我想在sqlite数据库中删除或添加列
我正在使用以下查询删除列。
ALTER TABLE TABLENAME DROP COLUMN COLUMNNAME
但它会产生错误
System.Data.SQLite.SQLiteException: SQLite error
near "DROP": syntax error
我想在sqlite数据库中删除或添加列
我正在使用以下查询删除列。
ALTER TABLE TABLENAME DROP COLUMN COLUMNNAME
但它会产生错误
System.Data.SQLite.SQLiteException: SQLite error
near "DROP": syntax error
当前回答
我猜您想做的是数据库迁移。在SQLite中不存在“删除”列。但是,您可以使用ALTER表查询添加一个额外的列。
其他回答
我重写了@Udinic答案,以便代码自动生成表创建查询。它也不需要ConnectionSource。它还必须在事务中完成此操作。
public static String getOneTableDbSchema(SQLiteDatabase db, String tableName) {
Cursor c = db.rawQuery(
"SELECT * FROM `sqlite_master` WHERE `type` = 'table' AND `name` = '" + tableName + "'", null);
String result = null;
if (c.moveToFirst()) {
result = c.getString(c.getColumnIndex("sql"));
}
c.close();
return result;
}
public List<String> getTableColumns(SQLiteDatabase db, String tableName) {
ArrayList<String> columns = new ArrayList<>();
String cmd = "pragma table_info(" + tableName + ");";
Cursor cur = db.rawQuery(cmd, null);
while (cur.moveToNext()) {
columns.add(cur.getString(cur.getColumnIndex("name")));
}
cur.close();
return columns;
}
private void dropColumn(SQLiteDatabase db, String tableName, String[] columnsToRemove) {
db.beginTransaction();
try {
List<String> columnNamesWithoutRemovedOnes = getTableColumns(db, tableName);
// Remove the columns we don't want anymore from the table's list of columns
columnNamesWithoutRemovedOnes.removeAll(Arrays.asList(columnsToRemove));
String newColumnNamesSeparated = TextUtils.join(" , ", columnNamesWithoutRemovedOnes);
String sql = getOneTableDbSchema(db, tableName);
// Extract the SQL query that contains only columns
String oldColumnsSql = sql.substring(sql.indexOf("(")+1, sql.lastIndexOf(")"));
db.execSQL("ALTER TABLE " + tableName + " RENAME TO " + tableName + "_old;");
db.execSQL("CREATE TABLE `" + tableName + "` (" + getSqlWithoutRemovedColumns(oldColumnsSql, columnsToRemove)+ ");");
db.execSQL("INSERT INTO " + tableName + "(" + newColumnNamesSeparated + ") SELECT " + newColumnNamesSeparated + " FROM " + tableName + "_old;");
db.execSQL("DROP TABLE " + tableName + "_old;");
db.setTransactionSuccessful();
} catch {
//Error in between database transaction
} finally {
db.endTransaction();
}
}
正如其他人指出的那样
不能重命名列、删除列或添加或 从表中删除约束。
来源:http://www.sqlite.org/lang_altertable.html
而您总是可以创建一个新表,然后删除旧表。 我将尝试用一个例子来解释这种解决方法。
sqlite> .schema
CREATE TABLE person(
id INTEGER PRIMARY KEY,
first_name TEXT,
last_name TEXT,
age INTEGER,
height INTEGER
);
sqlite> select * from person ;
id first_name last_name age height
---------- ---------- ---------- ---------- ----------
0 john doe 20 170
1 foo bar 25 171
现在要从该表中删除列的高度。
创建另一个名为new_person的表
sqlite> CREATE TABLE new_person(
...> id INTEGER PRIMARY KEY,
...> first_name TEXT,
...> last_name TEXT,
...> age INTEGER
...> ) ;
sqlite>
现在从旧表复制数据
sqlite> INSERT INTO new_person
...> SELECT id, first_name, last_name, age FROM person ;
sqlite> select * from new_person ;
id first_name last_name age
---------- ---------- ---------- ----------
0 john doe 20
1 foo bar 25
sqlite>
现在删除person表并将new_person重命名为person
sqlite> DROP TABLE IF EXISTS person ;
sqlite> ALTER TABLE new_person RENAME TO person ;
sqlite>
如果你使用。schema,你会看到
sqlite>.schema
CREATE TABLE "person"(
id INTEGER PRIMARY KEY,
first_name TEXT,
last_name TEXT,
age INTEGER
);
您现在还可以使用DB浏览器为SQLite操作列
public void DeleteColFromTable(String DbName, String TableName, String ColName){
SQLiteDatabase db = openOrCreateDatabase(""+DbName+"", Context.MODE_PRIVATE, null);
db.execSQL("CREATE TABLE IF NOT EXISTS "+TableName+"(1x00dff);");
Cursor c = db.rawQuery("PRAGMA table_info("+TableName+")", null);
if (c.getCount() == 0) {
} else {
String columns1 = "";
String columns2 = "";
while (c.moveToNext()) {
if (c.getString(1).equals(ColName)) {
} else {
columns1 = columns1 + ", " + c.getString(1) + " " + c.getString(2);
columns2 = columns2 + ", " + c.getString(1);
}
if (c.isLast()) {
db.execSQL("CREATE TABLE IF NOT EXISTS DataBackup (" + columns1 + ");");
db.execSQL("INSERT INTO DataBackup SELECT " + columns2 + " FROM "+TableName+";");
db.execSQL("DROP TABLE "+TableName+"");
db.execSQL("ALTER TABLE DataBackup RENAME TO "+TableName+";");
}
}
}
}
只需要调用一个方法
DeleteColFromTable("Database name","Table name","Col name which want to delete");
基于http://www.sqlite.org/faq.html#q11上的信息在Python中实现。
import sqlite3 as db
import random
import string
QUERY_TEMPLATE_GET_COLUMNS = "PRAGMA table_info(@table_name)"
QUERY_TEMPLATE_DROP_COLUMN = """
BEGIN TRANSACTION;
CREATE TEMPORARY TABLE @tmp_table(@columns_to_keep);
INSERT INTO @tmp_table SELECT @columns_to_keep FROM @table_name;
DROP TABLE @table_name;
CREATE TABLE @table_name(@columns_to_keep);
INSERT INTO @table_name SELECT @columns_to_keep FROM @tmp_table;
DROP TABLE @tmp_table;
COMMIT;
"""
def drop_column(db_file, table_name, column_name):
con = db.connect(db_file)
QUERY_GET_COLUMNS = QUERY_TEMPLATE_GET_COLUMNS.replace("@table_name", table_name)
query_res = con.execute(QUERY_GET_COLUMNS).fetchall()
columns_list_to_keep = [i[1] for i in query_res if i[1] != column_name]
columns_to_keep = ",".join(columns_list_to_keep)
tmp_table = "tmp_%s" % "".join(random.sample(string.ascii_lowercase, 10))
QUERY_DROP_COLUMN = QUERY_TEMPLATE_DROP_COLUMN.replace("@table_name", table_name)\
.replace("@tmp_table", tmp_table).replace("@columns_to_keep", columns_to_keep)
con.executescript(QUERY_DROP_COLUMN)
con.close()
drop_column(DB_FILE, TABLE_NAME, COLUMN_NAME)
这个脚本首先创建随机的临时表,并只插入必要列的数据,除了将要删除的列。然后根据临时表恢复原表,删除临时表。