如何在Android中使用意图打电话?

我正在使用以下代码在Android中拨打电话，但它给了我安全例外，请帮助。

 posted_by = "111-333-222-4";

 String uri = "tel:" + posted_by.trim() ;
 Intent intent = new Intent(Intent.ACTION_CALL);
 intent.setData(Uri.parse(uri));
 startActivity(intent);

权限

 <uses-permission android:name="android.permission.CALL_PHONE" />

异常

11-25 14:47:01.661: ERROR/AndroidRuntime(302): Uncaught handler: thread main exiting due to uncaught exception
11-25 14:47:01.681: ERROR/AndroidRuntime(302): java.lang.SecurityException: Permission Denial: starting Intent { act=android.intent.action.CALL dat=tel:111-333-222-4 cmp=com.android.phone/.OutgoingCallBroadcaster } from ProcessRecord{43d32508 302:com.Finditnear/10026} (pid=302, uid=10026) requires android.permission.CALL_PHONE
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1218)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1206)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.ActivityManagerProxy.startActivity(ActivityManagerNative.java:1214)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Instrumentation.execStartActivity(Instrumentation.java:1373)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivityForResult(Activity.java:2749)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivity(Activity.java:2855)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.Finditnear.PostDetail$2$1$1$1.onClick(PostDetail.java:604)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.android.internal.app.AlertController$AlertParams$3.onItemClick(AlertController.java:884)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AdapterView.performItemClick(AdapterView.java:284)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.ListView.performItemClick(ListView.java:3285)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AbsListView$PerformClick.run(AbsListView.java:1640)

当前回答

你也可以用这个:

String uri = "tel:" + posted_by.replaceAll("[^0-9|\\+]", "");

2013-07-04 11:04:09

其他回答

更优雅的选择:

String phone = "+34666777888";
Intent intent = new Intent(Intent.ACTION_DIAL, Uri.fromParts("tel", phone, null));
startActivity(intent);

2014-06-23 13:37:11

在Android中，对于某些功能，您需要将权限添加到Manifest文件。

转到项目AndroidManifest.xml 单击Permissions选项卡点击添加选择使用权限请看下面的快照

6.保存清单文件，然后运行项目。您的项目现在应该按预期运行。

2014-06-03 15:00:26

字符串电话= "9553290143";

意图意图=新的意图(意图。ACTION_DIAL, Uri.fromParts("tel"， phone, null));

startActivity(意图);

2022-08-01 12:29:09

 if(ContextCompat.checkSelfPermission(
        mContext,android.Manifest.permission.CALL_PHONE) != 
              PackageManager.PERMISSION_GRANTED) {
                    ActivityCompat.requestPermissions((Activity) mContext, new 
                  String[]{android.Manifest.permission.CALL_PHONE}, 0);
                } else {
                    startActivity(new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + "Your Number")));
                }

2018-04-03 05:42:09

只是一个简单的联机程序，不需要任何额外的权限:

private void dialContactPhone(final String phoneNumber) {
    startActivity(new Intent(Intent.ACTION_DIAL, Uri.fromParts("tel", phoneNumber, null)));
}

2015-08-14 12:29:30

如何在Android中使用意图打电话?

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