是否有方法确定正在运行应用程序的设备。如果可能的话,我想区分iPhone和iPod Touch。
当前回答
请随意使用这个类(gist @ github)
代码已删除并重新定位到 https://gist.github.com/1323251
更新(01/14/11)
显然,这段代码现在有点过时了,但它肯定可以使用Brian Robbins提供的这个线程上的代码进行更新,其中包括更新模型的类似代码。谢谢你在这个帖子上的支持。
其他回答
iPad Air 2和iPad mini 3的更新平台字符串:
- (NSString *)platformString
{
NSString *platform = [self platform];
if ([platform isEqualToString:@"iPhone1,1"]) return @"iPhone 1G";
if ([platform isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
if ([platform isEqualToString:@"iPhone2,1"]) return @"iPhone 3GS";
if ([platform isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
if ([platform isEqualToString:@"iPhone3,3"]) return @"Verizon iPhone 4";
if ([platform isEqualToString:@"iPhone4,1"]) return @"iPhone 4S";
if ([platform isEqualToString:@"iPhone5,1"]) return @"iPhone 5 (GSM)";
if ([platform isEqualToString:@"iPhone5,2"]) return @"iPhone 5 (GSM+CDMA)";
if ([platform isEqualToString:@"iPhone5,3"]) return @"iPhone 5c (GSM)";
if ([platform isEqualToString:@"iPhone5,4"]) return @"iPhone 5c (GSM+CDMA)";
if ([platform isEqualToString:@"iPhone6,1"]) return @"iPhone 5s (GSM)";
if ([platform isEqualToString:@"iPhone6,2"]) return @"iPhone 5s (GSM+CDMA)";
if ([platform isEqualToString:@"iPhone7,1"]) return @"iPhone 6 Plus";
if ([platform isEqualToString:@"iPhone7,2"]) return @"iPhone 6";
if ([platform isEqualToString:@"iPod1,1"]) return @"iPod Touch 1G";
if ([platform isEqualToString:@"iPod2,1"]) return @"iPod Touch 2G";
if ([platform isEqualToString:@"iPod3,1"]) return @"iPod Touch 3G";
if ([platform isEqualToString:@"iPod4,1"]) return @"iPod Touch 4G";
if ([platform isEqualToString:@"iPod5,1"]) return @"iPod Touch 5G";
if ([platform isEqualToString:@"iPad1,1"]) return @"iPad";
if ([platform isEqualToString:@"iPad2,1"]) return @"iPad 2 (WiFi)";
if ([platform isEqualToString:@"iPad2,2"]) return @"iPad 2 (GSM)";
if ([platform isEqualToString:@"iPad2,3"]) return @"iPad 2 (CDMA)";
if ([platform isEqualToString:@"iPad2,4"]) return @"iPad 2 (WiFi)";
if ([platform isEqualToString:@"iPad2,5"]) return @"iPad Mini (WiFi)";
if ([platform isEqualToString:@"iPad2,6"]) return @"iPad Mini (GSM)";
if ([platform isEqualToString:@"iPad2,7"]) return @"iPad Mini (GSM+CDMA)";
if ([platform isEqualToString:@"iPad3,1"]) return @"iPad 3 (WiFi)";
if ([platform isEqualToString:@"iPad3,2"]) return @"iPad 3 (GSM+CDMA)";
if ([platform isEqualToString:@"iPad3,3"]) return @"iPad 3 (GSM)";
if ([platform isEqualToString:@"iPad3,4"]) return @"iPad 4 (WiFi)";
if ([platform isEqualToString:@"iPad3,5"]) return @"iPad 4 (GSM)";
if ([platform isEqualToString:@"iPad3,6"]) return @"iPad 4 (GSM+CDMA)";
if ([platform isEqualToString:@"iPad4,1"]) return @"iPad Air (WiFi)";
if ([platform isEqualToString:@"iPad4,2"]) return @"iPad Air (Cellular)";
if ([platform isEqualToString:@"iPad4,4"]) return @"iPad mini 2G (WiFi)";
if ([platform isEqualToString:@"iPad4,5"]) return @"iPad mini 2G (Cellular)";
if ([platform isEqualToString:@"iPad4,7"]) return @"iPad mini 3 (WiFi)";
if ([platform isEqualToString:@"iPad4,8"]) return @"iPad mini 3 (Cellular)";
if ([platform isEqualToString:@"iPad4,9"]) return @"iPad mini 3 (China Model)";
if ([platform isEqualToString:@"iPad5,3"]) return @"iPad Air 2 (WiFi)";
if ([platform isEqualToString:@"iPad5,4"]) return @"iPad Air 2 (Cellular)";
if ([platform isEqualToString:@"iPad6,8"]) return @"iPad Pro";
if ([platform isEqualToString:@"i386"]) return @"Simulator";
if ([platform isEqualToString:@"x86_64"]) return @"Simulator";
return platform;
}
要识别iPhone 4S,只需检查以下内容:
var isIphone4S: Bool {
let width = UIScreen.main.bounds.size.width
let height = UIScreen.main.bounds.size.height
let proportions = width > height ? width / height : height / width
return proportions == 1.5 && UIDevice.current.model == "iPhone"
}
只是将iPhone 4S设备代码添加到这个线程…
iPhone 4S将返回字符串@"iPhone4,1"。
Dutchie432和Brian Robbins提供了很好的解决方案。但还有一款型号没有推出,那就是Verizon的iPhone 4。这是缺失的一行。
if ([platform isEqualToString:@"iPhone3,2"]) return @"iPhone 4"; //Verizon
这个代码怎么样,如果新版本发布,你将标识与最后知道的设备
- (NSString *)getModel {
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *model = malloc(size);
sysctlbyname("hw.machine", model, &size, NULL, 0);
NSString *sDeviceModel = [NSString stringWithCString:model encoding:NSUTF8StringEncoding];
free(model);
if ([sDeviceModel isEqual:@"i386"]) return @"Simulator"; //iPhone Simulator
if ([sDeviceModel isEqual:@"iPhone1,1"]) return @"iPhone1G"; //iPhone 1G
if ([sDeviceModel isEqual:@"iPhone1,2"]) return @"iPhone3G"; //iPhone 3G
if ([sDeviceModel isEqual:@"iPhone2,1"]) return @"iPhone3GS"; //iPhone 3GS
if ([sDeviceModel isEqual:@"iPhone3,1"]) return @"iPhone3GS"; //iPhone 4 - AT&T
if ([sDeviceModel isEqual:@"iPhone3,2"]) return @"iPhone3GS"; //iPhone 4 - Other carrier
if ([sDeviceModel isEqual:@"iPhone3,3"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([sDeviceModel isEqual:@"iPhone4,1"]) return @"iPhone4S"; //iPhone 4S
if ([sDeviceModel isEqual:@"iPod1,1"]) return @"iPod1stGen"; //iPod Touch 1G
if ([sDeviceModel isEqual:@"iPod2,1"]) return @"iPod2ndGen"; //iPod Touch 2G
if ([sDeviceModel isEqual:@"iPod3,1"]) return @"iPod3rdGen"; //iPod Touch 3G
if ([sDeviceModel isEqual:@"iPod4,1"]) return @"iPod4thGen"; //iPod Touch 4G
if ([sDeviceModel isEqual:@"iPad1,1"]) return @"iPadWiFi"; //iPad Wifi
if ([sDeviceModel isEqual:@"iPad1,2"]) return @"iPad3G"; //iPad 3G
if ([sDeviceModel isEqual:@"iPad2,1"]) return @"iPad2"; //iPad 2 (WiFi)
if ([sDeviceModel isEqual:@"iPad2,2"]) return @"iPad2"; //iPad 2 (GSM)
if ([sDeviceModel isEqual:@"iPad2,3"]) return @"iPad2"; //iPad 2 (CDMA)
NSString *aux = [[sDeviceModel componentsSeparatedByString:@","] objectAtIndex:0];
//If a newer version exist
if ([aux rangeOfString:@"iPhone"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] intValue];
if (version == 3) return @"iPhone4"
if (version >= 4) return @"iPhone4s";
}
if ([aux rangeOfString:@"iPod"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPod" withString:@""] intValue];
if (version >=4) return @"iPod4thGen";
}
if ([aux rangeOfString:@"iPad"].location!=NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPad" withString:@""] intValue];
if (version ==1) return @"iPad3G";
if (version >=2) return @"iPad2";
}
//If none was found, send the original string
return sDeviceModel;
}
推荐文章
- Xcode构建失败“架构x86_64未定义的符号”
- 如何使用Xcode创建。ipa文件?
- 动态改变UILabel的字体大小
- registerForRemoteNotificationTypes: iOS 8.0及以上版本不支持
- Xcode 4 -在新的Macintosh安装上的配置文件上“没有找到有效的签名标识”错误
- 新的自动引用计数机制是如何工作的?
- 如何测试对象在Objective-C中的类?
- 在iPhone上确定用户是否启用了推送通知
- 是否有可能禁用浮动头在UITableView与UITableViewStylePlain?
- 从Cocoa应用程序执行一个终端命令
- 错误ITMS-9000:“冗余二进制文件上传。火车1.0版本已经有一个二进制版本上传。
- Swift -转换为绝对值
- Swift编译器错误:“框架模块内的非模块化头”
- 从父iOS访问容器视图控制器
- 自定义dealloc和ARC (Objective-C)