是否有方法确定正在运行应用程序的设备。如果可能的话,我想区分iPhone和iPod Touch。
当前回答
只是将iPhone 4S设备代码添加到这个线程…
iPhone 4S将返回字符串@"iPhone4,1"。
其他回答
以下是新模型的小更新:
- (NSString *) platformString{
NSString *platform = [self platform];
if ([platform isEqualToString:@"iPhone1,1"]) return @"iPhone 1G";
if ([platform isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
if ([platform isEqualToString:@"iPhone2,1"]) return @"iPhone 3GS";
if ([platform isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
if ([platform isEqualToString:@"iPod1,1"]) return @"iPod Touch 1G";
if ([platform isEqualToString:@"iPod2,1"]) return @"iPod Touch 2G";
if ([platform isEqualToString:@"iPod3,1"]) return @"iPod Touch 3G";
if ([platform isEqualToString:@"i386"]) return @"iPhone Simulator";
return platform;
}
我已经创建了一个扩展,让你有3个级别的识别:
设备类型 按英寸划分iPhone/iPad的类型 设备型号
它会随着最新的iOS设备进行更新
UIDeviceDetector
if([UIDevice currentDevice].userInterfaceIdiom==UIUserInterfaceIdiomPad) {
//Device is ipad
}else{
//Device is iphone
}
我在我的应用程序中使用这个。截至2012年12月。
- (NSString *) platformString {
// Gets a string with the device model
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *machine = malloc(size);
sysctlbyname("hw.machine", machine, &size, NULL, 0);
NSString *platform = [NSString stringWithCString:machine encoding:NSUTF8StringEncoding];
free(machine);
if ([platform isEqualToString:@"iPhone1,1"]) return @"iPhone 2G";
if ([platform isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";
if ([platform isEqualToString:@"iPhone2,1"]) return @"iPhone 3GS";
if ([platform isEqualToString:@"iPhone3,1"]) return @"iPhone 4";
if ([platform isEqualToString:@"iPhone3,2"]) return @"iPhone 4";
if ([platform isEqualToString:@"iPhone3,3"]) return @"iPhone 4 (CDMA)";
if ([platform isEqualToString:@"iPhone4,1"]) return @"iPhone 4S";
if ([platform isEqualToString:@"iPhone5,1"]) return @"iPhone 5";
if ([platform isEqualToString:@"iPhone5,2"]) return @"iPhone 5 (GSM+CDMA)";
if ([platform isEqualToString:@"iPod1,1"]) return @"iPod Touch (1 Gen)";
if ([platform isEqualToString:@"iPod2,1"]) return @"iPod Touch (2 Gen)";
if ([platform isEqualToString:@"iPod3,1"]) return @"iPod Touch (3 Gen)";
if ([platform isEqualToString:@"iPod4,1"]) return @"iPod Touch (4 Gen)";
if ([platform isEqualToString:@"iPod5,1"]) return @"iPod Touch (5 Gen)";
if ([platform isEqualToString:@"iPad1,1"]) return @"iPad";
if ([platform isEqualToString:@"iPad1,2"]) return @"iPad 3G";
if ([platform isEqualToString:@"iPad2,1"]) return @"iPad 2 (WiFi)";
if ([platform isEqualToString:@"iPad2,2"]) return @"iPad 2";
if ([platform isEqualToString:@"iPad2,3"]) return @"iPad 2 (CDMA)";
if ([platform isEqualToString:@"iPad2,4"]) return @"iPad 2";
if ([platform isEqualToString:@"iPad2,5"]) return @"iPad Mini (WiFi)";
if ([platform isEqualToString:@"iPad2,6"]) return @"iPad Mini";
if ([platform isEqualToString:@"iPad2,7"]) return @"iPad Mini (GSM+CDMA)";
if ([platform isEqualToString:@"iPad3,1"]) return @"iPad 3 (WiFi)";
if ([platform isEqualToString:@"iPad3,2"]) return @"iPad 3 (GSM+CDMA)";
if ([platform isEqualToString:@"iPad3,3"]) return @"iPad 3";
if ([platform isEqualToString:@"iPad3,4"]) return @"iPad 4 (WiFi)";
if ([platform isEqualToString:@"iPad3,5"]) return @"iPad 4";
if ([platform isEqualToString:@"iPad3,6"]) return @"iPad 4 (GSM+CDMA)";
if ([platform isEqualToString:@"i386"]) return @"Simulator";
if ([platform isEqualToString:@"x86_64"]) return @"Simulator";
return platform;
}
要识别iPhone 4S,只需检查以下内容:
var isIphone4S: Bool {
let width = UIScreen.main.bounds.size.width
let height = UIScreen.main.bounds.size.height
let proportions = width > height ? width / height : height / width
return proportions == 1.5 && UIDevice.current.model == "iPhone"
}
推荐文章
- 如何更改导航栏上“后退”按钮的标题
- 有没有办法从UITableView中移除分隔线?
- 如何在Objective-C中声明类级属性?
- 我如何获得iOS 7默认的蓝色编程?
- UITapGestureRecognizer破坏UITableView didSelectRowAtIndexPath
- 在Objective-C中@property保留,赋值,复制,非原子
- 6.5英寸屏幕的App store截图大小是多少?
- 我如何在NSAttributedString中创建一个可点击的链接?
- iOS测试/规格TDD/BDD以及集成和验收测试
- 停止UIWebView垂直“弹跳”?
- 启动屏幕故事板不显示图像
- 对未渲染的视图进行快照,结果是一个空快照
- 是否可以为iPhone应用程序(如YouTube和地图)注册一个基于http+域的URL方案?
- 模拟器错误fbssystemservicdomain代码4
- 开始使用instancetype而不是id是否有益?