是否有方法确定正在运行应用程序的设备。如果可能的话,我想区分iPhone和iPod Touch。
当前回答
你可以在GitHub上查看GBDeviceInfo,也可以通过CocoaPods获得。它提供了简单的API来检测各种属性,支持所有最新的设备:
设备的家庭
[GBDeviceInfo deviceDetails]。family == GBDeviceFamilyiPhone;
设备模型
[GBDeviceInfo deviceDetails]。model == GBDeviceModeliPhone6。
欲了解更多,请参阅Readme。
其他回答
你可以像这样使用UIDevice类:
NSString *deviceType = [UIDevice currentDevice].model;
if([deviceType isEqualToString:@"iPhone"])
// it's an iPhone
我喜欢埃里卡·萨顿的作品。她包括苹果电视设备和其他你可能想不到的设备。
https://github.com/erica/uidevice-extension/blob/master/UIDevice-Hardware.h
要识别iPhone 4S,只需检查以下内容:
var isIphone4S: Bool {
let width = UIScreen.main.bounds.size.width
let height = UIScreen.main.bounds.size.height
let proportions = width > height ? width / height : height / width
return proportions == 1.5 && UIDevice.current.model == "iPhone"
}
NSString *deviceType = [[UIDevice currentDevice] systemName];
我可以保证,上述建议将适用于iOS 7及以上版本。我相信iOS 6也能运行。但我不确定。
基于以上非常好的答案,以下是我想到的。这与@Rodrigo的回答非常相似,但解决了@Oliver对该回答的评论所关注的问题。这还提供了在输出字符串中包含模型字符串的选项。
+ (NSString *) deviceModel {
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *model = malloc(size);
sysctlbyname("hw.machine", model, &size, NULL, 0);
NSString *deviceModel = [NSString stringWithCString:model encoding:NSUTF8StringEncoding];
free(model);
return deviceModel;
}
+ (NSString *) deviceName {
NSString *deviceModel = [DeviceGateway deviceModel];
if ([deviceModel isEqual:@"i386"]) return @"Simulator"; //iPhone Simulator
if ([deviceModel isEqual:@"iPhone1,1"]) return @"iPhone1G"; //iPhone 1G
if ([deviceModel isEqual:@"iPhone1,2"]) return @"iPhone3G"; //iPhone 3G
if ([deviceModel isEqual:@"iPhone2,1"]) return @"iPhone3GS"; //iPhone 3GS
if ([deviceModel isEqual:@"iPhone3,1"]) return @"iPhone4"; //iPhone 4 - AT&T
if ([deviceModel isEqual:@"iPhone3,2"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([deviceModel isEqual:@"iPhone3,3"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([deviceModel isEqual:@"iPhone4,1"]) return @"iPhone4S"; //iPhone 4S
if ([deviceModel isEqual:@"iPod1,1"]) return @"iPod1stGen"; //iPod Touch 1G
if ([deviceModel isEqual:@"iPod2,1"]) return @"iPod2ndGen"; //iPod Touch 2G
if ([deviceModel isEqual:@"iPod3,1"]) return @"iPod3rdGen"; //iPod Touch 3G
if ([deviceModel isEqual:@"iPod4,1"]) return @"iPod4thGen"; //iPod Touch 4G
if ([deviceModel isEqual:@"iPad1,1"]) return @"iPadWiFi"; //iPad Wifi
if ([deviceModel isEqual:@"iPad1,2"]) return @"iPad3G"; //iPad 3G
if ([deviceModel isEqual:@"iPad2,1"]) return @"iPad2"; //iPad 2 (WiFi)
if ([deviceModel isEqual:@"iPad2,2"]) return @"iPad2"; //iPad 2 (GSM)
if ([deviceModel isEqual:@"iPad2,3"]) return @"iPad2"; //iPad 2 (CDMA)
NSString *aux = [[deviceModel componentsSeparatedByString:@","] objectAtIndex:0];
//If a newer version exists
if ([aux rangeOfString:@"iPhone"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] intValue];
if (version == 3) return @"iPhone4";
if (version == 4) return @"iPhone4s";
return @"Newer iPhone";
}
if ([aux rangeOfString:@"iPod"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPod" withString:@""] intValue];
if (version == 4) return @"iPod4thGen";
return @"Newer iPod";
}
if ([aux rangeOfString:@"iPad"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPad" withString:@""] intValue];
if (version == 1) return @"iPad3G";
if (version == 2) return @"iPad2";
return @"Newer iPad";
}
//If none was found, send the original string
return deviceModel;
}
+ (NSString *) deviceNameWithDeviceModel:(BOOL)shouldIncludeDeviceModel {
if (shouldIncludeDeviceModel) {
return [NSString stringWithFormat:@"%@ (%@)", [DeviceGateway deviceName], [DeviceGateway deviceModel]];
}
return [DeviceGateway deviceName];
}
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