是否有方法确定正在运行应用程序的设备。如果可能的话，我想区分iPhone和iPod Touch。
当前回答
基于以上非常好的答案，以下是我想到的。这与@Rodrigo的回答非常相似，但解决了@Oliver对该回答的评论所关注的问题。这还提供了在输出字符串中包含模型字符串的选项。
+ (NSString *) deviceModel {
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *model = malloc(size);
sysctlbyname("hw.machine", model, &size, NULL, 0);
NSString *deviceModel = [NSString stringWithCString:model encoding:NSUTF8StringEncoding];
free(model);
return deviceModel;
}
+ (NSString *) deviceName {
NSString *deviceModel = [DeviceGateway deviceModel];
if ([deviceModel isEqual:@"i386"]) return @"Simulator"; //iPhone Simulator
if ([deviceModel isEqual:@"iPhone1,1"]) return @"iPhone1G"; //iPhone 1G
if ([deviceModel isEqual:@"iPhone1,2"]) return @"iPhone3G"; //iPhone 3G
if ([deviceModel isEqual:@"iPhone2,1"]) return @"iPhone3GS"; //iPhone 3GS
if ([deviceModel isEqual:@"iPhone3,1"]) return @"iPhone4"; //iPhone 4 - AT&T
if ([deviceModel isEqual:@"iPhone3,2"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([deviceModel isEqual:@"iPhone3,3"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([deviceModel isEqual:@"iPhone4,1"]) return @"iPhone4S"; //iPhone 4S
if ([deviceModel isEqual:@"iPod1,1"]) return @"iPod1stGen"; //iPod Touch 1G
if ([deviceModel isEqual:@"iPod2,1"]) return @"iPod2ndGen"; //iPod Touch 2G
if ([deviceModel isEqual:@"iPod3,1"]) return @"iPod3rdGen"; //iPod Touch 3G
if ([deviceModel isEqual:@"iPod4,1"]) return @"iPod4thGen"; //iPod Touch 4G
if ([deviceModel isEqual:@"iPad1,1"]) return @"iPadWiFi"; //iPad Wifi
if ([deviceModel isEqual:@"iPad1,2"]) return @"iPad3G"; //iPad 3G
if ([deviceModel isEqual:@"iPad2,1"]) return @"iPad2"; //iPad 2 (WiFi)
if ([deviceModel isEqual:@"iPad2,2"]) return @"iPad2"; //iPad 2 (GSM)
if ([deviceModel isEqual:@"iPad2,3"]) return @"iPad2"; //iPad 2 (CDMA)
NSString *aux = [[deviceModel componentsSeparatedByString:@","] objectAtIndex:0];
//If a newer version exists
if ([aux rangeOfString:@"iPhone"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] intValue];
if (version == 3) return @"iPhone4";
if (version == 4) return @"iPhone4s";
return @"Newer iPhone";
}
if ([aux rangeOfString:@"iPod"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPod" withString:@""] intValue];
if (version == 4) return @"iPod4thGen";
return @"Newer iPod";
}
if ([aux rangeOfString:@"iPad"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPad" withString:@""] intValue];
if (version == 1) return @"iPad3G";
if (version == 2) return @"iPad2";
return @"Newer iPad";
}
//If none was found, send the original string
return deviceModel;
}
+ (NSString *) deviceNameWithDeviceModel:(BOOL)shouldIncludeDeviceModel {
if (shouldIncludeDeviceModel) {
return [NSString stringWithFormat:@"%@ (%@)", [DeviceGateway deviceName], [DeviceGateway deviceModel]];
}
return [DeviceGateway deviceName];
}
其他回答
下面提到的代码片段应该有帮助:
if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
// iPhone device
}
else if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPad) {
// iPad device
}
else {
// Other device i.e. iPod
}
- (BOOL)deviceiPhoneOriPod
{
NSString *deviceType = [UIDevice currentDevice].model;
if([deviceType rangeOfString:@"iPhone"].location!=NSNotFound)
return YES;
else
return NO;
}
请随意使用这个类(gist @ github)
代码已删除并重新定位到 https://gist.github.com/1323251
更新(01/14/11)
显然，这段代码现在有点过时了，但它肯定可以使用Brian Robbins提供的这个线程上的代码进行更新，其中包括更新模型的类似代码。谢谢你在这个帖子上的支持。
基于以上非常好的答案，以下是我想到的。这与@Rodrigo的回答非常相似，但解决了@Oliver对该回答的评论所关注的问题。这还提供了在输出字符串中包含模型字符串的选项。
+ (NSString *) deviceModel {
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *model = malloc(size);
sysctlbyname("hw.machine", model, &size, NULL, 0);
NSString *deviceModel = [NSString stringWithCString:model encoding:NSUTF8StringEncoding];
free(model);
return deviceModel;
}
+ (NSString *) deviceName {
NSString *deviceModel = [DeviceGateway deviceModel];
if ([deviceModel isEqual:@"i386"]) return @"Simulator"; //iPhone Simulator
if ([deviceModel isEqual:@"iPhone1,1"]) return @"iPhone1G"; //iPhone 1G
if ([deviceModel isEqual:@"iPhone1,2"]) return @"iPhone3G"; //iPhone 3G
if ([deviceModel isEqual:@"iPhone2,1"]) return @"iPhone3GS"; //iPhone 3GS
if ([deviceModel isEqual:@"iPhone3,1"]) return @"iPhone4"; //iPhone 4 - AT&T
if ([deviceModel isEqual:@"iPhone3,2"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([deviceModel isEqual:@"iPhone3,3"]) return @"iPhone4"; //iPhone 4 - Other carrier
if ([deviceModel isEqual:@"iPhone4,1"]) return @"iPhone4S"; //iPhone 4S
if ([deviceModel isEqual:@"iPod1,1"]) return @"iPod1stGen"; //iPod Touch 1G
if ([deviceModel isEqual:@"iPod2,1"]) return @"iPod2ndGen"; //iPod Touch 2G
if ([deviceModel isEqual:@"iPod3,1"]) return @"iPod3rdGen"; //iPod Touch 3G
if ([deviceModel isEqual:@"iPod4,1"]) return @"iPod4thGen"; //iPod Touch 4G
if ([deviceModel isEqual:@"iPad1,1"]) return @"iPadWiFi"; //iPad Wifi
if ([deviceModel isEqual:@"iPad1,2"]) return @"iPad3G"; //iPad 3G
if ([deviceModel isEqual:@"iPad2,1"]) return @"iPad2"; //iPad 2 (WiFi)
if ([deviceModel isEqual:@"iPad2,2"]) return @"iPad2"; //iPad 2 (GSM)
if ([deviceModel isEqual:@"iPad2,3"]) return @"iPad2"; //iPad 2 (CDMA)
NSString *aux = [[deviceModel componentsSeparatedByString:@","] objectAtIndex:0];
//If a newer version exists
if ([aux rangeOfString:@"iPhone"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPhone" withString:@""] intValue];
if (version == 3) return @"iPhone4";
if (version == 4) return @"iPhone4s";
return @"Newer iPhone";
}
if ([aux rangeOfString:@"iPod"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPod" withString:@""] intValue];
if (version == 4) return @"iPod4thGen";
return @"Newer iPod";
}
if ([aux rangeOfString:@"iPad"].location != NSNotFound) {
int version = [[aux stringByReplacingOccurrencesOfString:@"iPad" withString:@""] intValue];
if (version == 1) return @"iPad3G";
if (version == 2) return @"iPad2";
return @"Newer iPad";
}
//If none was found, send the original string
return deviceModel;
}
+ (NSString *) deviceNameWithDeviceModel:(BOOL)shouldIncludeDeviceModel {
if (shouldIncludeDeviceModel) {
return [NSString stringWithFormat:@"%@ (%@)", [DeviceGateway deviceName], [DeviceGateway deviceModel]];
}
return [DeviceGateway deviceName];
}
我想添加一个私有API来检索设备的正面和外壳颜色:
UIDevice *device = [UIDevice currentDevice];
SEL selector = NSSelectorFromString([device.systemVersion hasPrefix:@"7"] ? @"_deviceInfoForKey:" : @"deviceInfoForKey:");
if ([device respondsToSelector:selector]) {
NSLog(@"DeviceColor: %@ DeviceEnclosureColor: %@", [device performSelector:selector withObject:@"DeviceColor"], [device performSelector:selector withObject:@"DeviceEnclosureColor"]);
}
我在博客上写过这方面的文章，并提供了一个示例应用程序:
http://www.futuretap.com/blog/device-colors/
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