我必须递归地重命名一个完整的文件夹树,这样就不会出现大写字母(这是c++源代码,但这无关紧要)。

忽略CVS和Subversion版本控制文件/文件夹的加分项。首选的方法是shell脚本,因为shell应该在任何Linux机器上可用。

关于文件重命名的细节有一些有效的争论。

I think files with the same lowercase names should be overwritten; it's the user's problem. When checked out on a case-ignoring file system, it would overwrite the first one with the latter, too. I would consider A-Z characters and transform them to a-z, everything else is just calling for problems (at least with source code). The script would be needed to run a build on a Linux system, so I think changes to CVS or Subversion version control files should be omitted. After all, it's just a scratch checkout. Maybe an "export" is more appropriate.


当前回答

如果你不需要关心效率,就试试下面的方法。

zip -r foo.zip foo/*
unzip -LL foo.zip

其他回答

使用Larry Wall的文件名修复器:

$op = shift or die $help;
chomp(@ARGV = <STDIN>) unless @ARGV;
for (@ARGV) {
    $was = $_;
    eval $op;
    die $@ if $@;
    rename($was,$_) unless $was eq $_;
}

这很简单

find | fix 'tr/A-Z/a-z/'

(其中fix当然是上面的脚本)

这是一个小的shell脚本,做你所要求的:

root_directory="${1?-please specify parent directory}"
do_it () {
    awk '{ lc= tolower($0); if (lc != $0) print "mv \""  $0 "\" \"" lc "\"" }' | sh
}
# first the folders
find "$root_directory" -depth -type d | do_it
find "$root_directory" ! -type d | do_it

注意第一个find中的-depth动作。

for f in `find`; do mv -v "$f" "`echo $f | tr '[A-Z]' '[a-z]'`"; done

如果你使用Arch Linux,你可以从AUR安装rename)包,它提供了renamexm命令作为/usr/bin/renamexm可执行文件和一个手册页面。

它是一个非常强大的工具,可以快速重命名文件和目录。

转换为小写字母

rename -l Developers.mp3 # or --lowcase

转换为大写

rename -u developers.mp3 # or --upcase, long option

其他选项

-R --recursive # directory and its children

-t --test # Dry run, output but don't rename

-o --owner # Change file owner as well to user specified

-v --verbose # Output what file is renamed and its new name

-s/str/str2 # Substitute string on pattern

--yes # Confirm all actions

如果需要,您可以从这里获取示例Developers.mp3文件;)

这在macOS上也能很好地工作:

ruby -e "Dir['*'].each { |p| File.rename(p, p.downcase) }"