是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?
没有jQuery,没有其他框架-只有纯JavaScript:)
是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?
没有jQuery,没有其他框架-只有纯JavaScript:)
当前回答
如果有很多嵌套对象,前面的答案就不起作用了。
相反,你可以从jquery-param/jquery-param.js中选择函数参数。这对我来说非常有效!
var param = function (a) {
var s = [], rbracket = /\[\]$/,
isArray = function (obj) {
return Object.prototype.toString.call(obj) === '[object Array]';
}, add = function (k, v) {
v = typeof v === 'function' ? v() : v === null ? '' : v === undefined ? '' : v;
s[s.length] = encodeURIComponent(k) + '=' + encodeURIComponent(v);
}, buildParams = function (prefix, obj) {
var i, len, key;
if (prefix) {
if (isArray(obj)) {
for (i = 0, len = obj.length; i < len; i++) {
if (rbracket.test(prefix)) {
add(prefix, obj[i]);
} else {
buildParams(prefix + '[' + (typeof obj[i] === 'object' ? i : '') + ']', obj[i]);
}
}
} else if (obj && String(obj) === '[object Object]') {
for (key in obj) {
buildParams(prefix + '[' + key + ']', obj[key]);
}
} else {
add(prefix, obj);
}
} else if (isArray(obj)) {
for (i = 0, len = obj.length; i < len; i++) {
add(obj[i].name, obj[i].value);
}
} else {
for (key in obj) {
buildParams(key, obj[key]);
}
}
return s;
};
return buildParams('', a).join('&').replace(/%20/g, '+');
};
其他回答
我对JSON stringfier进行了比较,结果如下:
JSON: {"_id":"5973782bdb9a930533b05cb2","isActive":true,"balance":"$1,446.35","age":32,"name":"Logan Keller","email":"logankeller@artiq.com","phone":"+1 (952) 533-2258","friends":[{"id":0,"name":"Colon Salazar"},{"id":1,"name":"French Mcneil"},{"id":2,"name":"Carol Martin"}],"favoriteFruit":"banana"}
Rison: (_id:'5973782bdb9a930533b05cb2',age:32,balance:'$1,446.35',email:'logankeller@artiq.com',favoriteFruit:banana,friends:!((id:0,name:'Colon Salazar'),(id:1,name:'French Mcneil'),(id:2,name:'Carol Martin')),isActive:!t,name:'Logan Keller',phone:'+1 (952) 533-2258')
O-Rison: _id:'5973782bdb9a930533b05cb2',age:32,balance:'$1,446.35',email:'logankeller@artiq.com',favoriteFruit:banana,friends:!((id:0,name:'Colon Salazar'),(id:1,name:'French Mcneil'),(id:2,name:'Carol Martin')),isActive:!t,name:'Logan Keller',phone:'+1 (952) 533-2258'
JSURL: ~(_id~'5973782bdb9a930533b05cb2~isActive~true~balance~'!1*2c446.35~age~32~name~'Logan*20Keller~email~'logankeller*40artiq.com~phone~'*2b1*20*28952*29*20533-2258~friends~(~(id~0~name~'Colon*20Salazar)~(id~1~name~'French*20Mcneil)~(id~2~name~'Carol*20Martin))~favoriteFruit~'banana)
QS: _id=5973782bdb9a930533b05cb2&isActive=true&balance=$1,446.35&age=32&name=Logan Keller&email=logankeller@artiq.com&phone=+1 (952) 533-2258&friends[0][id]=0&friends[0][name]=Colon Salazar&friends[1][id]=1&friends[1][name]=French Mcneil&friends[2][id]=2&friends[2][name]=Carol Martin&favoriteFruit=banana
URLON: $_id=5973782bdb9a930533b05cb2&isActive:true&balance=$1,446.35&age:32&name=Logan%20Keller&email=logankeller@artiq.com&phone=+1%20(952)%20533-2258&friends@$id:0&name=Colon%20Salazar;&$id:1&name=French%20Mcneil;&$id:2&name=Carol%20Martin;;&favoriteFruit=banana
QS-JSON: isActive=true&balance=%241%2C446.35&age=32&name=Logan+Keller&email=logankeller%40artiq.com&phone=%2B1+(952)+533-2258&friends(0).id=0&friends(0).name=Colon+Salazar&friends(1).id=1&friends(1).name=French+Mcneil&friends(2).id=2&friends(2).name=Carol+Martin&favoriteFruit=banana
其中最短的是URL对象表示法。
看起来好一点
objectToQueryString(obj, prefix) {
return Object.keys(obj).map(objKey => {
if (obj.hasOwnProperty(objKey)) {
const key = prefix ? `${prefix}[${objKey}]` : objKey;
const value = obj[objKey];
return typeof value === "object" ?
this.objectToQueryString(value, key) :
`${encodeURIComponent(key)}=${encodeURIComponent(value)}`;
}
return null;
}).join("&");
}
参考答案@user187291,添加“isArray”作为参数,使要转换的JSON嵌套数组。
data : {
staffId : "00000001",
Detail : [ {
"identityId" : "123456"
}, {
"identityId" : "654321"
} ],
}
要得到结果:
staffId=00000001&Detail[0].identityId=123456&Detail[1].identityId=654321
serialize = function(obj, prefix, isArray) {
var str = [],p = 0;
for (p in obj) {
if (obj.hasOwnProperty(p)) {
var k, v;
if (isArray)
k = prefix ? prefix + "[" + p + "]" : p, v = obj[p];
else
k = prefix ? prefix + "." + p + "" : p, v = obj[p];
if (v !== null && typeof v === "object") {
if (Array.isArray(v)) {
serialize(v, k, true);
} else {
serialize(v, k, false);
}
} else {
var query = k + "=" + v;
str.push(query);
}
}
}
return str.join("&");
};
serialize(data, "prefix", false);
对用户187291接受的解决方案的一个小修改:
serialize = function(obj) {
var str = [];
for(var p in obj){
if (obj.hasOwnProperty(p)) {
str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
}
}
return str.join("&");
}
检查对象上的hasOwnProperty使JSLint和JSHint高兴,它防止意外序列化对象的方法或其他东西,如果对象不是一个简单的字典。有关JavaScript编程语言的代码约定的语句,请参阅上一段。
下面是Object.entries的简洁递归版本。它处理任意嵌套的数组,但不处理嵌套的对象。它还会删除空元素:
const format = (k,v) => v !== null ? `${k}=${encodeURIComponent(v)}` : ''
const to_qs = (obj) => {
return [].concat(...Object.entries(obj)
.map(([k,v]) => Array.isArray(v)
? v.map(arr => to_qs({[k]:arr}))
: format(k,v)))
.filter(x => x)
.join('&');
}
例如:
let json = {
a: [1, 2, 3],
b: [], // omit b
c: 1,
d: "test&encoding", // uriencode
e: [[4,5],[6,7]], // flatten this
f: null, // omit nulls
g: 0
};
let qs = to_qs(json)
=> "a=1&a=2&a=3&c=1&d=test%26encoding&e=4&e=5&e=6&e=7&g=0"