如何在Android中使用意图打电话?

我正在使用以下代码在Android中拨打电话，但它给了我安全例外，请帮助。

 posted_by = "111-333-222-4";

 String uri = "tel:" + posted_by.trim() ;
 Intent intent = new Intent(Intent.ACTION_CALL);
 intent.setData(Uri.parse(uri));
 startActivity(intent);

权限

 <uses-permission android:name="android.permission.CALL_PHONE" />

异常

11-25 14:47:01.661: ERROR/AndroidRuntime(302): Uncaught handler: thread main exiting due to uncaught exception
11-25 14:47:01.681: ERROR/AndroidRuntime(302): java.lang.SecurityException: Permission Denial: starting Intent { act=android.intent.action.CALL dat=tel:111-333-222-4 cmp=com.android.phone/.OutgoingCallBroadcaster } from ProcessRecord{43d32508 302:com.Finditnear/10026} (pid=302, uid=10026) requires android.permission.CALL_PHONE
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1218)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1206)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.ActivityManagerProxy.startActivity(ActivityManagerNative.java:1214)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Instrumentation.execStartActivity(Instrumentation.java:1373)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivityForResult(Activity.java:2749)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivity(Activity.java:2855)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.Finditnear.PostDetail$2$1$1$1.onClick(PostDetail.java:604)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.android.internal.app.AlertController$AlertParams$3.onItemClick(AlertController.java:884)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AdapterView.performItemClick(AdapterView.java:284)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.ListView.performItemClick(ListView.java:3285)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AbsListView$PerformClick.run(AbsListView.java:1640)

当前回答

AndroidManifest.xml中的权限

<uses-permission android:name="android.permission.CALL_PHONE" />

完整的代码:

private void onCallBtnClick(){
    if (Build.VERSION.SDK_INT < 23) {
        phoneCall();
    }else {

        if (ActivityCompat.checkSelfPermission(mActivity,
                Manifest.permission.CALL_PHONE) == PackageManager.PERMISSION_GRANTED) {

            phoneCall();
        }else {
            final String[] PERMISSIONS_STORAGE = {Manifest.permission.CALL_PHONE};
            //Asking request Permissions
            ActivityCompat.requestPermissions(mActivity, PERMISSIONS_STORAGE, 9);
        }
    }
}

@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
    boolean permissionGranted = false;
    switch(requestCode){
        case 9:
            permissionGranted = grantResults[0]== PackageManager.PERMISSION_GRANTED;
            break;
    }
    if(permissionGranted){
        phoneCall();
    }else {
        Toast.makeText(mActivity, "You don't assign permission.", Toast.LENGTH_SHORT).show();
    }
}

private void phoneCall(){
    if (ActivityCompat.checkSelfPermission(mActivity,
            Manifest.permission.CALL_PHONE) == PackageManager.PERMISSION_GRANTED) {
        Intent callIntent = new Intent(Intent.ACTION_CALL);
        callIntent.setData(Uri.parse("tel:12345678900"));
        mActivity.startActivity(callIntent);
    }else{
        Toast.makeText(mActivity, "You don't assign permission.", Toast.LENGTH_SHORT).show();
    }
}

2017-10-26 02:56:09

其他回答

AndroidManifest.xml中的权限

<uses-permission android:name="android.permission.CALL_PHONE" />

完整的代码:

private void onCallBtnClick(){
    if (Build.VERSION.SDK_INT < 23) {
        phoneCall();
    }else {

        if (ActivityCompat.checkSelfPermission(mActivity,
                Manifest.permission.CALL_PHONE) == PackageManager.PERMISSION_GRANTED) {

            phoneCall();
        }else {
            final String[] PERMISSIONS_STORAGE = {Manifest.permission.CALL_PHONE};
            //Asking request Permissions
            ActivityCompat.requestPermissions(mActivity, PERMISSIONS_STORAGE, 9);
        }
    }
}

@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
    boolean permissionGranted = false;
    switch(requestCode){
        case 9:
            permissionGranted = grantResults[0]== PackageManager.PERMISSION_GRANTED;
            break;
    }
    if(permissionGranted){
        phoneCall();
    }else {
        Toast.makeText(mActivity, "You don't assign permission.", Toast.LENGTH_SHORT).show();
    }
}

private void phoneCall(){
    if (ActivityCompat.checkSelfPermission(mActivity,
            Manifest.permission.CALL_PHONE) == PackageManager.PERMISSION_GRANTED) {
        Intent callIntent = new Intent(Intent.ACTION_CALL);
        callIntent.setData(Uri.parse("tel:12345678900"));
        mActivity.startActivity(callIntent);
    }else{
        Toast.makeText(mActivity, "You don't assign permission.", Toast.LENGTH_SHORT).show();
    }
}

2017-10-26 02:56:09

为了避免这种情况，可以使用GUI来输入权限。Eclipse会考虑在哪里插入权限标记，通常情况下不这样做是正确的

2011-02-26 21:52:31

只是一个简单的联机程序，不需要任何额外的权限:

private void dialContactPhone(final String phoneNumber) {
    startActivity(new Intent(Intent.ACTION_DIAL, Uri.fromParts("tel", phoneNumber, null)));
}

2015-08-14 12:29:30

更优雅的选择:

String phone = "+34666777888";
Intent intent = new Intent(Intent.ACTION_DIAL, Uri.fromParts("tel", phone, null));
startActivity(intent);

2014-06-23 13:37:11

你也可以用这个:

String uri = "tel:" + posted_by.replaceAll("[^0-9|\\+]", "");

2013-07-04 11:04:09

如何在Android中使用意图打电话?

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