我正在使用以下代码在Android中拨打电话,但它给了我安全例外,请帮助。

 posted_by = "111-333-222-4";

 String uri = "tel:" + posted_by.trim() ;
 Intent intent = new Intent(Intent.ACTION_CALL);
 intent.setData(Uri.parse(uri));
 startActivity(intent);

权限

 <uses-permission android:name="android.permission.CALL_PHONE" />

异常

11-25 14:47:01.661: ERROR/AndroidRuntime(302): Uncaught handler: thread main exiting due to uncaught exception
11-25 14:47:01.681: ERROR/AndroidRuntime(302): java.lang.SecurityException: Permission Denial: starting Intent { act=android.intent.action.CALL dat=tel:111-333-222-4 cmp=com.android.phone/.OutgoingCallBroadcaster } from ProcessRecord{43d32508 302:com.Finditnear/10026} (pid=302, uid=10026) requires android.permission.CALL_PHONE
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1218)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1206)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.ActivityManagerProxy.startActivity(ActivityManagerNative.java:1214)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Instrumentation.execStartActivity(Instrumentation.java:1373)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivityForResult(Activity.java:2749)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivity(Activity.java:2855)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.Finditnear.PostDetail$2$1$1$1.onClick(PostDetail.java:604)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.android.internal.app.AlertController$AlertParams$3.onItemClick(AlertController.java:884)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AdapterView.performItemClick(AdapterView.java:284)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.ListView.performItemClick(ListView.java:3285)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AbsListView$PerformClick.run(AbsListView.java:1640)

当前回答

 if(ContextCompat.checkSelfPermission(
        mContext,android.Manifest.permission.CALL_PHONE) != 
              PackageManager.PERMISSION_GRANTED) {
                    ActivityCompat.requestPermissions((Activity) mContext, new 
                  String[]{android.Manifest.permission.CALL_PHONE}, 0);
                } else {
                    startActivity(new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + "Your Number")));
                }

其他回答

对于使用intent进行调用活动,您应该请求适当的权限。

为此,在AndroidManifest.xml文件中包含使用权限。

<uses-permission android:name="android.permission.CALL_PHONE" />

然后在您的活动中包含以下代码

if (ActivityCompat.checkSelfPermission(mActivity,
        Manifest.permission.CALL_PHONE) == PackageManager.PERMISSION_GRANTED) {
    //Creating intents for making a call
    Intent callIntent = new Intent(Intent.ACTION_CALL);
    callIntent.setData(Uri.parse("tel:123456789"));
    mActivity.startActivity(callIntent);

}else{
    Toast.makeText(mActivity, "You don't assign permission.", Toast.LENGTH_SHORT).show();
}

从拨号器调用(不需要权限):

   fun callFromDailer(mContext: Context, number: String) {
        try {
            val callIntent = Intent(Intent.ACTION_DIAL)
            callIntent.data = Uri.parse("tel:$number")
            mContext.startActivity(callIntent)
        } catch (e: Exception) {
            e.printStackTrace()
            Toast.makeText(mContext, "No SIM Found", Toast.LENGTH_LONG).show()
        }
    }

从应用程序直接呼叫(需要权限):

  fun callDirect(mContext: Context, number: String) {
        try {
            val callIntent = Intent(Intent.ACTION_CALL)
            callIntent.data = Uri.parse("tel:$number")
            mContext.startActivity(callIntent)
        } catch (e: SecurityException) {
            Toast.makeText(mContext, "Need call permission", Toast.LENGTH_LONG).show()
        } catch (e: Exception) {
            e.printStackTrace()
            Toast.makeText(mContext, "No SIM Found", Toast.LENGTH_LONG).show()
        }
    }

许可:

<uses-permission android:name="android.permission.CALL_PHONE"></uses-permission>
// Java
String mobileNumber = "99XXXXXXXX";
Intent intent = new Intent();
intent.setAction(Intent.ACTION_DIAL); // Action for what intent called for
intent.setData(Uri.parse("tel: " + mobileNumber)); // Data with intent respective action on intent
startActivity(intent);

// Kotlin
val mobileNumber = "99XXXXXXXX"
val intent = Intent()
intent.action = Intent.ACTION_DIAL // Action for what intent called for
intent.data = Uri.parse("tel: $mobileNumber") // Data with intent respective action on intent
startActivity(intent)

在Kotlin中使用此代码

fun makeCall(context: Context, mob: String) {
        try {
            val intent = Intent(Intent.ACTION_DIAL)

            intent.data = Uri.parse("tel:$mob")
            context.startActivity(intent)
        } catch (e: java.lang.Exception) {
            Toast.makeText(context,
                "Unable to call at this time", Toast.LENGTH_SHORT).show()
        }
    }

重要提示:

如果你使用Intent。ACTION_CALL必须增加CALL_PHONE权限。

如果你不想让你的应用在没有SIM卡或没有GSM的平板电脑上显示谷歌播放,这是可以的。

在活动中:

            Intent callIntent = new Intent(Intent.ACTION_CALL);
            callIntent.setData(Uri.parse("tel:" + Constants.CALL_CENTER_NUMBER));
            startActivity(callIntent);

清单:

<uses-permission android:name="android.permission.CALL_PHONE" />

因此,如果它不是应用程序的关键功能,尽量避免添加CALL_PHONE权限。

其他解决方案:

是在屏幕上显示手机应用程序,用户只需要点击呼叫按钮:

            Intent dialIntent = new Intent(Intent.ACTION_DIAL);
            dialIntent.setData(Uri.parse("tel:" + Constants.CALL_CENTER_NUMBER));
            startActivity(dialIntent);

这样做不需要许可。