新的iPhone 5屏幕有新的纵横比和新的分辨率(640 x 1136像素)。

开发新的应用程序或将现有应用程序转换到新的屏幕尺寸需要什么?

我们应该记住什么,使应用程序“通用”的旧显示器和新的宽屏纵横比?


当前回答

首先,创建两个xib并将所有委托,main类附加到xib,然后你可以在你的appdelegate中放入下面提到的条件。M文件在

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions 

    if ([[UIScreen mainScreen] bounds].size.height == 568)
        {

        self.ViewController = [[ViewController alloc] initWithNibName:@"ViewControlleriphone5" bundle:nil];
        }

        else
        {
             self.ViewController = [[ViewController alloc] initWithNibName:@"ViewControlleriphone4" bundle:nil];

        }

你可以在程序的任何地方使用它,这取决于你的需求,甚至在你的ViewController类中。最重要的是,您已经为iphone 4(320*480)和iphone 5(320*568)分别创建了两个xib文件。

其他回答

这是一个真正的通用代码,你可以创建3个不同的故事板:

设置你的项目通用模式,用iPhone5 storyboard设置你的主故事iPhone,用ipad target storyboard设置ipad main,现在为iPhone添加新的storyboard target,并修改iPhone 4s或更少的分辨率,现在实现你的appdelegate。m

iPhone4/4s (3/ 3g是一样的)一个iPhone5,并使项目通用,与一个新的Storyboard目标为iPad,现在在AppDelegate。在didFinishLaunching下添加以下代码:

    if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone){
        UIStoryboard *storyBoard;

        CGSize result = [[UIScreen mainScreen] bounds].size;
        CGFloat scale = [UIScreen mainScreen].scale;
        result = CGSizeMake(result.width *scale, result.height *scale);

//----------------HERE WE SETUP FOR IPHONE4/4s/iPod----------------------

        if(result.height == 960){
            storyBoard = [UIStoryboard storyboardWithName:@"iPhone4_Storyboard" bundle:nil];
            UIViewController *initViewController = [storyBoard instantiateInitialViewController];
            [self.window setRootViewController:initViewController];
        }

//----------------HERE WE SETUP FOR IPHONE3/3s/iPod----------------------

        if(result.height == 480){
            storyBoard = [UIStoryboard storyboardWithName:@"iPhone4_Storyboard" bundle:nil];
            UIViewController *initViewController = [storyBoard instantiateInitialViewController];
            [self.window setRootViewController:initViewController];
        }
    }

        return YES;
 }

所以你已经为iPhone 3/ 3g /4/4s/5所有一代的iPod和所有类型的iPad创建了一个通用应用程序

记住将所有IMG与myImage.png和myImage@2x.png集成

According to me the best way of dealing with such problems and avoiding couple of condition required for checking the the height of device, is using the relative frame for views or any UI element which you are adding to you view for example: if you are adding some UI element which you want should at the bottom of view or just above tab bar then you should take the y origin with respect to your view's height or with respect to tab bar (if present) and we have auto resizing property as well. I hope this will work for you

如果你需要将一个已经存在的应用程序转换为通用,你需要选择相应的xib文件->show Utilities-> show Size inspector。

在大小检查器中,你可以看到自动调整大小,通过使用这个工具你可以转换到现有的iOS应用程序。

我建议在你的应用程序中根据你的UI界面使用自动调整蒙版,这节省了很多麻烦,比为iPhone 4和5屏幕制作不同的UI更好。

在iOS设备和iOS模拟器上测试时,有一个小问题。看起来模拟器(XCode 6.0.1)在[[UIScreen mainScreen] bounds]中给出了宽度和高度的切换值。大小,取决于设备方向。

因此,在确定正确的物理屏幕尺寸时,这可能是一个问题。此代码还有助于区分所有2014年。iPhone型号:

iPhone4s iPhone5(和iPhone5s) iPhone6(及iPhone6+)

它也可以很容易地改变,使区别,如iPhone6从iPhone6+。

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {

    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;

    if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
    {
        if (iOSDeviceScreenSize.width > 568 || // for iOS devices
            iOSDeviceScreenSize.height > 568) // for iOS simulator
        {   // iPhone 6 and iPhone 6+

            // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone6
            storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone6" bundle:nil];

            NSLog(@"loaded iPhone6 Storyboard");
        }
        else if (iOSDeviceScreenSize.width == 568 || // for iOS devices
                 iOSDeviceScreenSize.height == 568) // for iOS simulator
        {   // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)

            // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone5
            storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone5" bundle:nil];

            NSLog(@"loaded iPhone5 Storyboard");
        }
        else
        {   // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)

                // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
            storyboard = [UIStoryboard story    boardWithName:@"MainStoryboard_iPhone" bundle:nil];

                NSLog(@"loaded iPhone4 Storyboard");
        }
    }
    else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)
    {   // The iOS device = iPad

        storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPadnew" bundle:nil];

        NSLog(@"loaded iPad Storyboard");
    }

    // rest my code
}