是否有方法确定正在运行应用程序的设备。如果可能的话，我想区分iPhone和iPod Touch。
当前回答
更有用
#include <sys/types.h>
#include <sys/sysctl.h>
@interface UIDevice(Hardware)
- (NSString *) platform;
- (BOOL)hasRetinaDisplay;
- (BOOL)hasMultitasking;
- (BOOL)hasCamera;
@end
@implementation UIDevice(Hardware)
- (NSString *) platform{
int mib[2];
size_t len;
char *machine;
mib[0] = CTL_HW;
mib[1] = HW_MACHINE;
sysctl(mib, 2, NULL, &len, NULL, 0);
machine = malloc(len);
sysctl(mib, 2, machine, &len, NULL, 0);
NSString *platform = [NSString stringWithCString:machine encoding:NSASCIIStringEncoding];
free(machine);
return platform;
}
- (BOOL)hasRetinaDisplay {
NSString *platform = [self platform];
BOOL ret = YES;
if ([platform isEqualToString:@"iPhone1,1"]) {
ret = NO;
}
else
if ([platform isEqualToString:@"iPhone1,2"]) ret = NO;
else
if ([platform isEqualToString:@"iPhone2,1"]) ret = NO;
else
if ([platform isEqualToString:@"iPod1,1"]) ret = NO;
else
if ([platform isEqualToString:@"iPod2,1"]) ret = NO;
else
if ([platform isEqualToString:@"iPod3,1"]) ret = NO;
return ret;
}
- (BOOL)hasMultitasking {
if ([self respondsToSelector:@selector(isMultitaskingSupported)]) {
return [self isMultitaskingSupported];
}
return NO;
}
- (BOOL)hasCamera {
BOOL ret = NO;
// check camera availability
return ret;
}
@end
您可以读取属性
NSLog(@"platform %@, retita %@, multitasking %@", [[UIDevice currentDevice] platform], [[UIDevice currentDevice] hasRetinaDisplay] ? @"YES" : @"NO" , [[UIDevice currentDevice] hasMultitasking] ? @"YES" : @"NO");
其他回答
只是将iPhone 4S设备代码添加到这个线程…
iPhone 4S将返回字符串@"iPhone4,1"。
我在我的应用程序中使用这个。截至2012年12月。
- (NSString *) platformString {
// Gets a string with the device model
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *machine = malloc(size);
sysctlbyname("hw.machine", machine, &size, NULL, 0);
NSString *platform = [NSString stringWithCString:machine encoding:NSUTF8StringEncoding];
free(machine);
if ([platform isEqualToString:@"iPhone1,1"]) return @"iPhone 2G";
if ([platform isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
if ([platform isEqualToString:@"iPhone2,1"]) return @"iPhone 3GS";
if ([platform isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
if ([platform isEqualToString:@"iPhone3,2"]) return @"iPhone 4";
if ([platform isEqualToString:@"iPhone3,3"]) return @"iPhone 4 (CDMA)";
if ([platform isEqualToString:@"iPhone4,1"]) return @"iPhone 4S";
if ([platform isEqualToString:@"iPhone5,1"]) return @"iPhone 5";
if ([platform isEqualToString:@"iPhone5,2"]) return @"iPhone 5 (GSM+CDMA)";
if ([platform isEqualToString:@"iPod1,1"]) return @"iPod Touch (1 Gen)";
if ([platform isEqualToString:@"iPod2,1"]) return @"iPod Touch (2 Gen)";
if ([platform isEqualToString:@"iPod3,1"]) return @"iPod Touch (3 Gen)";
if ([platform isEqualToString:@"iPod4,1"]) return @"iPod Touch (4 Gen)";
if ([platform isEqualToString:@"iPod5,1"]) return @"iPod Touch (5 Gen)";
if ([platform isEqualToString:@"iPad1,1"]) return @"iPad";
if ([platform isEqualToString:@"iPad1,2"]) return @"iPad 3G";
if ([platform isEqualToString:@"iPad2,1"]) return @"iPad 2 (WiFi)";
if ([platform isEqualToString:@"iPad2,2"]) return @"iPad 2";
if ([platform isEqualToString:@"iPad2,3"]) return @"iPad 2 (CDMA)";
if ([platform isEqualToString:@"iPad2,4"]) return @"iPad 2";
if ([platform isEqualToString:@"iPad2,5"]) return @"iPad Mini (WiFi)";
if ([platform isEqualToString:@"iPad2,6"]) return @"iPad Mini";
if ([platform isEqualToString:@"iPad2,7"]) return @"iPad Mini (GSM+CDMA)";
if ([platform isEqualToString:@"iPad3,1"]) return @"iPad 3 (WiFi)";
if ([platform isEqualToString:@"iPad3,2"]) return @"iPad 3 (GSM+CDMA)";
if ([platform isEqualToString:@"iPad3,3"]) return @"iPad 3";
if ([platform isEqualToString:@"iPad3,4"]) return @"iPad 4 (WiFi)";
if ([platform isEqualToString:@"iPad3,5"]) return @"iPad 4";
if ([platform isEqualToString:@"iPad3,6"]) return @"iPad 4 (GSM+CDMA)";
if ([platform isEqualToString:@"i386"]) return @"Simulator";
if ([platform isEqualToString:@"x86_64"]) return @"Simulator";
return platform;
}
为了简单的比较，我总是喜欢宏观:
#define IS_IPOD [[UIDevice currentDevice].model containsString:@"iPod"]
#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
它简单易用。
Dutchie432和Brian Robbins提供了很好的解决方案。但还有一款型号没有推出，那就是Verizon的iPhone 4。这是缺失的一行。
if ([platform isEqualToString:@"iPhone3,2"]) return @"iPhone 4"; //Verizon
更有用
#include <sys/types.h>
#include <sys/sysctl.h>
@interface UIDevice(Hardware)
- (NSString *) platform;
- (BOOL)hasRetinaDisplay;
- (BOOL)hasMultitasking;
- (BOOL)hasCamera;
@end
@implementation UIDevice(Hardware)
- (NSString *) platform{
int mib[2];
size_t len;
char *machine;
mib[0] = CTL_HW;
mib[1] = HW_MACHINE;
sysctl(mib, 2, NULL, &len, NULL, 0);
machine = malloc(len);
sysctl(mib, 2, machine, &len, NULL, 0);
NSString *platform = [NSString stringWithCString:machine encoding:NSASCIIStringEncoding];
free(machine);
return platform;
}
- (BOOL)hasRetinaDisplay {
NSString *platform = [self platform];
BOOL ret = YES;
if ([platform isEqualToString:@"iPhone1,1"]) {
ret = NO;
}
else
if ([platform isEqualToString:@"iPhone1,2"]) ret = NO;
else
if ([platform isEqualToString:@"iPhone2,1"]) ret = NO;
else
if ([platform isEqualToString:@"iPod1,1"]) ret = NO;
else
if ([platform isEqualToString:@"iPod2,1"]) ret = NO;
else
if ([platform isEqualToString:@"iPod3,1"]) ret = NO;
return ret;
}
- (BOOL)hasMultitasking {
if ([self respondsToSelector:@selector(isMultitaskingSupported)]) {
return [self isMultitaskingSupported];
}
return NO;
}
- (BOOL)hasCamera {
BOOL ret = NO;
// check camera availability
return ret;
}
@end
您可以读取属性
NSLog(@"platform %@, retita %@, multitasking %@", [[UIDevice currentDevice] platform], [[UIDevice currentDevice] hasRetinaDisplay] ? @"YES" : @"NO" , [[UIDevice currentDevice] hasMultitasking] ? @"YES" : @"NO");
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