extension String{
    func contains(find: String)->Bool{
        return self.range(of: find) != nil
    }
}
 
func check(n:String, h:String)->Int{
    let n1 = n.lowercased()
    let h1 = h.lowercased()//lowercase to make string case insensitive
    var pos = 0 //postion of substring
    if h1.contains(n1){
       // checking if sub string exists
        if let idx = h1.firstIndex(of:n1.first!){
             let pos1 = h1.distance(from: h1.startIndex, to: idx)
           pos = pos1
        }
        return pos
    }
    else{
        return -1
    }
}
 
print(check(n:"@", h:"hithisispushker,he is 99 a good Boy"))//put substring in n: and string in h

这对我很有效，

var loc = "abcdefghi".rangeOfString("c").location
NSLog("%d", loc);

这也奏效了，

var myRange: NSRange = "abcdefghi".rangeOfString("c")
var loc = myRange.location
NSLog("%d", loc);

最简单的方法是:

在Swift 3中:

 var textViewString:String = "HelloWorld2016"
    guard let index = textViewString.characters.index(of: "W") else { return }
    let mentionPosition = textViewString.distance(from: index, to: textViewString.endIndex)
    print(mentionPosition)

如果你只需要一个字符的索引，最简单，快速的解决方案(正如Pascal已经指出的那样)是:

let index = string.characters.index(of: ".")
let intIndex = string.distance(from: string.startIndex, to: index)

Swift 3.0让这个更加冗长:

let string = "Hello.World"
let needle: Character = "."
if let idx = string.characters.index(of: needle) {
    let pos = string.characters.distance(from: string.startIndex, to: idx)
    print("Found \(needle) at position \(pos)")
}
else {
    print("Not found")
}

扩展:

extension String {
    public func index(of char: Character) -> Int? {
        if let idx = characters.index(of: char) {
            return characters.distance(from: startIndex, to: idx)
        }
        return nil
    }
}

在Swift 2.0中，这变得更加容易:

let string = "Hello.World"
let needle: Character = "."
if let idx = string.characters.indexOf(needle) {
    let pos = string.startIndex.distanceTo(idx)
    print("Found \(needle) at position \(pos)")
}
else {
    print("Not found")
}

扩展:

extension String {
    public func indexOfCharacter(char: Character) -> Int? {
        if let idx = self.characters.indexOf(char) {
            return self.startIndex.distanceTo(idx)
        }
        return nil
    }
}

斯威夫特1。x实现:

对于纯Swift解决方案，可以使用:

let string = "Hello.World"
let needle: Character = "."
if let idx = find(string, needle) {
    let pos = distance(string.startIndex, idx)
    println("Found \(needle) at position \(pos)")
}
else {
    println("Not found")
}

作为String的扩展:

extension String {
    public func indexOfCharacter(char: Character) -> Int? {
        if let idx = find(self, char) {
            return distance(self.startIndex, idx)
        }
        return nil
    }
}

    // Using Swift 4, the code below works.
    // The problem is that String.index is a struct. Use dot notation to grab the integer part of it that you want: ".encodedOffset"
    let strx = "0123456789ABCDEF"
    let si = strx.index(of: "A")
    let i = si?.encodedOffset       // i will be an Int. You need "?" because it might be nil, no such character found.

    if i != nil {                   // You MUST deal with the optional, unwrap it only if not nil.
        print("i = ",i)
        print("i = ",i!)            // "!" str1ps off "optional" specification (unwraps i).
            // or
        let ii = i!
        print("ii = ",ii)

    }
    // Good luck.