我有一个Python命令行程序,需要一段时间才能完成。我想知道完成跑步所需的确切时间。

我看过timeit模块,但它似乎只适用于小代码片段。我想给整个节目计时。


当前回答

对于函数,我建议使用我创建的这个简单的修饰符。

def timeit(method):
    def timed(*args, **kwargs):
        ts = time.time()
        result = method(*args, **kwargs)
        te = time.time()
        if 'log_time' in kwargs:
            name = kwargs.get('log_name', method.__name__.upper())
            kwargs['log_time'][name] = int((te - ts) * 1000)
        else:
            print('%r  %2.22f ms' % (method.__name__, (te - ts) * 1000))
        return result
    return timed

@timeit
def foo():
    do_some_work()

# foo()
# 'foo'  0.000953 ms

其他回答

我认为这是最好和最简单的方法:

from time import monotonic

start_time = monotonic()
# something
print(f"Run time {monotonic() - start_time} seconds")

或与装饰师一起:

from time import monotonic
    
def record_time(function):
    def wrap(*args, **kwargs):
        start_time = monotonic()
        function_return = function(*args, **kwargs)
        print(f"Run time {monotonic() - start_time} seconds")
        return function_return
    return wrap

@record_time
def your_function():
    # something

time.clock在Python 3.3中已被弃用,并将从Python 3.8中删除:请改用time.perf_counter或time.prrocess_time

import time
start_time = time.perf_counter ()
for x in range(1, 100):
    print(x)
end_time = time.perf_counter ()
print(end_time - start_time, "seconds")

使用line_profiler。

line_profiler将描述单个代码行执行所需的时间。分析器通过Cython在C语言中实现,以减少分析开销。

from line_profiler import LineProfiler
import random

def do_stuff(numbers):
    s = sum(numbers)
    l = [numbers[i]/43 for i in range(len(numbers))]
    m = ['hello'+str(numbers[i]) for i in range(len(numbers))]

numbers = [random.randint(1,100) for i in range(1000)]
lp = LineProfiler()
lp_wrapper = lp(do_stuff)
lp_wrapper(numbers)
lp.print_stats()

结果将是:

Timer unit: 1e-06 s

Total time: 0.000649 s
File: <ipython-input-2-2e060b054fea>
Function: do_stuff at line 4

Line #      Hits         Time  Per Hit   % Time  Line Contents
==============================================================
     4                                           def do_stuff(numbers):
     5         1           10     10.0      1.5      s = sum(numbers)
     6         1          186    186.0     28.7      l = [numbers[i]/43 for i in range(len(numbers))]
     7         1          453    453.0     69.8      m = ['hello'+str(numbers[i]) for i in range(len(numbers))]

默认情况下,Linux或Unix系统(在macOS上测试)在终端上附带时间命令,您可以使用该命令运行Python脚本,并获取执行运行脚本的真实用户系统时间信息。

然而,默认输出不是很清楚(至少对我来说是这样),默认时间命令甚至不接受任何选项作为参数来格式化输出。这是因为time有两个版本——一个内置在bash中,只提供最小版本,另一个位于/usr/bin/time上。

/usr/bin/time命令接受其他参数,如-al、-h、-p和-o。我最喜欢的是-p,它在新行中显示输出,如下所示:

real 2.18
user 17.92
sys 2.71

根据这个答案,创建了一个简单但方便的工具。

import time
from datetime import timedelta

def start_time_measure(message=None):
    if message:
        print(message)
    return time.monotonic()

def end_time_measure(start_time, print_prefix=None):
    end_time = time.monotonic()
    if print_prefix:
        print(print_prefix + str(timedelta(seconds=end_time - start_time)))
    return end_time

用法:

total_start_time = start_time_measure()    
start_time = start_time_measure('Doing something...')
# Do something
end_time_measure(start_time, 'Done in: ')
start_time = start_time_measure('Doing something else...')
# Do something else
end_time_measure(start_time, 'Done in: ')
end_time_measure(total_start_time, 'Total time: ')

输出:

Doing something...
Done in: 0:00:01.218000
Doing something else...
Done in: 0:00:01.313000
Total time: 0:00:02.672000