像这样执行 Fragment_1 -> Fragment_2 -> Fragment_3

    Button btn = (Button) rootView.findViewById(R.id.your_button_id);
    btn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {

            Fragment_2 nextFrag= new Fragment_2();
            getActivity().getSupportFragmentManager().beginTransaction()
                    .replace(R.id.content_frame, nextFrag,getTag())
                    .addToBackStack(null)
                    .commit();

        }
    });

Fragment_3 -> Fragment_2 -> Fragment_1

Step_1:在Base Activity中创建一个可公开访问的字符串

step2:每当一个新的Fragment被激活时，在Base Activity中改变String的值

Step_3:然后添加onBackPressed()方法，并将字符串值传递给另一个方法，其中fagments可以被替换

在基础活动中

public static String currentFragment=null;

@Override
public void onBackPressed() 
{
        displayPreviousFragment(currentFragment);
}

public void displayPreviousFragment(String currentFragment)
{
    //creating fragment object
    Fragment fragment = null;

    //initializing the fragment object which is selected
    switch (currentFragment)
    {
        case "Fragment_2"    :   fragment = new Fargment_1();     break;
        case "Fragment_3"    :   fragment = new Fragment_2();     break;
    }

    //replacing the fragment
    if (fragment != null) {
        FragmentTransaction ft = getSupportFragmentManager().beginTransaction();
        ft.replace(R.id.frame_to_replace_fragment, fragment);
        ft.commit();
    }
}

在Fragment_2 在OnCreateView方法内

BaseActivity.currentFragment="Fragment_2";

在Fragment_3 在OnCreateView方法内

BaseActivity.currentFragment="Fragment_3";

非常简短而甜蜜的回答:

getActivity().onBackPressed();

我案例的整个场景说明:

我在MainActivity中有FragmentA， 我从FragmentA打开FragmentB (FragmentB是FragmentA的子或嵌套片段)

 Fragment duedateFrag = new FragmentB();
 FragmentTransaction ft  = getFragmentManager().beginTransaction();
 ft.replace(R.id.container_body, duedateFrag);
 ft.addToBackStack(null);
 ft.commit();

现在如果你想从FragmentB访问FragmentA你可以简单地输入getActivity().onBackPressed();在FragmentB。

如何使用onDestroyView()?

@Override
public void onDestroyView() {
    super.onDestroyView();
}

试试这个，如果你真的想在Fragment中启用onBackPressed()。 在浪费了一个小时的时间后，我根据我以前的经验，做出了这个完全符合需求的解决方案。

你只需要关注私有int STATUS_FRAGMENT=0的值;这就满足了片段中addToBackStack()的需求。

import android.view.MenuItem;
import android.view.View;

import androidx.annotation.NonNull;
import androidx.appcompat.app.AppCompatActivity;
import androidx.fragment.app.Fragment;

import com.example.growfast.NavigationItemsFolder.CoreFragments.Cart;
import com.example.growfast.NavigationItemsFolder.CoreFragments.HelpDesk;
import com.example.growfast.NavigationItemsFolder.CoreFragments.Home;
import com.example.growfast.NavigationItemsFolder.CoreFragments.ProfileDetails;
import com.example.growfast.R;
import com.google.android.material.bottomnavigation.BottomNavigationView;

public class BusinessManagement extends AppCompatActivity {

    public BottomNavigationView bottomNavigationView;
    private int STATUS_FRAGMENT=0;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_base_layout);
        setBottomNavigationMenu();

    }

    private void setBottomNavigationMenu() {
        bottomNavigationView = findViewById(R.id.navigation);
        bottomNavigationView.setVisibility(View.VISIBLE);

        bottomNavigationView.setOnNavigationItemSelectedListener(new BottomNavigationView.OnNavigationItemSelectedListener() {

            Fragment fragment = null;

            @Override
            public boolean onNavigationItemSelected(@NonNull MenuItem item) {

                switch (item.getItemId()) {

                    case R.id.action_home:
                        fragment = new Home();
                        break;

                    case R.id.action_profile:
                        fragment = new ProfileDetails();
                        break;
                    case R.id.action_cart:
                        fragment = new Cart();
                        break;
                    case R.id.action_favourites_menu:
                        fragment = new HelpDesk();
                        break;

                }
                return loadFromFragment(fragment);

            }
        });
        bottomNavigationView.setSelectedItemId(R.id.action_home);
    }

    private boolean loadFromFragment(Fragment fragment) {
        if (fragment != null) {
            getSupportFragmentManager().beginTransaction().replace(R.id.my_container, fragment)
                    .commit();
            STATUS_FRAGMENT=1;
            return true;
        }
        return false;
    }

    @Override
    public void onBackPressed() {
        if (STATUS_FRAGMENT==1) {
            bottomNavigationView.setSelectedItemId(R.id.action_home);
            STATUS_FRAGMENT=0;
            bottomNavigationView.setVisibility(View.VISIBLE);
        }
        else{
            super.onBackPressed();
        }
    }


}```

在我的解决方案(Kotlin);

我使用onBackAlternative函数作为BaseActivity的参数。

BaseActivity

abstract class BaseActivity {

    var onBackPressAlternative: (() -> Unit)? = null

    override fun onBackPressed() {
        if (onBackPressAlternative != null) {
            onBackPressAlternative!!()
        } else {
            super.onBackPressed()
        }
    }
}

我有一个函数在BaseFragment上设置onBackPressAlternative。

碱基片段

abstract class BaseFragment {

     override fun onStart() {
        super.onStart()
        ...
        setOnBackPressed(null) // Add this
     }

      //Method must be declared as open, for overriding in child class
     open fun setOnBackPressed(onBackAlternative: (() -> Unit)?) {
         (activity as BaseActivity<*, *>).onBackPressAlternative = onBackAlternative
     }
}

然后我的onBackPressAlternative就可以用于片段了。

子片段

override fun setOnBackPressed(onBackAlternative: (() -> Unit)?) {
    (activity as BaseActivity<*, *>).onBackPressAlternative = {
        // TODO Your own custom onback function 
    }
}

我使用的另一种方法如下:

一个Otto事件总线，用于在活动及其片段之间进行通信 Activity中的堆栈，包含在调用片段定义的Runnable中包装的自定义后退操作 当onBackPressed在控制Activity中被调用时，它弹出最近的自定义后退动作并执行它的Runnable。如果Stack上没有任何东西，则会调用默认的super.onBackPressed()

这里包含了完整的方法和示例代码，作为对另一个SO问题的回答。