在思考方面，这可能被称为反转。你会发现世界是圆的而不是平的。“你真的不需要知道角色的索引来处理它。”作为一名C程序员，我发现这也很难接受! 你的行“let index = letters.characters.indexOf("c")!”本身就足够了。 例如，要去掉c，你可以用…(操场粘贴)

    var letters = "abcdefg"
  //let index = letters.rangeOfString("c")!.startIndex //is the same as
    let index = letters.characters.indexOf("c")!
    range = letters.characters.indexOf("c")!...letters.characters.indexOf("c")!
    letters.removeRange(range)
    letters

然而，如果你想要一个索引，你需要返回一个实际的index而不是Int值，因为Int值对于任何实际使用都需要额外的步骤。这些扩展返回一个索引，一个特定字符的计数，以及这个游乐场插件代码将演示的范围。

extension String
{
    public func firstIndexOfCharacter(aCharacter: Character) -> String.CharacterView.Index? {

        for index in self.characters.indices {
            if self[index] == aCharacter {
                return index
            }

        }
        return nil
    }

    public func returnCountOfThisCharacterInString(aCharacter: Character) -> Int? {

        var count = 0
        for letters in self.characters{

            if aCharacter == letters{

                count++
            }
        }
        return count
    }


    public func rangeToCharacterFromStart(aCharacter: Character) -> Range<Index>? {

        for index in self.characters.indices {
            if self[index] == aCharacter {
                let range = self.startIndex...index
                return range
            }

        }
        return nil
    }

}



var MyLittleString = "MyVery:important String"

var theIndex = MyLittleString.firstIndexOfCharacter(":")

var countOfColons = MyLittleString.returnCountOfThisCharacterInString(":")

var theCharacterAtIndex:Character = MyLittleString[theIndex!]

var theRange = MyLittleString.rangeToCharacterFromStart(":")
MyLittleString.removeRange(theRange!)

在我看来，了解逻辑本身的更好方法是下面

 let testStr: String = "I love my family if you Love us to tell us I'm with you"
 var newStr = ""
 let char:Character = "i"

 for value in testStr {
      if value == char {
         newStr = newStr + String(value)
   }

}
print(newStr.count)

extension String {

    // MARK: - sub String
    func substringToIndex(index:Int) -> String {
        return self.substringToIndex(advance(self.startIndex, index))
    }
    func substringFromIndex(index:Int) -> String {
        return self.substringFromIndex(advance(self.startIndex, index))
    }
    func substringWithRange(range:Range<Int>) -> String {
        let start = advance(self.startIndex, range.startIndex)
        let end = advance(self.startIndex, range.endIndex)
        return self.substringWithRange(start..<end)
    }

    subscript(index:Int) -> Character{
        return self[advance(self.startIndex, index)]
    }
    subscript(range:Range<Int>) -> String {
        let start = advance(self.startIndex, range.startIndex)
            let end = advance(self.startIndex, range.endIndex)
            return self[start..<end]
    }


    // MARK: - replace
    func replaceCharactersInRange(range:Range<Int>, withString: String!) -> String {
        var result:NSMutableString = NSMutableString(string: self)
        result.replaceCharactersInRange(NSRange(range), withString: withString)
        return result
    }
}

String是NSString的桥接类型，add

import Cocoa

到你的swift文件，并使用所有“旧”的方法。

在Swift 2.0中，下面的函数在给定字符之前返回一个子字符串。

func substring(before sub: String) -> String {
    if let range = self.rangeOfString(sub),
        let index: Int = self.startIndex.distanceTo(range.startIndex) {
        return sub_range(0, index)
    }
    return ""
}

最简单的方法是:

在Swift 3中:

 var textViewString:String = "HelloWorld2016"
    guard let index = textViewString.characters.index(of: "W") else { return }
    let mentionPosition = textViewString.distance(from: index, to: textViewString.endIndex)
    print(mentionPosition)