如果有很多嵌套对象，前面的答案就不起作用了。

相反，你可以从jquery-param/jquery-param.js中选择函数参数。这对我来说非常有效!

    var param = function (a) {
    var s = [], rbracket = /\[\]$/,
        isArray = function (obj) {
            return Object.prototype.toString.call(obj) === '[object Array]';
        }, add = function (k, v) {
            v = typeof v === 'function' ? v() : v === null ? '' : v === undefined ? '' : v;
            s[s.length] = encodeURIComponent(k) + '=' + encodeURIComponent(v);
        }, buildParams = function (prefix, obj) {
            var i, len, key;

            if (prefix) {
                if (isArray(obj)) {
                    for (i = 0, len = obj.length; i < len; i++) {
                        if (rbracket.test(prefix)) {
                            add(prefix, obj[i]);
                        } else {
                            buildParams(prefix + '[' + (typeof obj[i] === 'object' ? i : '') + ']', obj[i]);
                        }
                    }
                } else if (obj && String(obj) === '[object Object]') {
                    for (key in obj) {
                        buildParams(prefix + '[' + key + ']', obj[key]);
                    }
                } else {
                    add(prefix, obj);
                }
            } else if (isArray(obj)) {
                for (i = 0, len = obj.length; i < len; i++) {
                    add(obj[i].name, obj[i].value);
                }
            } else {
                for (key in obj) {
                    buildParams(key, obj[key]);
                }
            }
            return s;
        };

    return buildParams('', a).join('&').replace(/%20/g, '+');
};

对用户187291接受的解决方案的一个小修改:

serialize = function(obj) {
   var str = [];
   for(var p in obj){
       if (obj.hasOwnProperty(p)) {
           str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
       }
   }
   return str.join("&");
}

检查对象上的hasOwnProperty使JSLint和JSHint高兴，它防止意外序列化对象的方法或其他东西，如果对象不是一个简单的字典。有关JavaScript编程语言的代码约定的语句，请参阅上一段。

如果你想将整个对象作为一个参数传递，例如，?filter={param1: "val1"， param2: "val2"}:

const serializeObject = (obj) => {
  let objStr = JSON.stringify(obj);

  objStr = objStr.replace(/\{/g, encodeURIComponent("{"));
  objStr = objStr.replace(/}/g, encodeURIComponent("}"));
  objStr = objStr.replace(/:/g, encodeURIComponent(":"));

  return objStr;
};

let res = serializeObject({param1: "val1", param2: "val2"});
console.log("serializeObject:", res); //%7B"param1"%3A"val1","param2"%3A"val2"%7D
console.log("serializeObject-decoded:", decodeURIComponent(res)); //{"param1":"val1","param2":"val2"}

可以将具有未定义属性的对象传递给此函数。如果属性存在，它将被转换为查询字符串并返回查询字符串。

函数convertToQueryString(props) { const objQueryString ={…道具}; for (objQueryString中的const键){ If (!key) { 删除objQueryString(例子); ｝ ｝ const params = JSON.stringify(objQueryString); Const qs =参数 .replace (/[/''""{}]/ 克,”) .replace (/ [:] / g, ' = ') .replace (/, / g, ' & '); console.log (qs) 返回qs; ｝ convertToQueryString({order: undefined, limit: 5, page: 1})

PHP符号的TypeScript版本(没有URL转义版本)

/**
 * Converts an object into a Cookie-like string.
 * @param toSerialize object or array to be serialized
 * @param prefix used in deep objects to describe the final query parameter
 * @returns ampersand separated key=value pairs
 *
 * Example:
 * ```js
 * serialize({hello:[{world: "nice"}]}); // outputs  "hello[0][world]=nice"
 * ```
 * ---
 * Adapted to TS from a StackOverflow answer https://stackoverflow.com/a/1714899/4537906
 */
const serialize = (toSerialize: unknown = {}, prefix?: string) => {
  const keyValuePairs = [];

  Object.keys(toSerialize).forEach((attribute) => {
    if (Object.prototype.hasOwnProperty.call(toSerialize, attribute)) {
      const key = prefix ? `${prefix}[${attribute}]` : attribute;
      const value = toSerialize[attribute];
      const toBePushed =
        value !== null && typeof value === "object"
          ? serialize(value, key)
          : `${key}=${value}`;
      keyValuePairs.push(toBePushed);
    }
  });

  return keyValuePairs.join("&");
};

单行转换对象为查询字符串，以防有人再次需要它:

let Objs = { a: 'obejct-a', b: 'object-b' }

Object.keys(objs).map(key => key + '=' + objs[key]).join('&')

// The result will be a=object-a&b=object-b