这个答案与上面的一些答案相似。然而，我觉得这将是有益的，因为与其他答案不同，这将删除任何额外的逗号或空格，并处理缩写。

/**
 * Converts milliseconds to "x days, x hours, x mins, x secs"
 * 
 * @param millis
 *            The milliseconds
 * @param longFormat
 *            {@code true} to use "seconds" and "minutes" instead of "secs" and "mins"
 * @return A string representing how long in days/hours/minutes/seconds millis is.
 */
public static String millisToString(long millis, boolean longFormat) {
    if (millis < 1000) {
        return String.format("0 %s", longFormat ? "seconds" : "secs");
    }
    String[] units = {
            "day", "hour", longFormat ? "minute" : "min", longFormat ? "second" : "sec"
    };
    long[] times = new long[4];
    times[0] = TimeUnit.DAYS.convert(millis, TimeUnit.MILLISECONDS);
    millis -= TimeUnit.MILLISECONDS.convert(times[0], TimeUnit.DAYS);
    times[1] = TimeUnit.HOURS.convert(millis, TimeUnit.MILLISECONDS);
    millis -= TimeUnit.MILLISECONDS.convert(times[1], TimeUnit.HOURS);
    times[2] = TimeUnit.MINUTES.convert(millis, TimeUnit.MILLISECONDS);
    millis -= TimeUnit.MILLISECONDS.convert(times[2], TimeUnit.MINUTES);
    times[3] = TimeUnit.SECONDS.convert(millis, TimeUnit.MILLISECONDS);
    StringBuilder s = new StringBuilder();
    for (int i = 0; i < 4; i++) {
        if (times[i] > 0) {
            s.append(String.format("%d %s%s, ", times[i], units[i], times[i] == 1 ? "" : "s"));
        }
    }
    return s.toString().substring(0, s.length() - 2);
}

/**
 * Converts milliseconds to "x days, x hours, x mins, x secs"
 * 
 * @param millis
 *            The milliseconds
 * @return A string representing how long in days/hours/mins/secs millis is.
 */
public static String millisToString(long millis) {
    return millisToString(millis, false);
}

使用java。Java 8中的时间包:

Instant start = Instant.now();
Thread.sleep(63553);
Instant end = Instant.now();
System.out.println(Duration.between(start, end));

输出为ISO 8601 Duration格式:pt1m3.53s(1分3.553秒)。

我修改了@MyKuLLSKI的回答，增加了多元化支持。我去掉了几秒，因为我不需要它们，如果你需要的话，可以重新添加。

public static String intervalToHumanReadableTime(int intervalMins) {

    if(intervalMins <= 0) {
        return "0";
    } else {

        long intervalMs = intervalMins * 60 * 1000;

        long days = TimeUnit.MILLISECONDS.toDays(intervalMs);
        intervalMs -= TimeUnit.DAYS.toMillis(days);
        long hours = TimeUnit.MILLISECONDS.toHours(intervalMs);
        intervalMs -= TimeUnit.HOURS.toMillis(hours);
        long minutes = TimeUnit.MILLISECONDS.toMinutes(intervalMs);

        StringBuilder sb = new StringBuilder(12);

        if (days >= 1) {
            sb.append(days).append(" day").append(pluralize(days)).append(", ");
        }

        if (hours >= 1) {
            sb.append(hours).append(" hour").append(pluralize(hours)).append(", ");
        }

        if (minutes >= 1) {
            sb.append(minutes).append(" minute").append(pluralize(minutes));
        } else {
            sb.delete(sb.length()-2, sb.length()-1);
        }

        return(sb.toString());          

    }

}

public static String pluralize(long val) {
    return (Math.round(val) > 1 ? "s" : "");
}

回顾@brent-nash的贡献，我们可以使用模函数代替减法并使用String。结果字符串的格式方法:

  /**
   * Convert a millisecond duration to a string format
   * 
   * @param millis A duration to convert to a string form
   * @return A string of the form "X Days Y Hours Z Minutes A Seconds B Milliseconds".
   */
   public static String getDurationBreakdown(long millis) {
       if (millis < 0) {
          throw new IllegalArgumentException("Duration must be greater than zero!");
       }

       long days = TimeUnit.MILLISECONDS.toDays(millis);
       long hours = TimeUnit.MILLISECONDS.toHours(millis) % 24;
       long minutes = TimeUnit.MILLISECONDS.toMinutes(millis) % 60;
       long seconds = TimeUnit.MILLISECONDS.toSeconds(millis) % 60;
       long milliseconds = millis % 1000;

       return String.format("%d Days %d Hours %d Minutes %d Seconds %d Milliseconds",
                            days, hours, minutes, seconds, milliseconds);
   }

long time = 1536259;

return (new SimpleDateFormat("mm:ss:SSS")).format(new Date(time));

打印:

25:36:259

嗯……一秒是多少毫秒?一分钟后呢?除法没那么难。

int seconds = (int) ((milliseconds / 1000) % 60);
int minutes = (int) ((milliseconds / 1000) / 60);

这样持续几小时、几天、几周、几个月、一年、几十年，等等。