这是我的答案，处理碎片按下后退按钮。 我有底部导航与五个项目(A, B, C, D,E)附加到活动时，点击一个项目，我附加的片段到活动。 让我们假设点击项目(A)，我附加片段(A)，然后如果点击项目(B)，我附加片段(B)，以此类推。

点击项目的流程。A - C > B - > - > D - > E

返回按钮按下的流程。D E - > - > - > C > B

 @Override
        public void onBackPressed() {
            int count = getSupportFragmentManager().getBackStackEntryCount();
            if (count == 0) {
                super.onBackPressed();
            } else {
                int index = ((getSupportFragmentManager().getBackStackEntryCount()) -1);
                getSupportFragmentManager().popBackStack();
                FragmentManager.BackStackEntry backEntry = getSupportFragmentManager().getBackStackEntryAt(index);
                int stackId = backEntry.getId();
                bottomNavigationView.getMenu().getItem(stackId).setChecked(true);
            }
        }

如何使用onDestroyView()?

@Override
public void onDestroyView() {
    super.onDestroyView();
}

在Fragments中处理onBackPressed()的简单方法

步骤1: 在activity中创建一个静态布尔值。

public static Fragment_one;

步骤2: 在On Create方法中的MainActivity(持有片段的活动)上声明

Fragment_one=true;

步骤3:在MainActivity中覆盖onBackPressed()

@Override
public void onBackPressed() {

    if(Fragment_one) {
     //Back key pressed on fragment one

    }else {
      //Back key pressed on fragment two
    }
}

步骤4:在fragment_one上声明onCreateView方法

MainActivity.Fragment_one=true;

步骤5在fragment_two上声明onCreateView方法

MainActivity.Fragment_one=false;

注:此方法仅适用于两个片段。

使用导航组件，你可以这样做:

Java

public class MyFragment extends Fragment {

@Override
public void onCreate(@Nullable Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    // This callback will only be called when MyFragment is at least Started.
    OnBackPressedCallback callback = new OnBackPressedCallback(true /* enabled by default */) {
        @Override
        public void handleOnBackPressed() {
            // Handle the back button event
        }
    });
    requireActivity().getOnBackPressedDispatcher().addCallback(this, callback);

    // The callback can be enabled or disabled here or in handleOnBackPressed()
}
...
}

科特林

class MyFragment : Fragment() {

override fun onCreate(savedInstanceState: Bundle?) {
    super.onCreate(savedInstanceState)

    // This callback will only be called when MyFragment is at least Started.
    val callback = requireActivity().onBackPressedDispatcher.addCallback(this) {
        // Handle the back button event
    }

    // The callback can be enabled or disabled here or in the lambda
}
...
}

我只是使用findFragmentById和转换到片段，并调用处理onBackpressed的方法。这个示例显示了检查这是否是订单流程的第一步，如果弹出一个对话框片段来确认退出订单。

@Override
    public void onBackPressed() {
        //check if first fragment in wizard is loaded, if true get abandon confirmation before going back
        OrderFragment frag =(OrderFragment)getSupportFragmentManager().findFragmentById(R.id.fragContainer);
        if (frag==null || (frag!=null && frag.getOrderStage()<1)){
            AlertDialogFragment.show(getSupportFragmentManager(), R.string.dialog_cancel_order,R.string.dialog_cancel_order_msg, R.string.dialog_cancel_order_pos,R.string.dialog_order_quiz_neg, DIALOG_ID_CANCEL);
        }else {
            super.onBackPressed();
        }
    }

我是这样做的，对我很管用

简单的界面

FragmentOnBackClickInterface.java

public interface FragmentOnBackClickInterface {
    void onClick();
}

示例实现

MyFragment.java

public class MyFragment extends Fragment implements FragmentOnBackClickInterface {

// other stuff

public void onClick() {
       // what you want to call onBackPressed?
}

然后在activity中重写onBackPressed

    @Override
public void onBackPressed() {
    int count = getSupportFragmentManager().getBackStackEntryCount();
    List<Fragment> frags = getSupportFragmentManager().getFragments();
    Fragment lastFrag = getLastNotNull(frags);
    //nothing else in back stack || nothing in back stack is instance of our interface
    if (count == 0 || !(lastFrag instanceof FragmentOnBackClickInterface)) {
        super.onBackPressed();
    } else {
        ((FragmentOnBackClickInterface) lastFrag).onClick();
    }
}

private Fragment getLastNotNull(List<Fragment> list){
    for (int i= list.size()-1;i>=0;i--){
        Fragment frag = list.get(i);
        if (frag != null){
            return frag;
        }
    }
    return null;
}