是否有方法确定正在运行应用程序的设备。如果可能的话，我想区分iPhone和iPod Touch。
当前回答
我进一步将大的“isEqualToString”块转换为设备类型、生成和逗号后的其他限定符(我称之为子生成)的位掩码分类。它被包装在一个类中，带有一个单例调用SGPlatform，避免了大量重复的字符串操作。代码可用https://github.com/danloughney/spookyGroup
这个类允许你做这样的事情:
if ([SGPlatform iPad] && [SGPlatform generation] > 3) {
// set for high performance
}
and
switch ([SGPlatform deviceMask]) {
case DEVICE_IPHONE:
break;
case DEVICE_IPAD:
break;
case DEVICE_IPAD_MINI:
break;
}
设备的分类在platformBits方法中。这个方法对于本文的读者来说应该非常熟悉。我根据设备的类型和年代对其进行了分类，因为我最感兴趣的是整体性能，但源代码可以调整以提供您感兴趣的任何分类，如视网膜屏幕、网络功能等。
其他回答
你可以像这样使用UIDevice类:
NSString *deviceType = [UIDevice currentDevice].model;
if([deviceType isEqualToString:@"iPhone"])
// it's an iPhone
这个代码怎么样，如果新版本发布，你将标识与最后知道的设备
- (NSString *)getModel {
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *model = malloc(size);
sysctlbyname("hw.machine", model, &size, NULL, 0);
NSString *sDeviceModel = [NSString stringWithCString:model encoding:NSUTF8StringEncoding];
free(model);
if ([sDeviceModel isEqual:@"i386"]) return @"Simulator"; //iPhone Simulator
if ([sDeviceModel isEqual:@"iPhone1,1"]) return @"iPhone1G"; //iPhone 1G
if ([sDeviceModel isEqual:@"iPhone1,2"]) return @"iPhone3G"; //iPhone 3G
if ([sDeviceModel isEqual:@"iPhone2,1"]) return @"iPhone3GS"; //iPhone 3GS
if ([sDeviceModel isEqual:@"iPhone3,1"]) return @"iPhone3GS"; //iPhone 4 - AT&T
if ([sDeviceModel isEqual:@"iPhone3,2"]) return @"iPhone3GS"; //iPhone 4 - Other carrier
if ([sDeviceModel isEqual:@"iPhone3,3"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([sDeviceModel isEqual:@"iPhone4,1"]) return @"iPhone4S"; //iPhone 4S
if ([sDeviceModel isEqual:@"iPod1,1"]) return @"iPod1stGen"; //iPod Touch 1G
if ([sDeviceModel isEqual:@"iPod2,1"]) return @"iPod2ndGen"; //iPod Touch 2G
if ([sDeviceModel isEqual:@"iPod3,1"]) return @"iPod3rdGen"; //iPod Touch 3G
if ([sDeviceModel isEqual:@"iPod4,1"]) return @"iPod4thGen"; //iPod Touch 4G
if ([sDeviceModel isEqual:@"iPad1,1"]) return @"iPadWiFi"; //iPad Wifi
if ([sDeviceModel isEqual:@"iPad1,2"]) return @"iPad3G"; //iPad 3G
if ([sDeviceModel isEqual:@"iPad2,1"]) return @"iPad2"; //iPad 2 (WiFi)
if ([sDeviceModel isEqual:@"iPad2,2"]) return @"iPad2"; //iPad 2 (GSM)
if ([sDeviceModel isEqual:@"iPad2,3"]) return @"iPad2"; //iPad 2 (CDMA)
NSString *aux = [[sDeviceModel componentsSeparatedByString:@","] objectAtIndex:0];
//If a newer version exist
if ([aux rangeOfString:@"iPhone"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] intValue];
if (version == 3) return @"iPhone4"
if (version >= 4) return @"iPhone4s";
}
if ([aux rangeOfString:@"iPod"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPod" withString:@""] intValue];
if (version >=4) return @"iPod4thGen";
}
if ([aux rangeOfString:@"iPad"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPad" withString:@""] intValue];
if (version ==1) return @"iPad3G";
if (version >=2) return @"iPad2";
}
//If none was found, send the original string
return sDeviceModel;
}
我想添加一个私有API来检索设备的正面和外壳颜色:
UIDevice *device = [UIDevice currentDevice];
SEL selector = NSSelectorFromString([device.systemVersion hasPrefix:@"7"] ? @"_deviceInfoForKey:" : @"deviceInfoForKey:");
if ([device respondsToSelector:selector]) {
NSLog(@"DeviceColor: %@ DeviceEnclosureColor: %@", [device performSelector:selector withObject:@"DeviceColor"], [device performSelector:selector withObject:@"DeviceEnclosureColor"]);
}
我在博客上写过这方面的文章，并提供了一个示例应用程序:
http://www.futuretap.com/blog/device-colors/
我知道答案已经被勾选了，但为了将来的参考，你可以总是使用设备屏幕大小来找出它是哪台设备:
if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
CGSize result = [[UIScreen mainScreen] bounds].size;
if (result.height == 480) {
// 3.5 inch display - iPhone 4S and below
NSLog(@"Device is an iPhone 4S or below");
}
else if (result.height == 568) {
// 4 inch display - iPhone 5
NSLog(@"Device is an iPhone 5/S/C");
}
else if (result.height == 667) {
// 4.7 inch display - iPhone 6
NSLog(@"Device is an iPhone 6");
}
else if (result.height == 736) {
// 5.5 inch display - iPhone 6 Plus
NSLog(@"Device is an iPhone 6 Plus");
}
}
else if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPad) {
// iPad 9.7 or 7.9 inch display.
NSLog(@"Device is an iPad.");
}
基于以上非常好的答案，以下是我想到的。这与@Rodrigo的回答非常相似，但解决了@Oliver对该回答的评论所关注的问题。这还提供了在输出字符串中包含模型字符串的选项。
+ (NSString *) deviceModel {
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *model = malloc(size);
sysctlbyname("hw.machine", model, &size, NULL, 0);
NSString *deviceModel = [NSString stringWithCString:model encoding:NSUTF8StringEncoding];
free(model);
return deviceModel;
}
+ (NSString *) deviceName {
NSString *deviceModel = [DeviceGateway deviceModel];
if ([deviceModel isEqual:@"i386"]) return @"Simulator"; //iPhone Simulator
if ([deviceModel isEqual:@"iPhone1,1"]) return @"iPhone1G"; //iPhone 1G
if ([deviceModel isEqual:@"iPhone1,2"]) return @"iPhone3G"; //iPhone 3G
if ([deviceModel isEqual:@"iPhone2,1"]) return @"iPhone3GS"; //iPhone 3GS
if ([deviceModel isEqual:@"iPhone3,1"]) return @"iPhone4"; //iPhone 4 - AT&T
if ([deviceModel isEqual:@"iPhone3,2"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([deviceModel isEqual:@"iPhone3,3"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([deviceModel isEqual:@"iPhone4,1"]) return @"iPhone4S"; //iPhone 4S
if ([deviceModel isEqual:@"iPod1,1"]) return @"iPod1stGen"; //iPod Touch 1G
if ([deviceModel isEqual:@"iPod2,1"]) return @"iPod2ndGen"; //iPod Touch 2G
if ([deviceModel isEqual:@"iPod3,1"]) return @"iPod3rdGen"; //iPod Touch 3G
if ([deviceModel isEqual:@"iPod4,1"]) return @"iPod4thGen"; //iPod Touch 4G
if ([deviceModel isEqual:@"iPad1,1"]) return @"iPadWiFi"; //iPad Wifi
if ([deviceModel isEqual:@"iPad1,2"]) return @"iPad3G"; //iPad 3G
if ([deviceModel isEqual:@"iPad2,1"]) return @"iPad2"; //iPad 2 (WiFi)
if ([deviceModel isEqual:@"iPad2,2"]) return @"iPad2"; //iPad 2 (GSM)
if ([deviceModel isEqual:@"iPad2,3"]) return @"iPad2"; //iPad 2 (CDMA)
NSString *aux = [[deviceModel componentsSeparatedByString:@","] objectAtIndex:0];
//If a newer version exists
if ([aux rangeOfString:@"iPhone"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] intValue];
if (version == 3) return @"iPhone4";
if (version == 4) return @"iPhone4s";
return @"Newer iPhone";
}
if ([aux rangeOfString:@"iPod"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPod" withString:@""] intValue];
if (version == 4) return @"iPod4thGen";
return @"Newer iPod";
}
if ([aux rangeOfString:@"iPad"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPad" withString:@""] intValue];
if (version == 1) return @"iPad3G";
if (version == 2) return @"iPad2";
return @"Newer iPad";
}
//If none was found, send the original string
return deviceModel;
}
+ (NSString *) deviceNameWithDeviceModel:(BOOL)shouldIncludeDeviceModel {
if (shouldIncludeDeviceModel) {
return [NSString stringWithFormat:@"%@ (%@)", [DeviceGateway deviceName], [DeviceGateway deviceModel]];
}
return [DeviceGateway deviceName];
}
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