我想测量执行一个函数所花费的时间。我没时间工作:

import timeit
start = timeit.timeit()
print("hello")
end = timeit.timeit()
print(end - start)

当前回答

下面是一个返回“hh:mm:ss”字符串的小型计时器类:

class Timer:
  def __init__(self):
    self.start = time.time()

  def restart(self):
    self.start = time.time()

  def get_time_hhmmss(self):
    end = time.time()
    m, s = divmod(end - self.start, 60)
    h, m = divmod(m, 60)
    time_str = "%02d:%02d:%02d" % (h, m, s)
    return time_str

用法:

# Start timer
my_timer = Timer()

# ... do something

# Get time string:
time_hhmmss = my_timer.get_time_hhmmss()
print("Time elapsed: %s" % time_hhmmss )

# ... use the timer again
my_timer.restart()

# ... do something

# Get time:
time_hhmmss = my_timer.get_time_hhmmss()

# ... etc

其他回答

除了ipython中的%timeit之外,您还可以使用%%timeit进行多行代码片段:

In [1]: %%timeit
   ...: complex_func()
   ...: 2 + 2 == 5
   ...:
   ...:

1 s ± 1.93 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)

同样,它也可以以同样的方式在jupyter笔记本中使用,只需将magic%%timeit放在单元格的开头。

这是另一种方法:

>> from pytictoc import TicToc
>> t = TicToc() # create TicToc instance
>> t.tic() # Start timer
>> # do something
>> t.toc() # Print elapsed time
Elapsed time is 2.612231 seconds.

与传统方式相比:

>> from time import time
>> t1 = time()
>> # do something
>> t2 = time()
>> elapsed = t2 - t1
>> print('Elapsed time is %f seconds.' % elapsed)
Elapsed time is 2.612231 seconds.

安装:

pip install pytictoc

有关详细信息,请参阅PyPi页面。

我更喜欢这个。timeit医生太令人困惑了。

from datetime import datetime 

start_time = datetime.now() 

# INSERT YOUR CODE 

time_elapsed = datetime.now() - start_time 

print('Time elapsed (hh:mm:ss.ms) {}'.format(time_elapsed))

注意,这里没有进行任何格式化,我只是在打印输出中写入hh:mm:ss,以便可以解释time_elapsed

基于https://stackoverflow.com/a/30024601/5095636,以下为无lambda版本,如flake8根据E731对lambda使用的警告:

from contextlib import contextmanager
from timeit import default_timer

@contextmanager
def elapsed_timer():
    start_time = default_timer()

    class _Timer():
      start = start_time
      end = default_timer()
      duration = end - start

    yield _Timer

    end_time = default_timer()
    _Timer.end = end_time
    _Timer.duration = end_time - start_time

测试:

from time import sleep

with elapsed_timer() as t:
    print("start:", t.start)
    sleep(1)
    print("end:", t.end)

t.start
t.end
t.duration

我喜欢简单(python 3):

from timeit import timeit

timeit(lambda: print("hello"))

单个执行的输出为微秒:

2.430883963010274

说明:timeit默认执行匿名函数100万次,结果以秒为单位。因此,1次执行的结果相同,但平均以微秒为单位。


对于速度较慢的操作,添加较少的迭代次数,否则您可能会一直等待:

import time

timeit(lambda: time.sleep(1.5), number=1)

总迭代次数的输出始终以秒为单位:

1.5015795179999714