我正在寻找一种优雅的方式来获得数据使用属性访问字典与一些嵌套的字典和列表(即javascript风格的对象语法)。
例如:
>>> d = {'a': 1, 'b': {'c': 2}, 'd': ["hi", {'foo': "bar"}]}
应该以这样的方式访问:
>>> x = dict2obj(d)
>>> x.a
1
>>> x.b.c
2
>>> x.d[1].foo
bar
我想,如果没有递归,这是不可能的,但是有什么更好的方法来获得字典的对象样式呢?
我正在寻找一种优雅的方式来获得数据使用属性访问字典与一些嵌套的字典和列表(即javascript风格的对象语法)。
例如:
>>> d = {'a': 1, 'b': {'c': 2}, 'd': ["hi", {'foo': "bar"}]}
应该以这样的方式访问:
>>> x = dict2obj(d)
>>> x.a
1
>>> x.b.c
2
>>> x.d[1].foo
bar
我想,如果没有递归,这是不可能的,但是有什么更好的方法来获得字典的对象样式呢?
当前回答
构建我对“python:如何动态地向类添加属性?”:
class data(object):
def __init__(self,*args,**argd):
self.__dict__.update(dict(*args,**argd))
def makedata(d):
d2 = {}
for n in d:
d2[n] = trydata(d[n])
return data(d2)
def trydata(o):
if isinstance(o,dict):
return makedata(o)
elif isinstance(o,list):
return [trydata(i) for i in o]
else:
return o
在要转换的字典上调用makedata,或者根据期望的输入调用trydata,它将输出一个数据对象。
注:
如果需要更多功能,可以向trydata添加elif。 显然,如果你想要x.a ={}或类似的东西,这是行不通的。 如果您想要一个只读版本,请使用原始答案中的类数据。
其他回答
在2021年,使用pydantic BaseModel -将嵌套字典和嵌套json对象转换为python对象,反之亦然:
https://pydantic-docs.helpmanual.io/usage/models/
>>> class Foo(BaseModel):
... count: int
... size: float = None
...
>>>
>>> class Bar(BaseModel):
... apple = 'x'
... banana = 'y'
...
>>>
>>> class Spam(BaseModel):
... foo: Foo
... bars: List[Bar]
...
>>>
>>> m = Spam(foo={'count': 4}, bars=[{'apple': 'x1'}, {'apple': 'x2'}])
对象to dict
>>> print(m.dict())
{'foo': {'count': 4, 'size': None}, 'bars': [{'apple': 'x1', 'banana': 'y'}, {'apple': 'x2', 'banana': 'y'}]}
对象转换为JSON
>>> print(m.json())
{"foo": {"count": 4, "size": null}, "bars": [{"apple": "x1", "banana": "y"}, {"apple": "x2", "banana": "y"}]}
反对的词典
>>> spam = Spam.parse_obj({'foo': {'count': 4, 'size': None}, 'bars': [{'apple': 'x1', 'banana': 'y'}, {'apple': 'x2', 'banana': 'y2'}]})
>>> spam
Spam(foo=Foo(count=4, size=None), bars=[Bar(apple='x1', banana='y'), Bar(apple='x2', banana='y2')])
JSON到对象
>>> spam = Spam.parse_raw('{"foo": {"count": 4, "size": null}, "bars": [{"apple": "x1", "banana": "y"}, {"apple": "x2", "banana": "y"}]}')
>>> spam
Spam(foo=Foo(count=4, size=None), bars=[Bar(apple='x1', banana='y'), Bar(apple='x2', banana='y')])
下面是一个使用namedtuple的嵌套就绪版本:
from collections import namedtuple
class Struct(object):
def __new__(cls, data):
if isinstance(data, dict):
return namedtuple(
'Struct', data.iterkeys()
)(
*(Struct(val) for val in data.values())
)
elif isinstance(data, (tuple, list, set, frozenset)):
return type(data)(Struct(_) for _ in data)
else:
return data
=>
>>> d = {'a': 1, 'b': {'c': 2}, 'd': ["hi", {'foo': "bar"}]}
>>> s = Struct(d)
>>> s.d
['hi', Struct(foo='bar')]
>>> s.d[0]
'hi'
>>> s.d[1].foo
'bar'
有一个 名为namedtuple的集合助手,可以为你做这些:
from collections import namedtuple
d_named = namedtuple('Struct', d.keys())(*d.values())
In [7]: d_named
Out[7]: Struct(a=1, b={'c': 2}, d=['hi', {'foo': 'bar'}])
In [8]: d_named.a
Out[8]: 1
这是另一种将字典列表转换为对象的替代方法:
def dict2object(in_dict):
class Struct(object):
def __init__(self, in_dict):
for key, value in in_dict.items():
if isinstance(value, (list, tuple)):
setattr(
self, key,
[Struct(sub_dict) if isinstance(sub_dict, dict)
else sub_dict for sub_dict in value])
else:
setattr(
self, key,
Struct(value) if isinstance(value, dict)
else value)
return [Struct(sub_dict) for sub_dict in in_dict] \
if isinstance(in_dict, list) else Struct(in_dict)
class Struct(dict):
def __getattr__(self, name):
try:
return self[name]
except KeyError:
raise AttributeError(name)
def __setattr__(self, name, value):
self[name] = value
def copy(self):
return Struct(dict.copy(self))
用法:
points = Struct(x=1, y=2)
# Changing
points['x'] = 2
points.y = 1
# Accessing
points['x'], points.x, points.get('x') # 2 2 2
points['y'], points.y, points.get('y') # 1 1 1
# Accessing inexistent keys/attrs
points['z'] # KeyError: z
points.z # AttributeError: z
# Copying
points_copy = points.copy()
points.x = 2
points_copy.x # 1