我想过一些不那么优雅的方法来解决这个问题,但我知道我一定遗漏了什么。

我的onItemSelected立即启动,没有与用户进行任何交互,这是不希望的行为。我希望UI能够等到用户选择某样东西后再执行任何操作。

我甚至尝试在onResume()中设置监听器,希望能有所帮助,但它没有。

我怎样才能阻止它在用户可以触摸控件之前发射?

public class CMSHome extends Activity { 

private Spinner spinner;

@Override
    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    // Heres my spinner ///////////////////////////////////////////
    spinner = (Spinner) findViewById(R.id.spinner);
    ArrayAdapter<CharSequence> adapter = ArrayAdapter.createFromResource(
            this, R.array.pm_list, android.R.layout.simple_spinner_item);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    spinner.setAdapter(adapter);
    };

public void onResume() {
    super.onResume();
    spinner.setOnItemSelectedListener(new MyOnItemSelectedListener());
}

    public class MyOnItemSelectedListener implements OnItemSelectedListener {

    public void onItemSelected(AdapterView<?> parent,
        View view, int pos, long id) {

     Intent i = new Intent(CMSHome.this, ListProjects.class);
     i.putExtra("bEmpID", parent.getItemAtPosition(pos).toString());
        startActivity(i);

        Toast.makeText(parent.getContext(), "The pm is " +
          parent.getItemAtPosition(pos).toString(), Toast.LENGTH_LONG).show();
    }

    public void onNothingSelected(AdapterView parent) {
      // Do nothing.
    }
}
}

当前回答

这不是一个完美的解决方案,但如果你喜欢将起始字符串作为一个占位符,你可以添加占位符弹簧值("Day_of_Work_Out")

  @Override
        public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
            String name = (String) parent.getItemAtPosition(position);
            if (name.equals("Day_of_Work_Out")) {

            }else {

                workOutD = name;
                Intent intent = new Intent();
                workOutNam = workOutName.getText().toString();

                if (workOutNam == null) {

                    startActivity(intent);
                    Log.i("NewWorkOutActivity","Name is null");

                }else {
                    Log.i("NewWorkOutActivity","Name Not null");
                    Toast.makeText(NewWorkOutActivity.this, "Please Select a Day", Toast.LENGTH_LONG).show();
                }


            }
        }

其他回答

我的解决方案使用onTouchListener,但不限制它的使用。如果需要,它会在设置onItemSelectedListener时为onTouchListener创建一个包装器。

public class Spinner extends android.widget.Spinner {
    /* ...constructors... */

    private OnTouchListener onTouchListener;
    private OnItemSelectedListener onItemSelectedListener;

    @Override
    public void setOnItemSelectedListener(OnItemSelectedListener listener) {
        onItemSelectedListener = listener;
        super.setOnTouchListener(wrapTouchListener(onTouchListener, onItemSelectedListener));
    }

    @Override
    public void setOnTouchListener(OnTouchListener listener) {
        onTouchListener = listener;
        super.setOnTouchListener(wrapTouchListener(onTouchListener, onItemSelectedListener));
    }

    private OnTouchListener wrapTouchListener(final OnTouchListener onTouchListener, final OnItemSelectedListener onItemSelectedListener) {
        return onItemSelectedListener != null ? new OnTouchListener() {
            @Override
            public boolean onTouch(View view, MotionEvent motionEvent) {
                Spinner.super.setOnItemSelectedListener(onItemSelectedListener);
                return onTouchListener != null && onTouchListener.onTouch(view, motionEvent);
            }
        } : onTouchListener;
    }
}

我有很多问题与旋转发射时,我不想,所有的答案在这里是不可靠的。它们确实有效——但只是有时有效。您最终会遇到它们失败并将错误引入代码的情况。

对我来说,有效的方法是将最后选中的索引存储在一个变量中,并在侦听器中对其求值。如果它与新选定的索引相同,则不做任何操作并返回,否则继续使用侦听器。这样做:

//Declare a int member variable and initialize to 0 (at the top of your class)
private int mLastSpinnerPosition = 0;

//then evaluate it in your listener
@Override
public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {

  if(mLastSpinnerPosition == i){
        return; //do nothing
  }

  mLastSpinnerPosition = i;
  //do the rest of your code now

}

相信我,这是目前为止最可靠的解决方案。一个黑客,但它工作!

布尔标志或计数器的解决方案没有帮助我,因为在方向变化onItemSelected()调用“飞越”标志或计数器。

我子类化了android.widget.Spinner,并做了一些小的补充。相关部分如下。这个解决方案对我很有效。

private void setHandleOnItemSelected()
{
  final StackTraceElement [] elements = Thread.currentThread().getStackTrace();

  for (int index = 1; index < elements.length; index++)
  {
     handleOnItemSelected = elements[index].toString().indexOf("PerformClick") != -1; //$NON-NLS-1$

     if (handleOnItemSelected)
     {
        break;
     }
  }
}

@Override
public void setSelection(int position, boolean animate)
{
  super.setSelection(position, animate);

  setHandleOnItemSelected();
}

@Override
public void setSelection(int position)
{
  super.setSelection(position);

  setHandleOnItemSelected();
}

public boolean shouldHandleOnItemSelected()
{
  return handleOnItemSelected;
}

没有不必要的事件从布局阶段,如果你推迟添加监听器,直到布局完成:

spinner.getViewTreeObserver().addOnGlobalLayoutListener(
    new ViewTreeObserver.OnGlobalLayoutListener() {
        @Override
        public void onGlobalLayout() {
            // Ensure you call it only once works for JELLY_BEAN and later
            spinner.getViewTreeObserver().removeOnGlobalLayoutListener(this);

            // add the listener
            spinner.setOnItemSelectedListener(new OnItemSelectedListener() {

                @Override
                public void onItemSelected(AdapterView<?> parent, View view, int pos, long id) {
                    // check if pos has changed
                    // then do your work
                }

                @Override
                public void onNothingSelected(AdapterView<?> arg0) {
                }

            });

        }
    });
mYear.setOnItemSelectedListener(new OnItemSelectedListener() {
            @Override
            public void onItemSelected(AdapterView<?> parent, View arg1, int item, long arg3) {
                if (mYearSpinnerAdapter.isEnabled(item)) {

                }
            }

            @Override
            public void onNothingSelected(AdapterView<?> parent) {
            }
        });