让我们说我有一个Javascript数组看起来如下:
["Element 1","Element 2","Element 3",...]; // with close to a hundred elements.
什么样的方法适合将数组分成许多更小的数组,假设最多有10个元素?
让我们说我有一个Javascript数组看起来如下:
["Element 1","Element 2","Element 3",...]; // with close to a hundred elements.
什么样的方法适合将数组分成许多更小的数组,假设最多有10个元素?
当前回答
in coffeescript:
b = (a.splice(0, len) while a.length)
demo
a = [1, 2, 3, 4, 5, 6, 7]
b = (a.splice(0, 2) while a.length)
[ [ 1, 2 ],
[ 3, 4 ],
[ 5, 6 ],
[ 7 ] ]
其他回答
这是我使用的,它可能不是超级快,但它是紧凑和简单:
让chunksplit = (stream, size) => stream。Reduce ((chunk, item, idx, arr) => (idx % size == 0) ?[…块,加勒比海盗。Slice (idx, idx + size)]: chunk, []); //如果索引是chunksize的倍数,则添加新数组 让testArray =[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12日,13日,14日,15日,16日,17日,18日,19日,20日,21日,22日); document . write (JSON。stringify(chunksplit(testArray, 5)); / /使用JSON。要显示的嵌套数组的Stringify
下面的ES2015方法不需要定义函数,直接在匿名数组上工作(例如块大小为2):
[11,22,33,44,55].map((_, i, all) => all.slice(2*i, 2*i+2)).filter(x=>x.length)
如果你想为此定义一个函数,你可以这样做(改进K._对Blazemonger的回答的评论):
const array_chunks = (array, chunk_size) => array
.map((_, i, all) => all.slice(i*chunk_size, (i+1)*chunk_size))
.filter(x => x.length)
整洁干净,易于理解
let nums = [1, 2, 3, 4, 5, 6, 7, 8, 9];
let len = nums.length ;
const chunkArr = (arr, chunkNo) => {
let newArr = [];
for(let i = 0; i < len; i++){
if(nums[0] !== "" && nums[0] !== undefined ){
let a = nums.splice(0,chunkNo) ;
newArr.push(a);
}
}
return newArr ;
}
console.log(chunkArr(nums, 5));
一个有效的解决方案是通过indexChunk将解决方案与slice和push连接起来,解决方案被分割成块:
function splitChunks(sourceArray, chunkSize) { if(chunkSize <= 0) throw "chunkSize must be greater than 0"; let result = []; for (var i = 0; i < sourceArray.length; i += chunkSize) { result[i / chunkSize] = sourceArray.slice(i, i + chunkSize); } return result; } let ar1 = [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20 ]; console.log("Split in chunks with 4 size", splitChunks(ar1, 4)); console.log("Split in chunks with 7 size", splitChunks(ar1, 7));
这是一个带有尾递归和数组解构的版本。
远非最快的性能,但我只是觉得好笑,js现在可以做到这一点。即使它没有为此进行优化:(
const getChunks = (arr, chunk_size, acc = []) => {
if (arr.length === 0) { return acc }
const [hd, tl] = [ arr.slice(0, chunk_size), arr.slice(chunk_size) ]
return getChunks(tl, chunk_size, acc.concat([hd]))
}
// USAGE
const my_arr = [1,2,3,4,5,6,7,8,9]
const chunks = getChunks(my_arr, 2)
console.log(chunks) // [[1,2],[3,4], [5,6], [7,8], [9]]