使用java.util.concurrent.TimeUnit类:

String.format("%d min, %d sec", 
    TimeUnit.MILLISECONDS.toMinutes(millis),
    TimeUnit.MILLISECONDS.toSeconds(millis) - 
    TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis))
);

注意:TimeUnit是Java 1.5规范的一部分，但是toMinutes是在Java 1.6中添加的。

为0-9的值添加前导零，只需执行以下操作:

String.format("%02d min, %02d sec", 
    TimeUnit.MILLISECONDS.toMinutes(millis),
    TimeUnit.MILLISECONDS.toSeconds(millis) - 
    TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis))
);

如果TimeUnit或toMinutes不受支持(例如在API版本9之前的Android上)，使用以下公式:

int seconds = (int) (milliseconds / 1000) % 60 ;
int minutes = (int) ((milliseconds / (1000*60)) % 60);
int hours   = (int) ((milliseconds / (1000*60*60)) % 24);
//etc...

我不会为此引入额外的依赖项(毕竟，除法并不那么难)，但如果您无论如何都在使用Commons Lang，还有DurationFormatUtils。

用法示例(从这里改编):

import org.apache.commons.lang3.time.DurationFormatUtils

public String getAge(long value) {
    long currentTime = System.currentTimeMillis();
    long age = currentTime - value;
    String ageString = DurationFormatUtils.formatDuration(age, "d") + "d";
    if ("0d".equals(ageString)) {
        ageString = DurationFormatUtils.formatDuration(age, "H") + "h";
        if ("0h".equals(ageString)) {
            ageString = DurationFormatUtils.formatDuration(age, "m") + "m";
            if ("0m".equals(ageString)) {
                ageString = DurationFormatUtils.formatDuration(age, "s") + "s";
                if ("0s".equals(ageString)) {
                    ageString = age + "ms";
                }
            }
        }
    }
    return ageString;
}   

例子:

long lastTime = System.currentTimeMillis() - 2000;
System.out.println("Elapsed time: " + getAge(lastTime)); 

//Output: 2s

注意:从两个LocalDateTime对象中获取millis可以使用:

long age = ChronoUnit.MILLIS.between(initTime, LocalDateTime.now())

乔达时间

使用Joda-Time:

DateTime startTime = new DateTime();

// do something

DateTime endTime = new DateTime();
Duration duration = new Duration(startTime, endTime);
Period period = duration.toPeriod().normalizedStandard(PeriodType.time());
System.out.println(PeriodFormat.getDefault().print(period));

使用java . util . concurrent。TimeUnit，使用这个简单的方法:

private static long timeDiff(Date date, Date date2, TimeUnit unit) {
    long milliDiff=date2.getTime()-date.getTime();
    long unitDiff = unit.convert(milliDiff, TimeUnit.MILLISECONDS);
    return unitDiff; 
}

例如:

SimpleDateFormat sdf = new SimpleDateFormat("yy/MM/dd HH:mm:ss");  
Date firstDate = sdf.parse("06/24/2017 04:30:00");
Date secondDate = sdf.parse("07/24/2017 05:00:15");
Date thirdDate = sdf.parse("06/24/2017 06:00:15");

System.out.println("days difference: "+timeDiff(firstDate,secondDate,TimeUnit.DAYS));
System.out.println("hours difference: "+timeDiff(firstDate,thirdDate,TimeUnit.HOURS));
System.out.println("minutes difference: "+timeDiff(firstDate,thirdDate,TimeUnit.MINUTES));
System.out.println("seconds difference: "+timeDiff(firstDate,thirdDate,TimeUnit.SECONDS));

这在Java 9中更容易:

    Duration elapsedTime = Duration.ofMillis(millisDiff );
    String humanReadableElapsedTime = String.format(
            "%d hours, %d mins, %d seconds",
            elapsedTime.toHours(),
            elapsedTime.toMinutesPart(),
            elapsedTime.toSecondsPart());

这将生成像0小时39分9秒这样的字符串。

如果你想在格式化前舍入整秒:

    elapsedTime = elapsedTime.plusMillis(500).truncatedTo(ChronoUnit.SECONDS);

如果小时数为0，则省略:

    long hours = elapsedTime.toHours();
    String humanReadableElapsedTime;
    if (hours == 0) {
        humanReadableElapsedTime = String.format(
                "%d mins, %d seconds",
                elapsedTime.toMinutesPart(),
                elapsedTime.toSecondsPart());

    } else {
        humanReadableElapsedTime = String.format(
                "%d hours, %d mins, %d seconds",
                hours,
                elapsedTime.toMinutesPart(),
                elapsedTime.toSecondsPart());
    }

现在我们有39分9秒。

要打印前导0的分钟和秒，使它们始终是两个数字，只需在相关的格式说明符中插入02，如下所示:

    String humanReadableElapsedTime = String.format(
            "%d hours, %02d mins, %02d seconds",
            elapsedTime.toHours(),
            elapsedTime.toMinutesPart(),
            elapsedTime.toSecondsPart());

现在我们有0小时39分09秒。

如果你知道时间差将小于一个小时，那么你可以使用以下代码:

    Calendar c1 = Calendar.getInstance();
    Calendar c2 = Calendar.getInstance();

    c2.add(Calendar.MINUTE, 51);

    long diff = c2.getTimeInMillis() - c1.getTimeInMillis();

    c2.set(Calendar.MINUTE, 0);
    c2.set(Calendar.HOUR, 0);
    c2.set(Calendar.SECOND, 0);

    DateFormat df = new SimpleDateFormat("mm:ss");
    long diff1 = c2.getTimeInMillis() + diff;
    System.out.println(df.format(new Date(diff1)));

结果是:51:00