两个对象。assign和Object spread只做浅合并。

这个问题的一个例子:

// No object nesting
const x = { a: 1 }
const y = { b: 1 }
const z = { ...x, ...y } // { a: 1, b: 1 }

输出是您所期望的。然而,如果我尝试这样做:

// Object nesting
const x = { a: { a: 1 } }
const y = { a: { b: 1 } }
const z = { ...x, ...y } // { a: { b: 1 } }

而不是

{ a: { a: 1, b: 1 } }

你得到

{ a: { b: 1 } }

X被完全覆盖,因为扩展语法只覆盖了一层。这与Object.assign()相同。

有办法做到这一点吗?


当前回答

https://lodash.com/docs/4.17.15#defaultsDeep

注意:此方法会使源发生突变。

_.defaultsDeep({ 'a': { 'b': 2 } }, { 'a': { 'b': 1, 'c': 3 } });
// => { 'a': { 'b': 2, 'c': 3 } }

其他回答

有一个lodash包专门处理对象的深度克隆。这样做的好处是不需要包含整个lodash库。

它叫lodash.clonedeep

在nodejs中,这种用法是这样的

var cloneDeep = require('lodash.clonedeep');
 
const newObject = cloneDeep(oldObject);

在ReactJS中,用法是

import cloneDeep from 'lodash/cloneDeep';

const newObject = cloneDeep(oldObject);

查看这里的文档。如果您对它的工作原理感兴趣,请查看这里的源文件

这里是@Salakar的答案的一个不可变(不修改输入)版本。如果你在做函数式编程,这很有用。

export function isObject(item) {
  return (item && typeof item === 'object' && !Array.isArray(item));
}

export default function mergeDeep(target, source) {
  let output = Object.assign({}, target);
  if (isObject(target) && isObject(source)) {
    Object.keys(source).forEach(key => {
      if (isObject(source[key])) {
        if (!(key in target))
          Object.assign(output, { [key]: source[key] });
        else
          output[key] = mergeDeep(target[key], source[key]);
      } else {
        Object.assign(output, { [key]: source[key] });
      }
    });
  }
  return output;
}

如果您想合并多个普通对象(不要修改输入对象)。基于对象。分配polyfill

function isPlainObject(a) { return (!!a) && (a.constructor === Object); } function merge(target) { let to = Object.assign({}, target); for (let index = 1; index < arguments.length; index++) { let nextSource = arguments[index]; if (nextSource !== null && nextSource !== undefined) { for (let nextKey in nextSource) { // Avoid bugs when hasOwnProperty is shadowed if (Object.prototype.hasOwnProperty.call(nextSource, nextKey)) { if (isPlainObject(to[nextKey]) && isPlainObject(nextSource[nextKey])) { to[nextKey] = merge(to[nextKey], nextSource[nextKey]); } else { to[nextKey] = nextSource[nextKey]; } } } } } return to; } // Usage var obj1 = { a: 1, b: { x: 2, y: { t: 3, u: 4 } }, c: "hi" }; var obj2 = { b: { x: 200, y: { u: 4000, v: 5000 } } }; var obj3 = { c: "hello" }; console.log("result", merge(obj1, obj2, obj3)); console.log("obj1", obj1); console.log("obj2", obj2); console.log("obj3", obj3);

如果你想合并有限的深度

function isPlainObject(a) { return (!!a) && (a.constructor === Object); } function merge(target) { let to = Object.assign({}, target); const hasDepth = arguments.length > 2 && typeof arguments[arguments.length - 1] === 'number'; const depth = hasDepth ? arguments[arguments.length - 1] : Infinity; const lastObjectIndex = hasDepth ? arguments.length - 2 : arguments.length - 1; for (let index = 1; index <= lastObjectIndex; index++) { let nextSource = arguments[index]; if (nextSource !== null && nextSource !== undefined) { for (let nextKey in nextSource) { // Avoid bugs when hasOwnProperty is shadowed if (Object.prototype.hasOwnProperty.call(nextSource, nextKey)) { if (depth > 0 && isPlainObject(to[nextKey]) && isPlainObject(nextSource[nextKey])) { to[nextKey] = merge(to[nextKey], nextSource[nextKey], depth - 1); } else { to[nextKey] = nextSource[nextKey]; } } } } } return to; } // Usage var obj1 = { a: 1, b: { x: 2, y: { t: 3, u: 4, z: {zzz: 100} } }, c: "hi" }; var obj2 = { b: { y: { u: 4000, v: 5000, z: {} } } }; var obj3 = { c: "hello" }; console.log('deep 0', merge(obj1, obj2, obj3, 0)); console.log('deep 1', merge(obj1, obj2, obj3, 1)); console.log('deep 2', merge(obj1, obj2, obj3, 2)); console.log('deep 2', merge(obj1, obj2, obj3, 4));

Ramda是一个很好的javascript函数库,它有mergeDeepLeft和mergeDeepRight。这些方法都能解决这个问题。请在这里查看文档:https://ramdajs.com/docs/#mergeDeepLeft

对于问题中的具体例子,我们可以使用:

import { mergeDeepLeft } from 'ramda'
const x = { a: { a: 1 } }
const y = { a: { b: 1 } }
const z = mergeDeepLeft(x, y)) // {"a":{"a":1,"b":1}}

这是一个廉价的深度合并,使用尽可能少的代码我能想到。当前一个属性存在时,每个源都会覆盖它。

const { keys } = Object;

const isObject = a => typeof a === "object" && !Array.isArray(a);
const merge = (a, b) =>
  isObject(a) && isObject(b)
    ? deepMerge(a, b)
    : isObject(a) && !isObject(b)
    ? a
    : b;

const coalesceByKey = source => (acc, key) =>
  (acc[key] && source[key]
    ? (acc[key] = merge(acc[key], source[key]))
    : (acc[key] = source[key])) && acc;

/**
 * Merge all sources into the target
 * overwriting primitive values in the the accumulated target as we go (if they already exist)
 * @param {*} target
 * @param  {...any} sources
 */
const deepMerge = (target, ...sources) =>
  sources.reduce(
    (acc, source) => keys(source).reduce(coalesceByKey(source), acc),
    target
  );

console.log(deepMerge({ a: 1 }, { a: 2 }));
console.log(deepMerge({ a: 1 }, { a: { b: 2 } }));
console.log(deepMerge({ a: { b: 2 } }, { a: 1 }));