有没有一种方法可以以平台无关的方式确定一台机器有多少个C/ c++内核?如果不存在这样的东西,如何确定每个平台(Windows/*nix/Mac)?
当前回答
Note that "number of cores" might not be a particularly useful number, you might have to qualify it a bit more. How do you want to count multi-threaded CPUs such as Intel HT, IBM Power5 and Power6, and most famously, Sun's Niagara/UltraSparc T1 and T2? Or even more interesting, the MIPS 1004k with its two levels of hardware threading (supervisor AND user-level)... Not to mention what happens when you move into hypervisor-supported systems where the hardware might have tens of CPUs but your particular OS only sees a few.
最好的情况是告诉您在本地OS分区中拥有的逻辑处理单元的数量。除非您是管理程序,否则不要考虑看到真正的机器。今天这个规则唯一的例外是在x86领域,但非虚拟机的末日很快就会到来……
其他回答
C++11
#include <thread>
//may return 0 when not able to detect
const auto processor_count = std::thread::hardware_concurrency();
参考:std::线程::hardware_concurrency
在c++ 11之前的c++中,没有可移植的方法。相反,你需要使用以下一个或多个方法(由适当的#ifdef行保护):
Win32 SYSTEM_INFO sysinfo; GetSystemInfo(&sysinfo); int numCPU = sysinfo.dwNumberOfProcessors; Linux, Solaris, AIX and Mac OS X >=10.4 (i.e. Tiger onwards) int numCPU = sysconf(_SC_NPROCESSORS_ONLN); FreeBSD, MacOS X, NetBSD, OpenBSD, etc. int mib[4]; int numCPU; std::size_t len = sizeof(numCPU); /* set the mib for hw.ncpu */ mib[0] = CTL_HW; mib[1] = HW_AVAILCPU; // alternatively, try HW_NCPU; /* get the number of CPUs from the system */ sysctl(mib, 2, &numCPU, &len, NULL, 0); if (numCPU < 1) { mib[1] = HW_NCPU; sysctl(mib, 2, &numCPU, &len, NULL, 0); if (numCPU < 1) numCPU = 1; } HPUX int numCPU = mpctl(MPC_GETNUMSPUS, NULL, NULL); IRIX int numCPU = sysconf(_SC_NPROC_ONLN); Objective-C (Mac OS X >=10.5 or iOS) NSUInteger a = [[NSProcessInfo processInfo] processorCount]; NSUInteger b = [[NSProcessInfo processInfo] activeProcessorCount];
Windows (x64和Win32)和c++ 11
共享单个处理器核心的逻辑处理器组的数目。(使用GetLogicalProcessorInformationEx,参见GetLogicalProcessorInformation)
size_t NumberOfPhysicalCores() noexcept {
DWORD length = 0;
const BOOL result_first = GetLogicalProcessorInformationEx(RelationProcessorCore, nullptr, &length);
assert(GetLastError() == ERROR_INSUFFICIENT_BUFFER);
std::unique_ptr< uint8_t[] > buffer(new uint8_t[length]);
const PSYSTEM_LOGICAL_PROCESSOR_INFORMATION_EX info =
reinterpret_cast< PSYSTEM_LOGICAL_PROCESSOR_INFORMATION_EX >(buffer.get());
const BOOL result_second = GetLogicalProcessorInformationEx(RelationProcessorCore, info, &length);
assert(result_second != FALSE);
size_t nb_physical_cores = 0;
size_t offset = 0;
do {
const PSYSTEM_LOGICAL_PROCESSOR_INFORMATION_EX current_info =
reinterpret_cast< PSYSTEM_LOGICAL_PROCESSOR_INFORMATION_EX >(buffer.get() + offset);
offset += current_info->Size;
++nb_physical_cores;
} while (offset < length);
return nb_physical_cores;
}
注意,NumberOfPhysicalCores的实现在我看来远非简单(例如:"使用GetLogicalProcessorInformation或GetLogicalProcessorInformationEx")。相反,如果阅读MSDN的文档(显式地为GetLogicalProcessorInformation提供,隐式地为GetLogicalProcessorInformationEx提供),就会发现这是相当微妙的。
逻辑处理器的数量。(使用GetSystemInfo)
size_t NumberOfSystemCores() noexcept {
SYSTEM_INFO system_info;
ZeroMemory(&system_info, sizeof(system_info));
GetSystemInfo(&system_info);
return static_cast< size_t >(system_info.dwNumberOfProcessors);
}
注意,这两种方法都可以很容易地转换为C/ c++ 98/ c++ 03。
在linux上,据我所知,最好的编程方式是使用
sysconf(_SC_NPROCESSORS_CONF)
or
sysconf(_SC_NPROCESSORS_ONLN)
这些不是标准的,但是在我的Linux手册页中。
这个功能是c++ 11标准的一部分。
#include <thread>
unsigned int nthreads = std::thread::hardware_concurrency();
对于较老的编译器,可以使用Boost。线程库。
#include <boost/thread.hpp>
unsigned int nthreads = boost::thread::hardware_concurrency();
在任何一种情况下,hardware_concurrency()都会根据CPU内核和超线程单元的数量返回硬件能够并发执行的线程数。
在Linux上,使用_SC_NPROCESSORS_ONLN可能是不安全的,因为它不是POSIX标准的一部分,sysconf手册也有同样的说明。所以有可能_SC_NPROCESSORS_ONLN不存在:
These values also exist, but may not be standard.
[...]
- _SC_NPROCESSORS_CONF
The number of processors configured.
- _SC_NPROCESSORS_ONLN
The number of processors currently online (available).
一个简单的方法是读取/proc/stat或/proc/cpuinfo并计算它们:
#include<unistd.h>
#include<stdio.h>
int main(void)
{
char str[256];
int procCount = -1; // to offset for the first entry
FILE *fp;
if( (fp = fopen("/proc/stat", "r")) )
{
while(fgets(str, sizeof str, fp))
if( !memcmp(str, "cpu", 3) ) procCount++;
}
if ( procCount == -1)
{
printf("Unable to get proc count. Defaulting to 2");
procCount=2;
}
printf("Proc Count:%d\n", procCount);
return 0;
}
使用 /proc/cpuinfo:
#include<unistd.h>
#include<stdio.h>
int main(void)
{
char str[256];
int procCount = 0;
FILE *fp;
if( (fp = fopen("/proc/cpuinfo", "r")) )
{
while(fgets(str, sizeof str, fp))
if( !memcmp(str, "processor", 9) ) procCount++;
}
if ( !procCount )
{
printf("Unable to get proc count. Defaulting to 2");
procCount=2;
}
printf("Proc Count:%d\n", procCount);
return 0;
}
同样的方法在shell中使用grep:
grep -c ^processor /proc/cpuinfo
Or
grep -c ^cpu /proc/stat # subtract 1 from the result
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