刚开始使用Xcode 4.5,我在控制台得到了这个错误:

警告:试图在< ViewController: 0x1ec3e000>上显示< finishViewController: 0x1e56e0a0 >,其视图不在窗口层次结构中!

视图仍在显示,应用程序中的一切都在正常工作。这是iOS 6的新功能吗?

这是我用来在视图之间更改的代码:

UIStoryboard *storyboard = self.storyboard;
finishViewController *finished = 
[storyboard instantiateViewControllerWithIdentifier:@"finishViewController"];

[self presentViewController:finished animated:NO completion:NULL];

当前回答

它主要发生在你在一些后台工作后,如Api命中或特别核心数据服务调用警报。 在应用程序主线程中调用警报。

DispatchQueue.main.async {
   // call your alert in this main thread.
   Constants.alert(title: "Network Error!", message: "Please connect to internet and try again.", controller: self)
}

其他回答

必须写在线下。

self.searchController.definesPresentationContext = true

而不是

self.definesPresentationContext = true

在ui

在主窗口中,可能总是会出现与显示警报不兼容的过渡。为了允许在应用程序生命周期的任何时候显示警报,您应该有一个单独的窗口来完成这项工作。

/// independant window for alerts
@interface AlertWindow: UIWindow

+ (void)presentAlertWithTitle:(NSString *)title message:(NSString *)message;

@end

@implementation AlertWindow

+ (AlertWindow *)sharedInstance
{
    static AlertWindow *sharedInstance;
    static dispatch_once_t onceToken;
    dispatch_once(&onceToken, ^{
        sharedInstance = [[AlertWindow alloc] initWithFrame:UIScreen.mainScreen.bounds];
    });
    return sharedInstance;
}

+ (void)presentAlertWithTitle:(NSString *)title message:(NSString *)message
{
    // Using a separate window to solve "Warning: Attempt to present <UIAlertController> on <UIViewController> whose view is not in the window hierarchy!"
    UIWindow *shared = AlertWindow.sharedInstance;
    shared.userInteractionEnabled = YES;
    UIViewController *root = shared.rootViewController;
    UIAlertController *alert = [UIAlertController alertControllerWithTitle:title message:message preferredStyle:UIAlertControllerStyleAlert];
    alert.modalInPopover = true;
    [alert addAction:[UIAlertAction actionWithTitle:@"OK" style:UIAlertActionStyleCancel handler:^(UIAlertAction *action) {
        shared.userInteractionEnabled = NO;
        [root dismissViewControllerAnimated:YES completion:nil];
    }]];
    [root presentViewController:alert animated:YES completion:nil];
}

- (instancetype)initWithFrame:(CGRect)frame
{
    self = [super initWithFrame:frame];

    self.userInteractionEnabled = NO;
    self.windowLevel = CGFLOAT_MAX;
    self.backgroundColor = UIColor.clearColor;
    self.hidden = NO;
    self.rootViewController = UIViewController.new;

    [NSNotificationCenter.defaultCenter addObserver:self
                                           selector:@selector(bringWindowToTop:)
                                               name:UIWindowDidBecomeVisibleNotification
                                             object:nil];

    return self;
}

/// Bring AlertWindow to top when another window is being shown.
- (void)bringWindowToTop:(NSNotification *)notification {
    if (![notification.object isKindOfClass:[AlertWindow class]]) {
        self.hidden = YES;
        self.hidden = NO;
    }
}

@end

在设计上总是成功的基本用法:

[AlertWindow presentAlertWithTitle:@"My title" message:@"My message"];

在我的情况下,我不能把我的类重写。所以,这是我得到的:

let viewController = self // I had viewController passed in as a function,
                          // but otherwise you can do this


// Present the view controller
let currentViewController = UIApplication.shared.keyWindow?.rootViewController
currentViewController?.dismiss(animated: true, completion: nil)

if viewController.presentedViewController == nil {
    currentViewController?.present(alert, animated: true, completion: nil)
} else {
    viewController.present(alert, animated: true, completion: nil)
}

要将任何子视图显示到主视图,请使用以下代码

UIViewController *yourCurrentViewController = [UIApplication sharedApplication].keyWindow.rootViewController;

while (yourCurrentViewController.presentedViewController) 
{
   yourCurrentViewController = yourCurrentViewController.presentedViewController;
}

[yourCurrentViewController presentViewController:composeViewController animated:YES completion:nil];

对于从主视图中解散任何子视图,请使用以下代码

UIViewController *yourCurrentViewController = [UIApplication sharedApplication].keyWindow.rootViewController;

while (yourCurrentViewController.presentedViewController) 
{
   yourCurrentViewController = yourCurrentViewController.presentedViewController;
}

[yourCurrentViewController dismissViewControllerAnimated:YES completion:nil];

你只能有1个rootViewController,它是最近出现的一个。所以不要尝试让一个视图控制器呈现另一个视图控制器当它已经呈现了一个没有被解散的视图控制器。

在做了一些自己的测试之后,我得出了一个结论。

如果你有一个rootViewController你想要显示所有东西,那么你就会遇到这个问题。

下面是我的rootController代码(打开是从根节点显示视图控制器的快捷方式)。

func open(controller:UIViewController)
{
    if (Context.ROOTWINDOW.rootViewController == nil)
    {
        Context.ROOTWINDOW.rootViewController = ROOT_VIEW_CONTROLLER
        Context.ROOTWINDOW.makeKeyAndVisible()
    }

    ROOT_VIEW_CONTROLLER.presentViewController(controller, animated: true, completion: {})
}

如果我在一行中调用open两次(不管时间流逝),这将在第一个开放上工作,但不是在第二个开放上。第二次打开尝试将导致上述错误。

然而,如果我关闭最近呈现的视图然后调用open,当我再次调用open(在另一个视图控制器上)时,它工作得很好。

func close(controller:UIViewController)
{
    ROOT_VIEW_CONTROLLER.dismissViewControllerAnimated(true, completion: nil)
}

我的结论是,只有MOST-RECENT-CALL的rootViewController在视图层次结构上(即使您没有解散它或删除视图)。我试着玩所有的加载器调用(viewDidLoad, viewDidAppear,并做延迟调度调用),我发现我能让它工作的唯一方法是从最顶层的视图控制器调用present。