是时候承认失败了……
在Objective-C中，我可以使用如下内容:
NSString* str = @"abcdefghi";
[str rangeOfString:@"c"].location; // 2
在Swift中，我看到了类似的东西:
var str = "abcdefghi"
str.rangeOfString("c").startIndex
.．.但这只是给了我一个字符串。索引，我可以使用它下标回原始字符串，但不能从中提取位置。
FWIW，字符串。Index有一个名为_position的私有ivar，其中有正确的值。我只是不明白怎么会暴露出来。
我知道我自己可以很容易地将其添加到String中。我更好奇在这个新的API中我缺少了什么。
当前回答
extension String{
func contains(find: String)->Bool{
return self.range(of: find) != nil
}
}
func check(n:String, h:String)->Int{
let n1 = n.lowercased()
let h1 = h.lowercased()//lowercase to make string case insensitive
var pos = 0 //postion of substring
if h1.contains(n1){
// checking if sub string exists
if let idx = h1.firstIndex(of:n1.first!){
let pos1 = h1.distance(from: h1.startIndex, to: idx)
pos = pos1
}
return pos
}
else{
return -1
}
}
print(check(n:"@", h:"hithisispushker,he is 99 a good Boy"))//put substring in n: and string in h
其他回答
Swift 3.0让这个更加冗长:
let string = "Hello.World"
let needle: Character = "."
if let idx = string.characters.index(of: needle) {
let pos = string.characters.distance(from: string.startIndex, to: idx)
print("Found \(needle) at position \(pos)")
}
else {
print("Not found")
}
扩展:
extension String {
public func index(of char: Character) -> Int? {
if let idx = characters.index(of: char) {
return characters.distance(from: startIndex, to: idx)
}
return nil
}
}
在Swift 2.0中，这变得更加容易:
let string = "Hello.World"
let needle: Character = "."
if let idx = string.characters.indexOf(needle) {
let pos = string.startIndex.distanceTo(idx)
print("Found \(needle) at position \(pos)")
}
else {
print("Not found")
}
扩展:
extension String {
public func indexOfCharacter(char: Character) -> Int? {
if let idx = self.characters.indexOf(char) {
return self.startIndex.distanceTo(idx)
}
return nil
}
}
斯威夫特1。x实现:
对于纯Swift解决方案，可以使用:
let string = "Hello.World"
let needle: Character = "."
if let idx = find(string, needle) {
let pos = distance(string.startIndex, idx)
println("Found \(needle) at position \(pos)")
}
else {
println("Not found")
}
作为String的扩展:
extension String {
public func indexOfCharacter(char: Character) -> Int? {
if let idx = find(self, char) {
return distance(self.startIndex, idx)
}
return nil
}
}
斯威夫特5.0
public extension String {
func indexInt(of char: Character) -> Int? {
return firstIndex(of: char)?.utf16Offset(in: self)
}
}
斯威夫特4.0
public extension String {
func indexInt(of char: Character) -> Int? {
return index(of: char)?.encodedOffset
}
}
在swift 2.0中
var stringMe="Something In this.World"
var needle="."
if let idx = stringMe.characters.indexOf(needle) {
let pos=stringMe.substringFromIndex(idx)
print("Found \(needle) at position \(pos)")
}
else {
print("Not found")
}
如果您正在寻找简单的方法来获得字符或字符串的索引，请检查这个库http://www.dollarswift.org/#indexof-char-character-int
您也可以使用另一个字符串或正则表达式模式从字符串中获取indexOf
在Swift 2.0中，下面的函数在给定字符之前返回一个子字符串。
func substring(before sub: String) -> String {
if let range = self.rangeOfString(sub),
let index: Int = self.startIndex.distanceTo(range.startIndex) {
return sub_range(0, index)
}
return ""
}
