是否有一种方法可以获得MySQL数据库中所有表的行计数,而无需在每个表上运行SELECT count() ?
当前回答
对于这个估算问题,有一点hack/workaround。
Auto_Increment -由于某些原因,如果您在表上设置了自动增量,则此函数将为数据库返回更准确的行数。
在探索为什么显示表信息与实际数据不匹配时发现了这一点。
SELECT
table_schema 'Database',
SUM(data_length + index_length) AS 'DBSize',
SUM(TABLE_ROWS) AS DBRows,
SUM(AUTO_INCREMENT) AS DBAutoIncCount
FROM information_schema.tables
GROUP BY table_schema;
+--------------------+-----------+---------+----------------+
| Database | DBSize | DBRows | DBAutoIncCount |
+--------------------+-----------+---------+----------------+
| Core | 35241984 | 76057 | 8341 |
| information_schema | 163840 | NULL | NULL |
| jspServ | 49152 | 11 | 856 |
| mysql | 7069265 | 30023 | 1 |
| net_snmp | 47415296 | 95123 | 324 |
| performance_schema | 0 | 1395326 | NULL |
| sys | 16384 | 6 | NULL |
| WebCal | 655360 | 2809 | NULL |
| WxObs | 494256128 | 530533 | 3066752 |
+--------------------+-----------+---------+----------------+
9 rows in set (0.40 sec)
然后,您可以轻松地使用PHP或其他工具返回2个数据列的最大值,以给出行数的“最佳估计”。
即。
SELECT
table_schema 'Database',
SUM(data_length + index_length) AS 'DBSize',
GREATEST(SUM(TABLE_ROWS), SUM(AUTO_INCREMENT)) AS DBRows
FROM information_schema.tables
GROUP BY table_schema;
Auto Increment将始终是+1 *(表数)行,但即使有4000个表和300万行,这也是99.9%的准确性。比估计的行数好多了。
这样做的好处是,performance_schema中返回的行计数也会被擦除,因为greatest对null无效。但是,如果没有带有自动递增功能的表,这可能是个问题。
其他回答
我只是跑:
show table status;
这将为您提供每个表的行数以及其他一些信息。 我曾经使用上面选择的答案,但这要简单得多。
我不确定这是否适用于所有版本,但我使用5.5与InnoDB引擎。
像@Venkatramanan和其他人一样,我找到了INFORMATION_SCHEMA。TABLES不可靠(使用InnoDB, MySQL 5.1.44),每次运行时给出不同的行数,即使是在静态表上。这里有一种生成大型SQL语句的相对hack(但是灵活/适应性强)的方法,您可以将其粘贴到新的查询中,而不需要安装Ruby宝石之类的东西。
SELECT CONCAT(
'SELECT "',
table_name,
'" AS table_name, COUNT(*) AS exact_row_count FROM `',
table_schema,
'`.`',
table_name,
'` UNION '
)
FROM INFORMATION_SCHEMA.TABLES
WHERE table_schema = '**my_schema**';
它产生如下输出:
SELECT "func" AS table_name, COUNT(*) AS exact_row_count FROM my_schema.func UNION
SELECT "general_log" AS table_name, COUNT(*) AS exact_row_count FROM my_schema.general_log UNION
SELECT "help_category" AS table_name, COUNT(*) AS exact_row_count FROM my_schema.help_category UNION
SELECT "help_keyword" AS table_name, COUNT(*) AS exact_row_count FROM my_schema.help_keyword UNION
SELECT "help_relation" AS table_name, COUNT(*) AS exact_row_count FROM my_schema.help_relation UNION
SELECT "help_topic" AS table_name, COUNT(*) AS exact_row_count FROM my_schema.help_topic UNION
SELECT "host" AS table_name, COUNT(*) AS exact_row_count FROM my_schema.host UNION
SELECT "ndb_binlog_index" AS table_name, COUNT(*) AS exact_row_count FROM my_schema.ndb_binlog_index UNION
复制粘贴,除了最后一个UNION,可以得到漂亮的输出,
+------------------+-----------------+
| table_name | exact_row_count |
+------------------+-----------------+
| func | 0 |
| general_log | 0 |
| help_category | 37 |
| help_keyword | 450 |
| help_relation | 990 |
| help_topic | 504 |
| host | 0 |
| ndb_binlog_index | 0 |
+------------------+-----------------+
8 rows in set (0.01 sec)
如果你使用数据库information_schema,你可以使用下面的mysql代码(where部分使查询不显示行为空值的表):
SELECT TABLE_NAME, TABLE_ROWS
FROM `TABLES`
WHERE `TABLE_ROWS` >=0
下面的代码为所有故事生成选择查询。只需删除最后的“UNION ALL”选择所有结果,并粘贴一个新的查询窗口运行。
SELECT
concat('select ''', table_name ,''' as TableName, COUNT(*) as RowCount from ' , table_name , ' UNION ALL ') as TR FROM
information_schema.tables where
table_schema = 'Database Name'
这个存储过程列出表,统计记录,并在最后生成记录的总数。
添加此过程后运行:
CALL `COUNT_ALL_RECORDS_BY_TABLE` ();
-
过程:
DELIMITER $$
CREATE DEFINER=`root`@`127.0.0.1` PROCEDURE `COUNT_ALL_RECORDS_BY_TABLE`()
BEGIN
DECLARE done INT DEFAULT 0;
DECLARE TNAME CHAR(255);
DECLARE table_names CURSOR for
SELECT table_name FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = DATABASE();
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;
OPEN table_names;
DROP TABLE IF EXISTS TCOUNTS;
CREATE TEMPORARY TABLE TCOUNTS
(
TABLE_NAME CHAR(255),
RECORD_COUNT INT
) ENGINE = MEMORY;
WHILE done = 0 DO
FETCH NEXT FROM table_names INTO TNAME;
IF done = 0 THEN
SET @SQL_TXT = CONCAT("INSERT INTO TCOUNTS(SELECT '" , TNAME , "' AS TABLE_NAME, COUNT(*) AS RECORD_COUNT FROM ", TNAME, ")");
PREPARE stmt_name FROM @SQL_TXT;
EXECUTE stmt_name;
DEALLOCATE PREPARE stmt_name;
END IF;
END WHILE;
CLOSE table_names;
SELECT * FROM TCOUNTS;
SELECT SUM(RECORD_COUNT) AS TOTAL_DATABASE_RECORD_CT FROM TCOUNTS;
END