync(dir)) {
fs.mkdirSync(dir, {
mode: 0o744,
});
// mode's default value is 0o744
}
refs
https://nodejs.org/api/fs.html#fsexistssyncpath
https://github.com/nodejs/help/issues/2907#issuecomment-671782092
从文档中可以看出,这是你异步(和递归)做这件事的方式:
const fs = require('fs');
const fsPromises = fs.promises;
fsPromises.access(dir, fs.constants.F_OK)
.catch(async() => {
await fs.mkdir(dir, { recursive: true }, function(err) {
if (err) {
console.log(err)
}
})
});
我想添加一个TypeScript承诺重构josh3736的答案。
它做的是同样的事情,有同样的边界情况。它只是碰巧使用Promises, TypeScript typedefs,并使用“use strict”。
// https://en.wikipedia.org/wiki/File_system_permissions#Numeric_notation
const allRWEPermissions = parseInt("0777", 8);
function ensureFilePathExists(path: string, mask: number = allRWEPermissions): Promise<void> {
return new Promise<void>(
function(resolve: (value?: void | PromiseLike<void>) => void,
reject: (reason?: any) => void): void{
mkdir(path, mask, function(err: NodeJS.ErrnoException): void {
if (err) {
if (err.code === "EEXIST") {
resolve(null); // Ignore the error if the folder already exists
} else {
reject(err); // Something else went wrong
}
} else {
resolve(null); // Successfully created folder
}
});
});
}
异步执行此操作的函数(从使用同步函数的SO上的类似答案调整,我现在找不到)
// ensure-directory.js
import { mkdir, access } from 'fs'
/**
* directoryPath is a path to a directory (no trailing file!)
*/
export default async directoryPath => {
directoryPath = directoryPath.replace(/\\/g, '/')
// -- preparation to allow absolute paths as well
let root = ''
if (directoryPath[0] === '/') {
root = '/'
directoryPath = directoryPath.slice(1)
} else if (directoryPath[1] === ':') {
root = directoryPath.slice(0, 3) // c:\
directoryPath = directoryPath.slice(3)
}
// -- create folders all the way down
const folders = directoryPath.split('/')
let folderPath = `${root}`
for (const folder of folders) {
folderPath = `${folderPath}${folder}/`
const folderExists = await new Promise(resolve =>
access(folderPath, error => {
if (error) {
resolve(false)
}
resolve(true)
})
)
if (!folderExists) {
await new Promise((resolve, reject) =>
mkdir(folderPath, error => {
if (error) {
reject('Error creating folderPath')
}
resolve(folderPath)
})
)
}
}
}