新的iPhone 5屏幕有新的纵横比和新的分辨率(640 x 1136像素)。

开发新的应用程序或将现有应用程序转换到新的屏幕尺寸需要什么?

我们应该记住什么,使应用程序“通用”的旧显示器和新的宽屏纵横比?


当前回答

Peter,你真的应该看看Canappi,它为你做了所有这些,你所要做的就是指定这样的布局:

button mySubmitButton 'Sumbit' (100,100,100,30 + 0,88,0,0) { ... }

从那里Canappi将生成正确的objective-c代码,检测应用程序正在运行的设备,并将使用:

(100,100,100,30) for iPhone4
(100,**188**,100,30) for iPhone 5

Canappi的工作原理类似于界面生成器和故事板的结合,除了它是文本形式。如果已经有XIB文件,可以转换它们,这样就不必从头重新创建整个UI。

其他回答

在这里你可以找到一个很好的教程(MonoTouch,但你也可以使用非MonoTouch项目的信息): http://redth.info/get-your-monotouch-apps-ready-for-iphone-5-ios-6-today/

为你的splash/default屏幕创建一个新图像(640 x 1136像素),名称为Default-568h@2x.png 在iOS模拟器中,转到硬件->设备菜单,并选择“iPhone(视网膜4英寸)” 创建其他图像,例如背景图像 检测iPhone 5加载你的新图像:


public static bool IsTall
{
    get {
        return UIDevice.currentDevice.userInterfaceIdiom
                    == UIUserInterfaceIdiomPhone
                && UIScreen.mainScreen.bounds.size.height
                    * UIScreen.mainScreen.scale >= 1136;
    }
}

private static string tallMagic = "-568h@2x";
public static UIImage FromBundle16x9(string path)
{
    //adopt the -568h@2x naming convention
    if(IsTall())
    {
        var imagePath = Path.GetDirectoryName(path.ToString());
        var imageFile = Path.GetFileNameWithoutExtension(path.ToString());
        var imageExt = Path.GetExtension(path.ToString());
        imageFile = imageFile + tallMagic + imageExt;
        return UIImage.FromFile(Path.Combine(imagePath,imageFile));
    }
    else
    {
        return UIImage.FromBundle(path.ToString());
    }
}

唯一真正需要做的事情是在应用程序资源中添加一个名为“Default-568h@2x.png”的启动图像,在一般情况下(如果你足够幸运)应用程序将正常工作。

如果应用程序不处理触摸事件,那么确保键窗口有适当的大小。解决方法是设置适当的框架:

[window setFrame:[[UIScreen mainScreen] bounds]]

在迁移到iOS 6时,还有其他与屏幕大小无关的问题。详情请阅读iOS 6.0发布说明。

I never faced such an issue with any device as I've had one codebase for all, without any hardcoded values. What I do is to have the maximum sized image as resource instead of one for each device. For example, I would have one for retina display and show it as aspect fit so it will be views as is on every device. Coming to deciding the frame of button, for instance, at run time. For this I use the % value of the patent view, example , if I want the width to be half of parent view take 50 % of parent and same applies for height and center.

有了这个,我甚至不需要xib。

首先,创建两个xib并将所有委托,main类附加到xib,然后你可以在你的appdelegate中放入下面提到的条件。M文件在

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions 

    if ([[UIScreen mainScreen] bounds].size.height == 568)
        {

        self.ViewController = [[ViewController alloc] initWithNibName:@"ViewControlleriphone5" bundle:nil];
        }

        else
        {
             self.ViewController = [[ViewController alloc] initWithNibName:@"ViewControlleriphone4" bundle:nil];

        }

你可以在程序的任何地方使用它,这取决于你的需求,甚至在你的ViewController类中。最重要的是,您已经为iphone 4(320*480)和iphone 5(320*568)分别创建了两个xib文件。

在iOS设备和iOS模拟器上测试时,有一个小问题。看起来模拟器(XCode 6.0.1)在[[UIScreen mainScreen] bounds]中给出了宽度和高度的切换值。大小,取决于设备方向。

因此,在确定正确的物理屏幕尺寸时,这可能是一个问题。此代码还有助于区分所有2014年。iPhone型号:

iPhone4s iPhone5(和iPhone5s) iPhone6(及iPhone6+)

它也可以很容易地改变,使区别,如iPhone6从iPhone6+。

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {

    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;

    if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
    {
        if (iOSDeviceScreenSize.width > 568 || // for iOS devices
            iOSDeviceScreenSize.height > 568) // for iOS simulator
        {   // iPhone 6 and iPhone 6+

            // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone6
            storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone6" bundle:nil];

            NSLog(@"loaded iPhone6 Storyboard");
        }
        else if (iOSDeviceScreenSize.width == 568 || // for iOS devices
                 iOSDeviceScreenSize.height == 568) // for iOS simulator
        {   // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)

            // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone5
            storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone5" bundle:nil];

            NSLog(@"loaded iPhone5 Storyboard");
        }
        else
        {   // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)

                // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
            storyboard = [UIStoryboard story    boardWithName:@"MainStoryboard_iPhone" bundle:nil];

                NSLog(@"loaded iPhone4 Storyboard");
        }
    }
    else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)
    {   // The iOS device = iPad

        storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPadnew" bundle:nil];

        NSLog(@"loaded iPad Storyboard");
    }

    // rest my code
}