我想测量执行一个函数所花费的时间。我没时间工作:
import timeit
start = timeit.timeit()
print("hello")
end = timeit.timeit()
print(end - start)
我想测量执行一个函数所花费的时间。我没时间工作:
import timeit
start = timeit.timeit()
print("hello")
end = timeit.timeit()
print(end - start)
当前回答
下面是一个返回“hh:mm:ss”字符串的小型计时器类:
class Timer:
def __init__(self):
self.start = time.time()
def restart(self):
self.start = time.time()
def get_time_hhmmss(self):
end = time.time()
m, s = divmod(end - self.start, 60)
h, m = divmod(m, 60)
time_str = "%02d:%02d:%02d" % (h, m, s)
return time_str
用法:
# Start timer
my_timer = Timer()
# ... do something
# Get time string:
time_hhmmss = my_timer.get_time_hhmmss()
print("Time elapsed: %s" % time_hhmmss )
# ... use the timer again
my_timer.restart()
# ... do something
# Get time:
time_hhmmss = my_timer.get_time_hhmmss()
# ... etc
其他回答
除了ipython中的%timeit之外,您还可以使用%%timeit进行多行代码片段:
In [1]: %%timeit
...: complex_func()
...: 2 + 2 == 5
...:
...:
1 s ± 1.93 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
同样,它也可以以同样的方式在jupyter笔记本中使用,只需将magic%%timeit放在单元格的开头。
这是另一种方法:
>> from pytictoc import TicToc
>> t = TicToc() # create TicToc instance
>> t.tic() # Start timer
>> # do something
>> t.toc() # Print elapsed time
Elapsed time is 2.612231 seconds.
与传统方式相比:
>> from time import time
>> t1 = time()
>> # do something
>> t2 = time()
>> elapsed = t2 - t1
>> print('Elapsed time is %f seconds.' % elapsed)
Elapsed time is 2.612231 seconds.
安装:
pip install pytictoc
有关详细信息,请参阅PyPi页面。
我更喜欢这个。timeit医生太令人困惑了。
from datetime import datetime
start_time = datetime.now()
# INSERT YOUR CODE
time_elapsed = datetime.now() - start_time
print('Time elapsed (hh:mm:ss.ms) {}'.format(time_elapsed))
注意,这里没有进行任何格式化,我只是在打印输出中写入hh:mm:ss,以便可以解释time_elapsed
基于https://stackoverflow.com/a/30024601/5095636,以下为无lambda版本,如flake8根据E731对lambda使用的警告:
from contextlib import contextmanager
from timeit import default_timer
@contextmanager
def elapsed_timer():
start_time = default_timer()
class _Timer():
start = start_time
end = default_timer()
duration = end - start
yield _Timer
end_time = default_timer()
_Timer.end = end_time
_Timer.duration = end_time - start_time
测试:
from time import sleep
with elapsed_timer() as t:
print("start:", t.start)
sleep(1)
print("end:", t.end)
t.start
t.end
t.duration
我喜欢简单(python 3):
from timeit import timeit
timeit(lambda: print("hello"))
单个执行的输出为微秒:
2.430883963010274
说明:timeit默认执行匿名函数100万次,结果以秒为单位。因此,1次执行的结果相同,但平均以微秒为单位。
对于速度较慢的操作,添加较少的迭代次数,否则您可能会一直等待:
import time
timeit(lambda: time.sleep(1.5), number=1)
总迭代次数的输出始终以秒为单位:
1.5015795179999714