当我们网站上的用户丢失密码并转到丢失密码页面时,我们需要给他一个新的临时密码。我并不介意这有多随机,或者它是否符合所有“所需的”强密码规则,我想做的只是给他们一个他们以后可以更改的密码。
该应用程序是用c#编写的Web应用程序。所以我想刻薄一点,走一条简单的路线,用Guid的一部分。即。
Guid.NewGuid().ToString("d").Substring(1,8)
Suggesstions吗?想法吗?
当我们网站上的用户丢失密码并转到丢失密码页面时,我们需要给他一个新的临时密码。我并不介意这有多随机,或者它是否符合所有“所需的”强密码规则,我想做的只是给他们一个他们以后可以更改的密码。
该应用程序是用c#编写的Web应用程序。所以我想刻薄一点,走一条简单的路线,用Guid的一部分。即。
Guid.NewGuid().ToString("d").Substring(1,8)
Suggesstions吗?想法吗?
当前回答
public string Sifre_Uret(int boy, int noalfa)
{
// 01.03.2016
// Genel amaçlı şifre üretme fonksiyonu
//Fonskiyon 128 den büyük olmasına izin vermiyor.
if (boy > 128 ) { boy = 128; }
if (noalfa > 128) { noalfa = 128; }
if (noalfa > boy) { noalfa = boy; }
string passch = System.Web.Security.Membership.GeneratePassword(boy, noalfa);
//URL encoding ve Url Pass + json sorunu yaratabilecekler pass ediliyor.
//Microsoft Garanti etmiyor. Alfa Sayısallar Olabiliyorimiş . !@#$%^&*()_-+=[{]};:<>|./?.
//https://msdn.microsoft.com/tr-tr/library/system.web.security.membership.generatepassword(v=vs.110).aspx
//URL ve Json ajax lar için filtreleme
passch = passch.Replace(":", "z");
passch = passch.Replace(";", "W");
passch = passch.Replace("'", "t");
passch = passch.Replace("\"", "r");
passch = passch.Replace("/", "+");
passch = passch.Replace("\\", "e");
passch = passch.Replace("?", "9");
passch = passch.Replace("&", "8");
passch = passch.Replace("#", "D");
passch = passch.Replace("%", "u");
passch = passch.Replace("=", "4");
passch = passch.Replace("~", "1");
passch = passch.Replace("[", "2");
passch = passch.Replace("]", "3");
passch = passch.Replace("{", "g");
passch = passch.Replace("}", "J");
//passch = passch.Replace("(", "6");
//passch = passch.Replace(")", "0");
//passch = passch.Replace("|", "p");
//passch = passch.Replace("@", "4");
//passch = passch.Replace("!", "u");
//passch = passch.Replace("$", "Z");
//passch = passch.Replace("*", "5");
//passch = passch.Replace("_", "a");
passch = passch.Replace(",", "V");
passch = passch.Replace(".", "N");
passch = passch.Replace("+", "w");
passch = passch.Replace("-", "7");
return passch;
}
其他回答
对于这种类型的密码,我倾向于使用可能生成更容易“使用”的密码的系统。短的,通常由发音片段和一些数字组成,并且没有字符间的歧义(这是0还是O?是1还是I?)类似的
string[] words = { 'bur', 'ler', 'meh', 'ree' };
string word = "";
Random rnd = new Random();
for (i = 0; i < 3; i++)
word += words[rnd.Next(words.length)]
int numbCount = rnd.Next(4);
for (i = 0; i < numbCount; i++)
word += (2 + rnd.Next(7)).ToString();
return word;
(直接在浏览器中输入,因此仅作为参考。同时,要多加单词)。
public string CreatePassword(int length)
{
const string valid = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
StringBuilder res = new StringBuilder();
Random rnd = new Random();
while (0 < length--)
{
res.Append(valid[rnd.Next(valid.Length)]);
}
return res.ToString();
}
这有一个很好的好处,可以从可用的字符列表中选择生成的密码(例如,仅数字,仅大写或仅小写等)。
使用Random和linq-to-objects来要求每个组都有一个很简单的方法。
随机分组 从第一组中选择随机金额 从以下组中选择剩余的随机金额
Random rand = new Random();
int min = 8;
int max = 16;
int totalLen = rand.Next(min, max);
int remainingGroups = 4;
string[] allowedLowerChars = "a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z".Split(',');
string [] allowedUpperChars = "A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z".Split(',');
string [] allowedNumbers = "1,2,3,4,5,6,7,8,9,0".Split(',');
string [] allowedSpecialChars = "!,@,#,$,%,&,?".Split(',');
var password = allowedLowerChars.OrderBy(c => rand.Next()).Take(rand.Next(1, totalLen-remainingGroups--)).ToList();
password.AddRange(allowedUpperChars.OrderBy(c => rand.Next()).Take(rand.Next(1, totalLen-password.Count-remainingGroups--)).ToList());
password.AddRange(allowedNumbers.OrderBy(c => rand.Next()).Take(rand.Next(1, totalLen-password.Count-remainingGroups--)).ToList());
password.AddRange(allowedSpecialChars.OrderBy(c => rand.Next()).Take(totalLen-password.Count).ToList());
password = password.OrderBy(c => rand.Next()).ToList(); // randomize groups
public static string GeneratePassword(int passLength) {
var chars = "abcdefghijklmnopqrstuvwxyz@#$&ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
var random = new Random();
var result = new string(
Enumerable.Repeat(chars, passLength)
.Select(s => s[random.Next(s.Length)])
.ToArray());
return result;
}
这是我快速拼凑的东西。
public string GeneratePassword(int len)
{
string res = "";
Random rnd = new Random();
while (res.Length < len) res += (new Func<Random, string>((r) => {
char c = (char)((r.Next(123) * DateTime.Now.Millisecond % 123));
return (Char.IsLetterOrDigit(c)) ? c.ToString() : "";
}))(rnd);
return res;
}