新的iPhone 5屏幕有新的纵横比和新的分辨率(640 x 1136像素)。

开发新的应用程序或将现有应用程序转换到新的屏幕尺寸需要什么?

我们应该记住什么,使应用程序“通用”的旧显示器和新的宽屏纵横比?


当前回答

I never faced such an issue with any device as I've had one codebase for all, without any hardcoded values. What I do is to have the maximum sized image as resource instead of one for each device. For example, I would have one for retina display and show it as aspect fit so it will be views as is on every device. Coming to deciding the frame of button, for instance, at run time. For this I use the % value of the patent view, example , if I want the width to be half of parent view take 50 % of parent and same applies for height and center.

有了这个,我甚至不需要xib。

其他回答

在constants.h文件中,你可以添加以下定义语句:

 #define IS_IPAD UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad 
 #define IS_IPHONE UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone
 #define IS_WIDESCREEN (fabs((double)[[UIScreen mainScreen] bounds].size.height - (double)568) < DBL_EPSILON) 
 #define IS_IPHONE_5 (!IS_IPAD && IS_WIDESCREEN)

你可以使用这个定义来计算你是否使用基于屏幕大小的iPhone 5:

#define IS_IPHONE_5 ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON )

然后使用简单的if语句:

    if (IS_IPHONE_5) {

    // What ever changes
    }

值得注意的是,在新的Xcode中,你必须将这个图像文件Default-568h@2x.png添加到资产中

在iOS设备和iOS模拟器上测试时,有一个小问题。看起来模拟器(XCode 6.0.1)在[[UIScreen mainScreen] bounds]中给出了宽度和高度的切换值。大小,取决于设备方向。

因此,在确定正确的物理屏幕尺寸时,这可能是一个问题。此代码还有助于区分所有2014年。iPhone型号:

iPhone4s iPhone5(和iPhone5s) iPhone6(及iPhone6+)

它也可以很容易地改变,使区别,如iPhone6从iPhone6+。

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {

    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;

    if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
    {
        if (iOSDeviceScreenSize.width > 568 || // for iOS devices
            iOSDeviceScreenSize.height > 568) // for iOS simulator
        {   // iPhone 6 and iPhone 6+

            // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone6
            storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone6" bundle:nil];

            NSLog(@"loaded iPhone6 Storyboard");
        }
        else if (iOSDeviceScreenSize.width == 568 || // for iOS devices
                 iOSDeviceScreenSize.height == 568) // for iOS simulator
        {   // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)

            // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone5
            storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone5" bundle:nil];

            NSLog(@"loaded iPhone5 Storyboard");
        }
        else
        {   // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)

                // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
            storyboard = [UIStoryboard story    boardWithName:@"MainStoryboard_iPhone" bundle:nil];

                NSLog(@"loaded iPhone4 Storyboard");
        }
    }
    else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)
    {   // The iOS device = iPad

        storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPadnew" bundle:nil];

        NSLog(@"loaded iPad Storyboard");
    }

    // rest my code
}

唯一真正需要做的事情是在应用程序资源中添加一个名为“Default-568h@2x.png”的启动图像,在一般情况下(如果你足够幸运)应用程序将正常工作。

如果应用程序不处理触摸事件,那么确保键窗口有适当的大小。解决方法是设置适当的框架:

[window setFrame:[[UIScreen mainScreen] bounds]]

在迁移到iOS 6时,还有其他与屏幕大小无关的问题。详情请阅读iOS 6.0发布说明。