我正在使用以下代码在Android中拨打电话,但它给了我安全例外,请帮助。

 posted_by = "111-333-222-4";

 String uri = "tel:" + posted_by.trim() ;
 Intent intent = new Intent(Intent.ACTION_CALL);
 intent.setData(Uri.parse(uri));
 startActivity(intent);

权限

 <uses-permission android:name="android.permission.CALL_PHONE" />

异常

11-25 14:47:01.661: ERROR/AndroidRuntime(302): Uncaught handler: thread main exiting due to uncaught exception
11-25 14:47:01.681: ERROR/AndroidRuntime(302): java.lang.SecurityException: Permission Denial: starting Intent { act=android.intent.action.CALL dat=tel:111-333-222-4 cmp=com.android.phone/.OutgoingCallBroadcaster } from ProcessRecord{43d32508 302:com.Finditnear/10026} (pid=302, uid=10026) requires android.permission.CALL_PHONE
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1218)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.os.Parcel.readException(Parcel.java:1206)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.ActivityManagerProxy.startActivity(ActivityManagerNative.java:1214)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Instrumentation.execStartActivity(Instrumentation.java:1373)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivityForResult(Activity.java:2749)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.app.Activity.startActivity(Activity.java:2855)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.Finditnear.PostDetail$2$1$1$1.onClick(PostDetail.java:604)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at com.android.internal.app.AlertController$AlertParams$3.onItemClick(AlertController.java:884)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AdapterView.performItemClick(AdapterView.java:284)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.ListView.performItemClick(ListView.java:3285)
11-25 14:47:01.681: ERROR/AndroidRuntime(302):     at android.widget.AbsListView$PerformClick.run(AbsListView.java:1640)

当前回答

这个演示对你有帮助…

在呼叫按钮上单击:

Intent intent = new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + "Your Phone_number"));
startActivity(intent);

舱单许可:

 <uses-permission android:name="android.permission.CALL_PHONE" />

2021年编辑

你应该把它写在你的清单文件,但同时你应该在运行时问。像这样的代码:

if (ContextCompat.checkSelfPermission(this,android.Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
            ActivityCompat.requestPermissions(this, arrayOf(android.Manifest.permission.CALL_PHONE),
                REQUEST_CODE)

        } else {

// else block means user has already accepted.And make your phone call here.

}

如果你想,你可以覆盖onRequestPermissionsResult给用户更好的体验,如果你写相同的代码与else块在这里,你的用户将不需要再次点击你的按钮,在你给予权限后,它将直接调用。

其他回答

为了避免这种情况,可以使用GUI来输入权限。Eclipse会考虑在哪里插入权限标记,通常情况下不这样做是正确的

你也可以用这个:

String uri = "tel:" + posted_by.replaceAll("[^0-9|\\+]", "");

使用完整代码

          Intent callIntent = new Intent(Intent.ACTION_DIAL);
          callIntent.setData(Uri.parse("tel:"+Uri.encode(PhoneNum.trim())));
          callIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
          startActivity(callIntent);     

在Kotlin中使用此代码

fun makeCall(context: Context, mob: String) {
        try {
            val intent = Intent(Intent.ACTION_DIAL)

            intent.data = Uri.parse("tel:$mob")
            context.startActivity(intent)
        } catch (e: java.lang.Exception) {
            Toast.makeText(context,
                "Unable to call at this time", Toast.LENGTH_SHORT).show()
        }
    }

只是一个简单的联机程序,不需要任何额外的权限:

private void dialContactPhone(final String phoneNumber) {
    startActivity(new Intent(Intent.ACTION_DIAL, Uri.fromParts("tel", phoneNumber, null)));
}