是否有一种方法可以在JavaScript中返回两个数组之间的差异?
例如:
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
// need ["c", "d"]
是否有一种方法可以在JavaScript中返回两个数组之间的差异?
例如:
var a1 = ['a', 'b'];
var a2 = ['a', 'b', 'c', 'd'];
// need ["c", "d"]
当前回答
我同意@luis-sieira的解决方案
我创建了位自解释函数,便于初学者一步一步理解:
function difference(oneArr, twoArr){
var newArr = [];
newArr = oneArr.filter((item)=>{
return !twoArr.includes(item)
});
console.log(newArr)
let arr = twoArr.filter((item)=>{
return !oneArr.includes(item)
});
newArr = newArr.concat(arr);
console.log(newArr)
}
difference([1, 2, 3, 5], [1, 2, 3, 4, 5])
其他回答
数据:
var new_storage = JSON.parse('[{"id_order":"0003"},{"id_order":"0004"},{"id_order":"0006"}]');
var old_storage = JSON.parse('[{"id_order":"0001"},{"id_order":"0002"},{"id_order":"0003"},{"id_order":"0004"},{"id_order":"0005"}]');
使用过滤器:
var diff = new_storage
.filter(x => {if(!(old_storage.filter(y => y.id_order==x.id_order)).length){return x}})
.concat(old_storage
.filter(x => {if(!(new_storage.filter(y => y.id_order==x.id_order)).length){return x}})
)
console.log(JSON.stringify(diff))
两个数组的结果不同
[{"id_order":"0006"},{"id_order":"0001"},{"id_order":"0002"},{"id_order":"0005"}]
var result = [];
var arr1 = [1,2,3,4];
var arr2 = [2,3];
arr1.forEach(function(el, idx) {
function unEqual(element, index, array) {
var a = el;
return (element!=a);
}
if (arr2.every(unEqual)) {
result.push(el);
};
});
alert(result);
以下是我使用的方法:
var newArr = a1.filter(function(elem) {
return a2.indexOf(elem) === -1;
}).concat( a2.filter(function(elem) {
return a1.indexOf(elem) === -1;
}));
console.log(newArr);
或者这个
var newArr = a1.concat(a2);
function check(item) {
if (a1.indexOf(item) === -1 || a2.indexOf(item) === -1) {
return item;
}
}
return newArr.filter(check);
如果不使用hasOwnProperty,那么我们有不正确的元素。例如:
[1,2,3].diff([1,2]); //Return ["3", "remove", "diff"] This is the wrong version
我的版本:
Array.prototype.diff = function(array2)
{
var a = [],
diff = [],
array1 = this || [];
for (var i = 0; i < array1.length; i++) {
a[array1[i]] = true;
}
for (var i = 0; i < array2.length; i++) {
if (a[array2[i]]) {
delete a[array2[i]];
} else {
a[array2[i]] = true;
}
}
for (var k in a) {
if (!a.hasOwnProperty(k)){
continue;
}
diff.push(k);
}
return diff;
}
我已经尝试了以上所有这些,但没有一个工作时,你需要匹配不接受副本。
例如:
var a1 = [1, 2, 1, 4], a2 = [1, 2, 4];
会返回一个空的diff数组,因为2会在第二个数组中被找到一次,即使我们需要它匹配两次。
所以我设法解决了一些问题:
Array.prototype.diff = function(a) {
return this.filter(function(item) {
match = a.indexOf(item);
if (match)
a.splice(match, 1);
return match < 0;
});
};