这里是我的演示:https://stackblitz.com/edit/react-dgz1ee?file=styles.css

I am using useEffect to call the children component's methods. I have tried with Proxy and Setter_Getter but sor far useEffect seems to be the more convenient way to call a child method from parent. To use Proxy and Setter_Getter it seems there is some subtlety to overcome first, because the element firstly rendered is an objectLike's element through the ref.current return => <div/>'s specificity. Concerning useEffect, you can also leverage on this approach to set the parent's state depending on what you want to do with the children.

在我提供的演示链接中，你会发现我完整的ReactJS代码和我的草稿，所以你可以欣赏我的解决方案的工作流程。

在这里，我只提供了相关代码的ReactJS片段。：

import React, {
  Component,
  createRef,
  forwardRef,
  useState,
  useEffect
} from "react"; 

{...}

// Child component
// I am defining here a forwardRef's element to get the Child's methods from the parent
// through the ref's element.
let Child = forwardRef((props, ref) => {
  // I am fetching the parent's method here
  // that allows me to connect the parent and the child's components
  let { validateChildren } = props;
  // I am initializing the state of the children
  // good if we can even leverage on the functional children's state
  let initialState = {
    one: "hello world",
    two: () => {
      console.log("I am accessing child method from parent :].");
      return "child method achieve";
    }
  };
  // useState initialization
  const [componentState, setComponentState] = useState(initialState);
  // useEffect will allow me to communicate with the parent
  // through a lifecycle data flow
  useEffect(() => {
    ref.current = { componentState };
    validateChildren(ref.current.componentState.two);
  });

{...}

});

{...}

// Parent component
class App extends Component {
  // initialize the ref inside the constructor element
  constructor(props) {
    super(props);
    this.childRef = createRef();
  }

  // I am implementing a parent's method
  // in child useEffect's method
  validateChildren = childrenMethod => {
    // access children method from parent
    childrenMethod();
    // or signaling children is ready
    console.log("children active");
  };

{...}
render(){
       return (
          {
            // I am referencing the children
            // also I am implementing the parent logic connector's function
            // in the child, here => this.validateChildren's function
          }
          <Child ref={this.childRef} validateChildren={this.validateChildren} />
        </div>
       )
}

https://facebook.github.io/react/tips/expose-component-functions.html 更多答案请参考这里调用React子组件上的方法

通过查看“reason”组件的引用，您正在破坏封装，如果不仔细检查使用该组件的所有位置，就不可能重构该组件。正因为如此，我们强烈建议将引用视为组件的私有，就像状态一样。

一般来说，数据应该通过道具沿着树向下传递。有一些例外情况(比如调用.focus()或触发一个不会真正“改变”状态的一次性动画)，但任何时候你要公开一个名为“set”的方法，道具通常是更好的选择。试着让内部输入组件担心它的大小和外观，这样它的祖先就不会担心。

我使用useEffect钩子来克服做这些事情的头痛，所以现在我传递一个变量给child，像这样:

import { useEffect, useState } from "react"; export const ParentComponent = () => { const [trigger, setTrigger] = useState(false); return ( <div onClick={() => { setTrigger(trigger => !trigger); }}> <ChildComponent trigger={trigger}></ChildComponent> </div> ); }; export const ChildComponent = (props) => { const triggerInvokedFromParent = () => { console.log('TriggerInvokedFromParent'); }; useEffect(() => { triggerInvokedFromParent(); }, [props.trigger]); return <span>ChildComponent</span>; };

我尝试使用createRef或useRef。它们都返回null。

其次，这个答案提出通过一个道具来设置一个在我看来最合理的函数。但如果子组件用于多个地方，则应该将额外的道具添加到其他地方。此外，如果您想在孙辈中调用一个方法，这个方法可能太啰嗦或太冗长。

所以我用一种非常原始的方式创建了我自己的函数存储。

下面是functionStore.js文件

const fns = {};

export function setFn(componentName, fnName, fn) {
  if (fns[componentName]) {
    fns[componentName][fnName] = fn;
  } else {
    fns[componentName] = { fnName: fn };
  }
}

export function callFn(componentName, fnName) {
  fns[componentName][fnName]();
}

我只是设置了需要从任何组件调用的函数。

import { setFn } from "./functionStore";
export class AComponent extends React.Component {
  componentDidMount() {
    setFn("AComponent", "aFunc", this.aFunc);
  }
  aFunc = () => { console.log("aFunc is called!"); };
}

然后我从其他组件调用它

import { callFn } from "./functionStore";
export class BComponent extends React.Component {
  
  // just call the function
  bFunc = () => { 
    callFn("AComponent", "aFunc");
  };
}

一个缺点是要调用的函数应该是无参数的。但这也可能以某种方式解决。目前，我不需要传递参数。

我希望我没有重复上面的内容但是如果传递一个回调道具来设置父类中的函数呢?这很有效，也很简单。(添加的代码在////之间)

class Parent extends Component {
  ///// 
  getAlert = () => {} // initial value for getAlert

  setGetAlertMethod = (newMethod) => {
    this.getAlert = newMethod;
  }
  /////

  render() {
    return (
      <Child setGetAlertMethod={this.setGetAlertMethod}>
        <button onClick={this.getAlert}>Click</button>
      </Child>
      );
    }
  }



class Child extends Component {
  /////
  componentDidMount() {
    this.props.setGetAlertMethod(this.getAlert);
  }
  /////

  getAlert() => {
    alert('clicked');
  }

  render() {
    return (
      <h1 ref="hello">Hello</h1>
    );
  }
}

这里有个虫子?注意: 我同意rossipedia的解决方案使用forwardRef, useRef, useImperativeHandle

网上有一些错误的信息说refs只能从React类组件创建，但如果你使用上面提到的钩子，你确实可以使用函数组件。注意，只有在我将文件更改为在导出组件时不使用withRouter()后，钩子才对我有效。例如，从

export default withRouter(TableConfig);

取而代之的是

export default TableConfig;

In hindsight the withRouter() is not needed for such a component anyway, but usually it doesn't hurt anything having it in. My use case is that I created a component to create a Table to handle the viewing and editing of config values, and I wanted to be able to tell this Child component to reset it's state values whenever the Parent form's Reset button was hit. UseRef() wouldn't properly get the ref or ref.current (kept on getting null) until I removed withRouter() from the file containing my child component TableConfig