下面是一个基于Brent Nash的答案，希望有帮助!

public static String getDurationBreakdown(long millis)
{
    String[] units = {" Days ", " Hours ", " Minutes ", " Seconds "};
    Long[] values = new Long[units.length];
    if(millis < 0)
    {
        throw new IllegalArgumentException("Duration must be greater than zero!");
    }

    values[0] = TimeUnit.MILLISECONDS.toDays(millis);
    millis -= TimeUnit.DAYS.toMillis(values[0]);
    values[1] = TimeUnit.MILLISECONDS.toHours(millis);
    millis -= TimeUnit.HOURS.toMillis(values[1]);
    values[2] = TimeUnit.MILLISECONDS.toMinutes(millis);
    millis -= TimeUnit.MINUTES.toMillis(values[2]);
    values[3] = TimeUnit.MILLISECONDS.toSeconds(millis);

    StringBuilder sb = new StringBuilder(64);
    boolean startPrinting = false;
    for(int i = 0; i < units.length; i++){
        if( !startPrinting && values[i] != 0)
            startPrinting = true;
        if(startPrinting){
            sb.append(values[i]);
            sb.append(units[i]);
        }
    }

    return(sb.toString());
}

我修改了@MyKuLLSKI的回答，增加了多元化支持。我去掉了几秒，因为我不需要它们，如果你需要的话，可以重新添加。

public static String intervalToHumanReadableTime(int intervalMins) {

    if(intervalMins <= 0) {
        return "0";
    } else {

        long intervalMs = intervalMins * 60 * 1000;

        long days = TimeUnit.MILLISECONDS.toDays(intervalMs);
        intervalMs -= TimeUnit.DAYS.toMillis(days);
        long hours = TimeUnit.MILLISECONDS.toHours(intervalMs);
        intervalMs -= TimeUnit.HOURS.toMillis(hours);
        long minutes = TimeUnit.MILLISECONDS.toMinutes(intervalMs);

        StringBuilder sb = new StringBuilder(12);

        if (days >= 1) {
            sb.append(days).append(" day").append(pluralize(days)).append(", ");
        }

        if (hours >= 1) {
            sb.append(hours).append(" hour").append(pluralize(hours)).append(", ");
        }

        if (minutes >= 1) {
            sb.append(minutes).append(" minute").append(pluralize(minutes));
        } else {
            sb.delete(sb.length()-2, sb.length()-1);
        }

        return(sb.toString());          

    }

}

public static String pluralize(long val) {
    return (Math.round(val) > 1 ? "s" : "");
}

乔达时间

使用Joda-Time:

DateTime startTime = new DateTime();

// do something

DateTime endTime = new DateTime();
Duration duration = new Duration(startTime, endTime);
Period period = duration.toPeriod().normalizedStandard(PeriodType.time());
System.out.println(PeriodFormat.getDefault().print(period));

这个答案与上面的一些答案相似。然而，我觉得这将是有益的，因为与其他答案不同，这将删除任何额外的逗号或空格，并处理缩写。

/**
 * Converts milliseconds to "x days, x hours, x mins, x secs"
 * 
 * @param millis
 *            The milliseconds
 * @param longFormat
 *            {@code true} to use "seconds" and "minutes" instead of "secs" and "mins"
 * @return A string representing how long in days/hours/minutes/seconds millis is.
 */
public static String millisToString(long millis, boolean longFormat) {
    if (millis < 1000) {
        return String.format("0 %s", longFormat ? "seconds" : "secs");
    }
    String[] units = {
            "day", "hour", longFormat ? "minute" : "min", longFormat ? "second" : "sec"
    };
    long[] times = new long[4];
    times[0] = TimeUnit.DAYS.convert(millis, TimeUnit.MILLISECONDS);
    millis -= TimeUnit.MILLISECONDS.convert(times[0], TimeUnit.DAYS);
    times[1] = TimeUnit.HOURS.convert(millis, TimeUnit.MILLISECONDS);
    millis -= TimeUnit.MILLISECONDS.convert(times[1], TimeUnit.HOURS);
    times[2] = TimeUnit.MINUTES.convert(millis, TimeUnit.MILLISECONDS);
    millis -= TimeUnit.MILLISECONDS.convert(times[2], TimeUnit.MINUTES);
    times[3] = TimeUnit.SECONDS.convert(millis, TimeUnit.MILLISECONDS);
    StringBuilder s = new StringBuilder();
    for (int i = 0; i < 4; i++) {
        if (times[i] > 0) {
            s.append(String.format("%d %s%s, ", times[i], units[i], times[i] == 1 ? "" : "s"));
        }
    }
    return s.toString().substring(0, s.length() - 2);
}

/**
 * Converts milliseconds to "x days, x hours, x mins, x secs"
 * 
 * @param millis
 *            The milliseconds
 * @return A string representing how long in days/hours/mins/secs millis is.
 */
public static String millisToString(long millis) {
    return millisToString(millis, false);
}

我在另一个答案中提到了这一点，但你可以这样做:

public static Map<TimeUnit,Long> computeDiff(Date date1, Date date2) {
    long diffInMillies = date2.getTime() - date1.getTime();
    List<TimeUnit> units = new ArrayList<TimeUnit>(EnumSet.allOf(TimeUnit.class));
    Collections.reverse(units);
    Map<TimeUnit,Long> result = new LinkedHashMap<TimeUnit,Long>();
    long milliesRest = diffInMillies;
    for ( TimeUnit unit : units ) {
        long diff = unit.convert(milliesRest,TimeUnit.MILLISECONDS);
        long diffInMilliesForUnit = unit.toMillis(diff);
        milliesRest = milliesRest - diffInMilliesForUnit;
        result.put(unit,diff);
    }
    return result;
}

输出类似Map:{DAYS=1, HOURS=3, MINUTES=46, SECONDS=40, MILLISECONDS=0, MICROSECONDS=0, NANOSECONDS=0}，单位是有序的。

由您决定如何根据目标语言环境对这些数据进行国际化。

嗯……一秒是多少毫秒?一分钟后呢?除法没那么难。

int seconds = (int) ((milliseconds / 1000) % 60);
int minutes = (int) ((milliseconds / 1000) / 60);

这样持续几小时、几天、几周、几个月、一年、几十年，等等。