新的iPhone 5屏幕有新的纵横比和新的分辨率(640 x 1136像素)。
开发新的应用程序或将现有应用程序转换到新的屏幕尺寸需要什么?
我们应该记住什么,使应用程序“通用”的旧显示器和新的宽屏纵横比?
新的iPhone 5屏幕有新的纵横比和新的分辨率(640 x 1136像素)。
开发新的应用程序或将现有应用程序转换到新的屏幕尺寸需要什么?
我们应该记住什么,使应用程序“通用”的旧显示器和新的宽屏纵横比?
当前回答
首先显示这张图片。在那个图像中,你显示了视网膜4支持的警告,所以点击这个警告,然后点击添加,这样你的视网膜4启动屏幕自动添加到你的项目中。
在你使用这段代码之后
if([[UIScreen mainScreen] bounds].size.height == 568)
{
// For iphone 5
}
else
{
// For iphone 4 or less
}
其他回答
According to me the best way of dealing with such problems and avoiding couple of condition required for checking the the height of device, is using the relative frame for views or any UI element which you are adding to you view for example: if you are adding some UI element which you want should at the bottom of view or just above tab bar then you should take the y origin with respect to your view's height or with respect to tab bar (if present) and we have auto resizing property as well. I hope this will work for you
在iOS设备和iOS模拟器上测试时,有一个小问题。看起来模拟器(XCode 6.0.1)在[[UIScreen mainScreen] bounds]中给出了宽度和高度的切换值。大小,取决于设备方向。
因此,在确定正确的物理屏幕尺寸时,这可能是一个问题。此代码还有助于区分所有2014年。iPhone型号:
iPhone4s iPhone5(和iPhone5s) iPhone6(及iPhone6+)
它也可以很容易地改变,使区别,如iPhone6从iPhone6+。
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
{
if (iOSDeviceScreenSize.width > 568 || // for iOS devices
iOSDeviceScreenSize.height > 568) // for iOS simulator
{ // iPhone 6 and iPhone 6+
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone6
storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone6" bundle:nil];
NSLog(@"loaded iPhone6 Storyboard");
}
else if (iOSDeviceScreenSize.width == 568 || // for iOS devices
iOSDeviceScreenSize.height == 568) // for iOS simulator
{ // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone5
storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone5" bundle:nil];
NSLog(@"loaded iPhone5 Storyboard");
}
else
{ // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)
// Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
storyboard = [UIStoryboard story boardWithName:@"MainStoryboard_iPhone" bundle:nil];
NSLog(@"loaded iPhone4 Storyboard");
}
}
else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)
{ // The iOS device = iPad
storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard_iPadnew" bundle:nil];
NSLog(@"loaded iPad Storyboard");
}
// rest my code
}
我添加了新的默认启动图像,(在检查其他几个SE答案…)确保我的故事板都自动大小和子视图,但视网膜4英寸仍然是信箱。
然后我注意到我的信息plist有一个行项目“启动图像”设置为“Default.png”,因此我删除了它,神奇的字母盒不再出现。希望这能让别人免受我所经历的疯狂。
我想,它不是在所有情况下都能工作,但在我的特定项目中,它避免了我对nib文件的重复:
在common.h中,你可以根据屏幕高度来做这些定义:
#define HEIGHT_IPHONE_5 568
#define IS_IPHONE ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone)
#define IS_IPHONE_5 ([[UIScreen mainScreen] bounds ].size.height == HEIGHT_IPHONE_5)
在你的基本控制器中:
- (void)viewDidLoad
{
[super viewDidLoad];
if (IS_IPHONE_5) {
CGRect r = self.view.frame;
r.size.height = HEIGHT_IPHONE_5 - 20;
self.view.frame = r;
}
// now the view is stretched properly and not pushed to the bottom
// it is pushed to the top instead...
// other code goes here...
}
在单例类中尝试下面的方法:
-(NSString *)typeOfDevice
{
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
CGSize result = [[UIScreen mainScreen] bounds].size;
if(result.height == 480)
{
return @"Iphone";
}
if(result.height == 568)
{
return @"Iphone 5";
}
}
else{
return @"Ipad";;
}
return @"Iphone";
}