是否有方法确定正在运行应用程序的设备。如果可能的话,我想区分iPhone和iPod Touch。


当前回答

回答在Swift 3,

struct DeviceInformation {
    // UIDevice.current.model's value is "iPhone" or "iPad",which does not include details; the following "model" is detailed, such as, iPhone7,1 is actually iPhone 6 plus
    static let model: String = {
        var size = 0
        sysctlbyname("hw.machine", nil, &size, nil, 0)
        var machine = [CChar](repeating: 0,  count: Int(size))
        sysctlbyname("hw.machine", &machine, &size, nil, 0)
        return String(cString: machine)
    }()

    static let uuid = UIDevice.current.identifierForVendor?.uuidString ?? ""
    static let idForAdService = ASIdentifierManager.shared().advertisingIdentifier.uuidString

    static func diviceTypeReadableName() -> String {
        switch model {
        case "iPhone1,1":   return "iPhone 1G"
        case "iPhone1,2":   return "iPhone 3G"
        case "iPhone2,1":   return "iPhone 3GS"
        case "iPhone3,1":   return "iPhone 4"
        case "iPhone3,3":   return "iPhone 4 (Verizon)"
        case "iPhone4,1":   return "iPhone 4S"
        case "iPhone5,1":   return "iPhone 5 (GSM)"
        case "iPhone5,2":   return "iPhone 5 (GSM+CDMA)"
        case "iPhone5,3":   return "iPhone 5c (GSM)"
        case "iPhone5,4":   return "iPhone 5c (GSM+CDMA)"
        case "iPhone6,1":   return "iPhone 5s (GSM)"
        case "iPhone6,2":   return "iPhone 5s (GSM+CDMA)"
        case "iPhone7,2":   return "iPhone 6"
        case "iPhone7,1":   return "iPhone 6 Plus"
        case "iPhone8,1":   return "iPhone 6s"
        case "iPhone8,2":   return "iPhone 6s Plus"
        case "iPhone8,4":   return "iPhone SE"
        case "iPhone9,1":   return "iPhone 7"
        case "iPhone9,3":   return "iPhone 7"
        case "iPhone9,2":   return "iPhone 7 Plus"
        case "iPhone9,4":   return "iPhone 7 Plus"
        case "iPod1,1":     return "iPod Touch 1G"
        case "iPod2,1":     return "iPod Touch 2G"
        case "iPod3,1":     return "iPod Touch 3G"
        case "iPod4,1":     return "iPod Touch 4G"
        case "iPod5,1":     return "iPod Touch 5G"
        case "iPod7,1":     return "iPod Touch 6G"
        case "iPad1,1":     return "iPad 1G"
        case "iPad2,1":     return "iPad 2 (Wi-Fi)"
        case "iPad2,2":     return "iPad 2 (GSM)"
        case "iPad2,3":     return "iPad 2 (CDMA)"
        case "iPad2,4":     return "iPad 2 (Wi-Fi)"
        case "iPad2,5":     return "iPad Mini (Wi-Fi)"
        case "iPad2,6":     return "iPad Mini (GSM)"
        case "iPad2,7":     return "iPad Mini (GSM+CDMA)"
        case "iPad3,1":     return "iPad 3 (Wi-Fi)"
        case "iPad3,2":     return "iPad 3 (GSM+CDMA)"
        case "iPad3,3":     return "iPad 3 (GSM)"
        case "iPad3,4":     return "iPad 4 (Wi-Fi)"
        case "iPad3,5":     return "iPad 4 (GSM)"
        case "iPad3,6":     return "iPad 4 (GSM+CDMA)"
        case "iPad4,1":     return "iPad Air (Wi-Fi)"
        case "iPad4,2":     return "iPad Air (Cellular)"
        case "iPad4,3":     return "iPad Air (China)"
        case "iPad4,4":     return "iPad Mini 2G (Wi-Fi)"
        case "iPad4,5":     return "iPad Mini 2G (Cellular)"
        case "iPad4,6":     return "iPad Mini 2G (China)"
        case "iPad4,7":     return "iPad Mini 3 (Wi-Fi)"
        case "iPad4,8":     return "iPad Mini 3 (Cellular)"
        case "iPad4,9":     return "iPad Mini 3 (China)"
        case "iPad5,1":     return "iPad Mini 4 (Wi-Fi)"
        case "iPad5,2":     return "iPad Mini 4 (Cellular)"
        case "iPad5,3":     return "iPad Air 2 (Wi-Fi)"
        case "iPad5,4":     return "iPad Air 2 (Cellular)"
        case "iPad6,3":     return "iPad Pro 9.7' (Wi-Fi)"
        case "iPad6,4":     return "iPad Pro 9.7' (Cellular)"
        case "iPad6,7":     return "iPad Pro 12.9' (Wi-Fi)"
        case "iPad6,8":     return "iPad Pro 12.9' (Cellular)"
        case "AppleTV2,1":  return "Apple TV 2G"
        case "AppleTV3,1":  return "Apple TV 3"
        case "AppleTV3,2":  return "Apple TV 3 (2013)"
        case "AppleTV5,3":  return "Apple TV 4"
        case "Watch1,1":    return "Apple Watch Series 1 (38mm, S1)"
        case "Watch1,2":    return "Apple Watch Series 1 (42mm, S1)"
        case "Watch2,6":    return "Apple Watch Series 1 (38mm, S1P)"
        case "Watch2,7":    return "Apple Watch Series 1 (42mm, S1P)"
        case "Watch2,3":    return "Apple Watch Series 2 (38mm, S2)"
        case "Watch2,4":    return "Apple Watch Series 2 (42mm, S2)"
        case "i386":        return "Simulator"
        case "x86_64":      return "Simulator"

        default:
            return ""
        }
    }
}

其他回答

- (BOOL)deviceiPhoneOriPod
  {
    NSString *deviceType = [UIDevice currentDevice].model;
    if([deviceType rangeOfString:@"iPhone"].location!=NSNotFound)
      return YES;
    else
      return NO;
  }

你可以像这样使用UIDevice类:

NSString *deviceType = [UIDevice currentDevice].model;

if([deviceType isEqualToString:@"iPhone"])
    // it's an iPhone

你可以在GitHub上查看GBDeviceInfo,也可以通过CocoaPods获得。它提供了简单的API来检测各种属性,支持所有最新的设备:

设备的家庭

[GBDeviceInfo deviceDetails]。family == GBDeviceFamilyiPhone;

设备模型

[GBDeviceInfo deviceDetails]。model == GBDeviceModeliPhone6。

欲了解更多,请参阅Readme。

请随意使用这个类(gist @ github)

代码已删除并重新定位到 https://gist.github.com/1323251

更新(01/14/11)

显然,这段代码现在有点过时了,但它肯定可以使用Brian Robbins提供的这个线程上的代码进行更新,其中包括更新模型的类似代码。谢谢你在这个帖子上的支持。

NSString *deviceType = [UIDevice currentDevice].model;