是否有一种方法可以获得MySQL数据库中所有表的行计数,而无需在每个表上运行SELECT count() ?
当前回答
像许多其他人一样,我很难用InnoDB在INFORMATION_SCHEMA表上获得准确的值,并且能够通过count()进行查询将无限受益,并且希望在一次查询中完成它。
首先,确保启用大规模group_concats:
SET SESSION group_concat_max_len = 1000000;
然后运行此查询以获得将为数据库运行的结果查询。
SELECT CONCAT('SELECT ', GROUP_CONCAT(table1.count SEPARATOR ',\n')) FROM (
SELECT concat('(SELECT count(id) AS \'',table_name,' Count\' ','FROM ',table_name,') AS ',table_name,'_Count') AS 'count'
FROM information_schema.tables
WHERE table_schema = '**YOUR_DATABASE_HERE**'
) AS table1
这将生成诸如…
SELECT (SELECT count(id) AS 'table1 Count' FROM table1) AS table1_Count,
(SELECT count(id) AS 'table2 Count' FROM table2) AS table2_Count,
(SELECT count(id) AS 'table3 Count' FROM table3) AS table3_Count;
这反过来又产生了以下结果:
*************************** 1. row ***************************
table1_Count: 1
table2_Count: 1
table3_Count: 0
其他回答
还有一个选择:对于非InnoDB,它使用information_schema中的数据。TABLES(因为它更快),对于InnoDB -选择count(*)来获得准确的计数。它还会忽略视图。
SET @table_schema = DATABASE();
-- or SET @table_schema = 'my_db_name';
SET GROUP_CONCAT_MAX_LEN=131072;
SET @selects = NULL;
SELECT GROUP_CONCAT(
'SELECT "', table_name,'" as TABLE_NAME, COUNT(*) as TABLE_ROWS FROM `', table_name, '`'
SEPARATOR '\nUNION\n') INTO @selects
FROM information_schema.TABLES
WHERE TABLE_SCHEMA = @table_schema
AND ENGINE = 'InnoDB'
AND TABLE_TYPE = "BASE TABLE";
SELECT CONCAT_WS('\nUNION\n',
CONCAT('SELECT TABLE_NAME, TABLE_ROWS FROM information_schema.TABLES WHERE TABLE_SCHEMA = ? AND ENGINE <> "InnoDB" AND TABLE_TYPE = "BASE TABLE"'),
@selects) INTO @selects;
PREPARE stmt FROM @selects;
EXECUTE stmt USING @table_schema;
DEALLOCATE PREPARE stmt;
如果你的数据库有很多大的InnoDB表,计算所有行会花费更多的时间。
下面的查询生成一个(另一个)查询,该查询将从information_schema.tables中列出的每个模式中获取每个表的count(*)值。这里显示的查询的整个结果——所有行放在一起——包含一个以分号结尾的有效SQL语句——没有悬空的“联合”。在下面的查询中使用联合来避免悬空联合。
select concat('select "', table_schema, '.', table_name, '" as `schema.table`,
count(*)
from ', table_schema, '.', table_name, ' union ') as 'Query Row'
from information_schema.tables
union
select '(select null, null limit 0);';
下面的代码为所有故事生成选择查询。只需删除最后的“UNION ALL”选择所有结果,并粘贴一个新的查询窗口运行。
SELECT
concat('select ''', table_name ,''' as TableName, COUNT(*) as RowCount from ' , table_name , ' UNION ALL ') as TR FROM
information_schema.tables where
table_schema = 'Database Name'
像许多其他人一样,我很难用InnoDB在INFORMATION_SCHEMA表上获得准确的值,并且能够通过count()进行查询将无限受益,并且希望在一次查询中完成它。
首先,确保启用大规模group_concats:
SET SESSION group_concat_max_len = 1000000;
然后运行此查询以获得将为数据库运行的结果查询。
SELECT CONCAT('SELECT ', GROUP_CONCAT(table1.count SEPARATOR ',\n')) FROM (
SELECT concat('(SELECT count(id) AS \'',table_name,' Count\' ','FROM ',table_name,') AS ',table_name,'_Count') AS 'count'
FROM information_schema.tables
WHERE table_schema = '**YOUR_DATABASE_HERE**'
) AS table1
这将生成诸如…
SELECT (SELECT count(id) AS 'table1 Count' FROM table1) AS table1_Count,
(SELECT count(id) AS 'table2 Count' FROM table2) AS table2_Count,
(SELECT count(id) AS 'table3 Count' FROM table3) AS table3_Count;
这反过来又产生了以下结果:
*************************** 1. row ***************************
table1_Count: 1
table2_Count: 1
table3_Count: 0
基于上面@Nathan的回答,但不需要“删除最终的联合”,并带有对输出进行排序的选项,我使用以下SQL。它生成另一个SQL语句,然后运行:
select CONCAT( 'select * from (\n', group_concat( single_select SEPARATOR ' UNION\n'), '\n ) Q order by Q.exact_row_count desc') as sql_query
from (
SELECT CONCAT(
'SELECT "',
table_name,
'" AS table_name, COUNT(1) AS exact_row_count
FROM `',
table_schema,
'`.`',
table_name,
'`'
) as single_select
FROM INFORMATION_SCHEMA.TABLES
WHERE table_schema = 'YOUR_SCHEMA_NAME'
and table_type = 'BASE TABLE'
) Q
您确实需要一个足够大的group_concat_max_len服务器变量的值,但是从MariaDb 10.2.4开始,它应该默认为1M。
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