是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?
没有jQuery,没有其他框架-只有纯JavaScript:)
是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?
没有jQuery,没有其他框架-只有纯JavaScript:)
当前回答
看起来好一点
objectToQueryString(obj, prefix) {
return Object.keys(obj).map(objKey => {
if (obj.hasOwnProperty(objKey)) {
const key = prefix ? `${prefix}[${objKey}]` : objKey;
const value = obj[objKey];
return typeof value === "object" ?
this.objectToQueryString(value, key) :
`${encodeURIComponent(key)}=${encodeURIComponent(value)}`;
}
return null;
}).join("&");
}
其他回答
Ruby on Rails和PHP样式的查询生成器
该方法将JavaScript对象转换为URI查询字符串。它还处理嵌套数组和对象(在Ruby on Rails和PHP语法中):
function serializeQuery(params, prefix) {
const query = Object.keys(params).map((key) => {
const value = params[key];
if (params.constructor === Array)
key = `${prefix}[]`;
else if (params.constructor === Object)
key = (prefix ? `${prefix}[${key}]` : key);
if (typeof value === 'object')
return serializeQuery(value, key);
else
return `${key}=${encodeURIComponent(value)}`;
});
return [].concat.apply([], query).join('&');
}
使用示例:
let params = {
a: 100,
b: 'has spaces',
c: [1, 2, 3],
d: { x: 9, y: 8}
}
serializeQuery(params)
// returns 'a=100&b=has%20spaces&c[]=1&c[]=2&c[]=3&d[x]=9&d[y]=8
是这样的:
Serialize =函数(obj) { Var STR = []; For (var p in obj) if (obj.hasOwnProperty(p)) { str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]))); } 返回str.join(“&”); } console.log(序列化({ Foo:“你好”, 栏:“100%” })); / / foo =你好% 20 there&bar 25 = 100%
它还转换递归对象(使用PHP“数组”符号表示查询字符串):
serialize = function(obj, prefix) { var str = [], p; for (p in obj) { if (obj.hasOwnProperty(p)) { var k = prefix ? prefix + "[" + p + "]" : p, v = obj[p]; str.push((v !== null && typeof v === "object") ? serialize(v, k) : encodeURIComponent(k) + "=" + encodeURIComponent(v)); } } return str.join("&"); } console.log(serialize({ foo: "hi there", bar: { blah: 123, quux: [1, 2, 3] } })); // foo=hi%20there&bar%5Bblah%5D=123&bar%5Bquux%5D%5B0%5D=1&bar%5Bquux%5D%5B1%5D=2&bar%5Bquux%5D%5B2%5D=3
只使用URLSearchParams,这适用于当前所有浏览器
new URLSearchParams(object).toString()
下面是Object.entries的简洁递归版本。它处理任意嵌套的数组,但不处理嵌套的对象。它还会删除空元素:
const format = (k,v) => v !== null ? `${k}=${encodeURIComponent(v)}` : ''
const to_qs = (obj) => {
return [].concat(...Object.entries(obj)
.map(([k,v]) => Array.isArray(v)
? v.map(arr => to_qs({[k]:arr}))
: format(k,v)))
.filter(x => x)
.join('&');
}
例如:
let json = {
a: [1, 2, 3],
b: [], // omit b
c: 1,
d: "test&encoding", // uriencode
e: [[4,5],[6,7]], // flatten this
f: null, // omit nulls
g: 0
};
let qs = to_qs(json)
=> "a=1&a=2&a=3&c=1&d=test%26encoding&e=4&e=5&e=6&e=7&g=0"
let data = {
id:1,
name:'Newuser'
};
const getqueryParam = data => {
let datasize = Object.keys(data).length;
let initial = '?';
Object.keys(data).map(function (key, index) {
initial = initial.concat(`${key}=${data[key]}`);
index != datasize - 1 && (initial = initial.concat('&'));
});
console.log(initial, 'MyqueryString');
return initial;
};
console.log(getqueryParam(data))//You can get the query string here
If you have baseUrl means to get full query use
baseUrl concat (getqueryParam(数据)。