我是这样做的，对我很管用

简单的界面

FragmentOnBackClickInterface.java

public interface FragmentOnBackClickInterface {
    void onClick();
}

示例实现

MyFragment.java

public class MyFragment extends Fragment implements FragmentOnBackClickInterface {

// other stuff

public void onClick() {
       // what you want to call onBackPressed?
}

然后在activity中重写onBackPressed

    @Override
public void onBackPressed() {
    int count = getSupportFragmentManager().getBackStackEntryCount();
    List<Fragment> frags = getSupportFragmentManager().getFragments();
    Fragment lastFrag = getLastNotNull(frags);
    //nothing else in back stack || nothing in back stack is instance of our interface
    if (count == 0 || !(lastFrag instanceof FragmentOnBackClickInterface)) {
        super.onBackPressed();
    } else {
        ((FragmentOnBackClickInterface) lastFrag).onClick();
    }
}

private Fragment getLastNotNull(List<Fragment> list){
    for (int i= list.size()-1;i>=0;i--){
        Fragment frag = list.get(i);
        if (frag != null){
            return frag;
        }
    }
    return null;
}

这只是一个小代码，可以做到这一点:

 getActivity().onBackPressed();

希望它能帮助到别人:)

在我看来，最好的解决办法是:

JAVA解决方案

创建简单的界面:

public interface IOnBackPressed {
    /**
     * If you return true the back press will not be taken into account, otherwise the activity will act naturally
     * @return true if your processing has priority if not false
     */
    boolean onBackPressed();
}

在你的活动中

public class MyActivity extends Activity {
    @Override public void onBackPressed() {
    Fragment fragment = getSupportFragmentManager().findFragmentById(R.id.main_container);
       if (!(fragment instanceof IOnBackPressed) || !((IOnBackPressed) fragment).onBackPressed()) {
          super.onBackPressed();
       }
    } ...
}

最后在你的片段中:

public class MyFragment extends Fragment implements IOnBackPressed{
   @Override
   public boolean onBackPressed() {
       if (myCondition) {
            //action not popBackStack
            return true; 
        } else {
            return false;
        }
    }
}

芬兰湾的科特林解决方案

1 -创建接口

interface IOnBackPressed {
    fun onBackPressed(): Boolean
}

2 -准备你的活动

class MyActivity : AppCompatActivity() {
    override fun onBackPressed() {
        val fragment =
            this.supportFragmentManager.findFragmentById(R.id.main_container)
        (fragment as? IOnBackPressed)?.onBackPressed()?.not()?.let {
            super.onBackPressed()
        }
    }
}

3 -实现在你的目标片段

class MyFragment : Fragment(), IOnBackPressed {
    override fun onBackPressed(): Boolean {
        return if (myCondition) {
            //action not popBackStack
            true
        } else {
            false
        }
    }
}

如何使用onDestroyView()?

@Override
public void onDestroyView() {
    super.onDestroyView();
}

以下是我对这个问题的解决方案:

活动A:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) 
{
    super.onActivityResult(requestCode, resultCode, data);

    if(requestCode == REQUEST_CODE)
    {
        if(resultCode == Activity.RESULT_OK)
        {
            tvTitle.setText(data.getExtras().getString("title", ""));
        }
    }
}

活动B:

@Override
public void onBackPressed() 
{
    setResult(Activity.RESULT_OK, getIntent());

    super.onBackPressed();
}

活动b保存片段。

在片段:

private void setText(String text)
    {
        Intent intent = new Intent();
        intent.putExtra("title", text);
        getActivity().setIntent(intent);
    }

通过这种方式，活动A中的意图对象“data”将从片段中获取字符串

不要实现ft.addToBackStack()方法，这样当你按下返回按钮时，你的活动就会结束。

proAddAccount = new ProfileAddAccount();
FragmentManager fragmentManager = getSupportFragmentManager();
FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction();
fragmentTransaction.replace(R.id.fragment_container, proAddAccount);
//fragmentTransaction.addToBackStack(null);
fragmentTransaction.commit();