UseEffect是主要的解决方案。但正如Darryl提到的，使用useEffect并将state作为第二个参数传入有一个缺陷，组件将在初始化过程中运行。如果你只想让回调函数使用更新后的状态值运行，你可以设置一个本地常量，并在setState和回调中使用它。

const [counter, setCounter] = useState(0);

const doSomething = () => {
  const updatedNumber = 123;
  setCounter(updatedNumber);

  // now you can "do something" with updatedNumber and don't have to worry about the async nature of setState!
  console.log(updatedNumber);
}

我探索了use-state with-callback npm库和其他类似的自定义钩子，但最后我意识到我可以做这样的事情:

const [user, setUser] = React.useState(
  {firstName: 'joe', lastName: 'schmo'}
)

const handleFirstNameChange=(val)=> {
  const updatedUser = {
     ...user,
     firstName: val
  }
  setUser(updatedUser)
  updateDatabase(updatedUser)
}

你的问题很有道理。让我告诉您，useEffect在默认情况下运行一次，并在每次依赖数组更改之后运行一次。

请看下面的例子:

import React,{ useEffect, useState } from "react";

const App = () => {
  const [age, setAge] = useState(0);
  const [ageFlag, setAgeFlag] = useState(false);

  const updateAge = ()=>{
    setAgeFlag(false);
    setAge(age+1);
    setAgeFlag(true);
  };

  useEffect(() => {
    if(!ageFlag){
      console.log('effect called without change - by default');
    }
    else{
      console.log('effect called with change ');
    }
  }, [ageFlag,age]);

  return (
    <form>
      <h2>hooks demo effect.....</h2>
      {age}
      <button onClick={updateAge}>Text</button>
    </form>
  );
}

export default App;

如果你想要setState回调与钩子一起执行，那么使用标志变量并在useEffect中给出If ELSE OR If块，以便当条件满足时，只执行该代码块。无论如何，当依赖项数组改变时，效果会运行，但效果中的IF代码只会在特定的条件下执行。

简单的解决方案，只需安装

我使用-state-with-callback

import React from 'react';
import { useStateWithCallbackLazy } from "use-state-with-callback";

const initialFilters = {
  smart_filter: "",
};

const MyCallBackComp = () => {
  const [filters, setFilters] = useStateWithCallbackLazy(initialFilters);

  const filterSearchHandle = (e) => {
    setFilters(
      {
        ...filters,
        smart_filter: e,
      },
      (value) => console.log("smartFilters:>", value)
    );
  };

  return (
    <Input
      type="text"
      onChange={(e) => filterSearchHandle(e.target.value)}
      name="filter"
      placeholder="Search any thing..."
    />
  );
};

认为: 反应usestate回调

编辑

在这里使用promise似乎仍然推迟了重新渲染后的执行，两次触发setState可能是获得最新状态的最佳解决方案。因为setState将被列出，我们只需要在重新渲染之前获得prevState。

最初的发布

我刚刚弄清楚了我们是否可以在这里使用一个Promise让setState变成可等待的。

这是我的实验结果，感觉比使用回调更好

主要是在useEffect中触发解析函数

function useAsyncState(initialState) {
  const [state, setState] = useState(initialState)
  const resolveCb = useRef()

  const handleSetState = (updatedState) => new Promise((resolve, reject) => {
    // force previous promise resolved
    if (typeof resolveCb.current === 'function') {
      resolveCb.current(updatedState)
    }
    resolveCb.current = resolve
    try {
      setState(updatedState)
    } catch(err) {
      resolveCb.current = undefined
      reject(err)
    }
  })

  useEffect(() => {
    if (typeof resolveCb.current === 'function') {
      resolveCb.current(state)
      resolveCb.current = undefined
    }
  }, [state])

  return [state, handleSetState]
}

组件中使用

function App() {
  const [count, setCount] = useAsyncState(0)

  const increment = useMemoizedFn(async () => {
    const newCount = await setCount(count + 1)
    console.log(newCount)
  })

  console.log('rerender')

  return (
    <div>
      <h3 onClick={increment}>Hi, {count}</h3>
    </div>
  )
}

我认为你需要的是useState和useCallback:

useState react doc; useCallback react doc;

示例代码

import React, { useCallback, useState } from 'react';

const Test = () => {
  const [name, setName] = useState("");
  const testCallback = useCallback(() => console.log(name), [name]);

  return (
    <button onClick={() => {
      setName("Michael")
      testCallback();
    }}>Name</button>
  )
};

export default Test;