Use:

const objectToQueryParams = (o = {}) =>
  Object.entries(o)
    .map((p) => `${encodeURIComponent(p[0])}=${encodeURIComponent(p[1])}`)
    .join("&");

参考以下要点了解更多信息: https://gist.github.com/bhaireshm

如果有很多嵌套对象，前面的答案就不起作用了。

相反，你可以从jquery-param/jquery-param.js中选择函数参数。这对我来说非常有效!

    var param = function (a) {
    var s = [], rbracket = /\[\]$/,
        isArray = function (obj) {
            return Object.prototype.toString.call(obj) === '[object Array]';
        }, add = function (k, v) {
            v = typeof v === 'function' ? v() : v === null ? '' : v === undefined ? '' : v;
            s[s.length] = encodeURIComponent(k) + '=' + encodeURIComponent(v);
        }, buildParams = function (prefix, obj) {
            var i, len, key;

            if (prefix) {
                if (isArray(obj)) {
                    for (i = 0, len = obj.length; i < len; i++) {
                        if (rbracket.test(prefix)) {
                            add(prefix, obj[i]);
                        } else {
                            buildParams(prefix + '[' + (typeof obj[i] === 'object' ? i : '') + ']', obj[i]);
                        }
                    }
                } else if (obj && String(obj) === '[object Object]') {
                    for (key in obj) {
                        buildParams(prefix + '[' + key + ']', obj[key]);
                    }
                } else {
                    add(prefix, obj);
                }
            } else if (isArray(obj)) {
                for (i = 0, len = obj.length; i < len; i++) {
                    add(obj[i].name, obj[i].value);
                }
            } else {
                for (key in obj) {
                    buildParams(key, obj[key]);
                }
            }
            return s;
        };

    return buildParams('', a).join('&').replace(/%20/g, '+');
};

const querystring=  {};

querystring.stringify = function (obj, sep = '&', eq = '=') {
  const escape = encodeURIComponent;
  const qs = [];
  let key = null;

  for (key in obj) if (obj.hasOwnProperty(key)) {
    qs.push(escape(key) + eq + escape(String(obj[key])));
  }
  return qs.join(sep);
};

例子:

const a  = querystring.stringify({a: 'all of them', b: true});
console.log(a);  // Output: a=all%20of%20them&b=true

另一种方法(没有递归对象):

   getQueryString = function(obj)
   {
      result = "";

      for(param in obj)
         result += ( encodeURIComponent(param) + '=' + encodeURIComponent(obj[param]) + '&' );

      if(result) //it's not empty string when at least one key/value pair was added. In such case we need to remove the last '&' char
         result = result.substr(0, result.length - 1); //If length is zero or negative, substr returns an empty string [ref. http://msdn.microsoft.com/en-us/library/0esxc5wy(v=VS.85).aspx]

      return result;
   }

alert( getQueryString({foo: "hi there", bar: 123, quux: 2 }) );

下面是一个简单的实现，获取一个对象并将其转换为查询参数字符串:

export function objectToQueryParams(queryParams: object): string {
  return queryParams ?
    Object.entries(queryParams).reduce((acc, [key, val], index) => {
      const sign = index === 0 ? '?' : '&';
      acc += `${sign}${encodeURIComponent(key)}=${encodeURIComponent(val)}`;
      return acc;
    }, '')
    : '';
}

下面是Object.entries的简洁递归版本。它处理任意嵌套的数组，但不处理嵌套的对象。它还会删除空元素:

const format = (k,v) => v !== null ? `${k}=${encodeURIComponent(v)}` : ''

const to_qs = (obj) => {
    return [].concat(...Object.entries(obj)
                       .map(([k,v]) => Array.isArray(v) 
                          ? v.map(arr => to_qs({[k]:arr})) 
                          : format(k,v)))
           .filter(x => x)
           .join('&');
}

例如:

let json = { 
    a: [1, 2, 3],
    b: [],              // omit b
    c: 1,
    d: "test&encoding", // uriencode
    e: [[4,5],[6,7]],   // flatten this
    f: null,            // omit nulls
    g: 0
};

let qs = to_qs(json)

=> "a=1&a=2&a=3&c=1&d=test%26encoding&e=4&e=5&e=6&e=7&g=0"