我必须递归地重命名一个完整的文件夹树,这样就不会出现大写字母(这是c++源代码,但这无关紧要)。

忽略CVS和Subversion版本控制文件/文件夹的加分项。首选的方法是shell脚本,因为shell应该在任何Linux机器上可用。

关于文件重命名的细节有一些有效的争论。

I think files with the same lowercase names should be overwritten; it's the user's problem. When checked out on a case-ignoring file system, it would overwrite the first one with the latter, too. I would consider A-Z characters and transform them to a-z, everything else is just calling for problems (at least with source code). The script would be needed to run a build on a Linux system, so I think changes to CVS or Subversion version control files should be omitted. After all, it's just a scratch checkout. Maybe an "export" is more appropriate.


当前回答

你可以简单地使用下面的简单方法:

rename 'y/A-Z/a-z/' *

其他回答

在OS X中,mv -f显示“same file”错误,所以我重命名两次:

for i in `find . -name "*" -type f |grep -e "[A-Z]"`; do j=`echo $i | tr '[A-Z]' '[a-z]' | sed s/\-1$//`; mv $i $i-1; mv $i-1 $j; done

下面是我的次优解决方案,使用Bash shell脚本:

#!/bin/bash
# First, rename all folders
for f in `find . -depth ! -name CVS -type d`; do
   g=`dirname "$f"`/`basename "$f" | tr '[A-Z]' '[a-z]'`
   if [ "xxx$f" != "xxx$g" ]; then
      echo "Renaming folder $f"
      mv -f "$f" "$g"
   fi
done

# Now, rename all files
for f in `find . ! -type d`; do
   g=`dirname "$f"`/`basename "$f" | tr '[A-Z]' '[a-z]'`
   if [ "xxx$f" != "xxx$g" ]; then
      echo "Renaming file $f"
      mv -f "$f" "$g"
   fi
done

文件夹都正确地重命名,mv在权限不匹配时不会询问问题,CVS文件夹也不会重命名(不幸的是,该文件夹内的CVS控制文件仍然会重命名)。

由于“find -depth”和“find | sort -r”都以可用于重命名的顺序返回文件夹列表,我更喜欢使用“-depth”来搜索文件夹。

如果你已经设置了重命名命令(例如,在Mac中通过brew install),这是有效的:

rename --lower-case --force somedir/*

如果你使用Arch Linux,你可以从AUR安装rename)包,它提供了renamexm命令作为/usr/bin/renamexm可执行文件和一个手册页面。

它是一个非常强大的工具,可以快速重命名文件和目录。

转换为小写字母

rename -l Developers.mp3 # or --lowcase

转换为大写

rename -u developers.mp3 # or --upcase, long option

其他选项

-R --recursive # directory and its children

-t --test # Dry run, output but don't rename

-o --owner # Change file owner as well to user specified

-v --verbose # Output what file is renamed and its new name

-s/str/str2 # Substitute string on pattern

--yes # Confirm all actions

如果需要,您可以从这里获取示例Developers.mp3文件;)

你可以简单地使用下面的简单方法:

rename 'y/A-Z/a-z/' *