如何改变这个输入(顺序:时间，输入，输出，文件):
Time In Out Files
1 2 3 4
2 3 4 5
到这个输出(序列:时间，输出，输入，文件)?
Time Out In Files
1 3 2 4
2 4 3 5
这是虚拟R数据:
table <- data.frame(Time=c(1,2), In=c(2,3), Out=c(3,4), Files=c(4,5))
table
## Time In Out Files
##1 1 2 3 4
##2 2 3 4 5
当前回答
# reorder by column name
data <- data[, c("A", "B", "C")] # leave the row index blank to keep all rows
#reorder by column index
data <- data[, c(1,3,2)] # leave the row index blank to keep all rows
其他回答
你的数据帧有四列，比如df[，c(1,2,3,4)]。 注意，第一个逗号表示保留所有行，1、2、3、4表示列。
要像上面的问题一样改变顺序，请执行df2[，c(1,3,2,4)]
如果你想以csv格式输出这个文件，请执行write.csv(df2, file="somedf.csv")
Dplyr 1.0.0版本包含了relocate()函数来轻松地重新排序列:
dat <- data.frame(Time=c(1,2), In=c(2,3), Out=c(3,4), Files=c(4,5))
library(dplyr) # from version 1.0.0 only
dat %>%
relocate(Out, .before = In)
or
dat %>%
relocate(Out, .after = Time)
# reorder by column name
data <- data[, c("A", "B", "C")] # leave the row index blank to keep all rows
#reorder by column index
data <- data[, c(1,3,2)] # leave the row index blank to keep all rows
你可以使用数据。表包:
如何重新排序数据。表列(不复制)
require(data.table)
setcolorder(DT,myOrder)
我唯一见过的效果不错的就是这里。
shuffle_columns <- function (invec, movecommand) {
movecommand <- lapply(strsplit(strsplit(movecommand, ";")[[1]],
",|\\s+"), function(x) x[x != ""])
movelist <- lapply(movecommand, function(x) {
Where <- x[which(x %in% c("before", "after", "first",
"last")):length(x)]
ToMove <- setdiff(x, Where)
list(ToMove, Where)
})
myVec <- invec
for (i in seq_along(movelist)) {
temp <- setdiff(myVec, movelist[[i]][[1]])
A <- movelist[[i]][[2]][1]
if (A %in% c("before", "after")) {
ba <- movelist[[i]][[2]][2]
if (A == "before") {
after <- match(ba, temp) - 1
}
else if (A == "after") {
after <- match(ba, temp)
}
}
else if (A == "first") {
after <- 0
}
else if (A == "last") {
after <- length(myVec)
}
myVec <- append(temp, values = movelist[[i]][[1]], after = after)
}
myVec
}
像这样使用:
new_df <- iris[shuffle_columns(names(iris), "Sepal.Width before Sepal.Length")]
效果非常好。
